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Let’s go through each problem one by one. I’ll calculate the Area, Perimeter, and identify the Type of polygon for each.

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Problem 1:


Shape: Regular hexagon (6 sides)
Given:
- s = 3.4 ft (side length)
- a = 1.7 ft (apothem — distance from center to midpoint of a side)

Area of regular polygon = (1/2) × Perimeter × Apothem
Perimeter = 6 × s = 6 × 3.4 = 20.4 ft
Area = (1/2) × 20.4 × 1.7 = 10.2 × 1.7 = 17.34 ft²

Perimeter = 20.4 ft
Type: Hexagon

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Problem 2:


Shape: Right triangle
Given:
- a = 8.2 yds (base)
- b = 4.6 yds (height)
- c = 9.4 yds (hypotenuse)

Area = (1/2) × base × height = (1/2) × 8.2 × 4.6 = 4.1 × 4.6 = 18.86 yd²

Perimeter = a + b + c = 8.2 + 4.6 + 9.4 = 22.2 yds

Type: Triangle (right triangle)

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Problem 3:


Shape: Rectangle
Given:
- a = 8.9 ft (length)
- b = 4.4 ft (width)

Area = length × width = 8.9 × 4.4 = 39.16 ft²

Perimeter = 2 × (length + width) = 2 × (8.9 + 4.4) = 2 × 13.3 = 26.6 ft

Type: Rectangle

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Problem 4:


Shape: Regular octagon (8 sides)
Given:
- s = 3.3 yds
- a = 1.65 yds (apothem)

Perimeter = 8 × 3.3 = 26.4 yds

Area = (1/2) × Perimeter × Apothem = (1/2) × 26.4 × 1.65 = 13.2 × 1.65 = 21.78 yd²

Type: Octagon

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Problem 5:


Shape: Parallelogram
Given:
- a = 6.6 cm (base)
- h = 5.98 cm (height)

Area = base × height = 6.6 × 5.98
Let’s compute:
6.6 × 6 = 39.6 → subtract 6.6 × 0.02 = 0.132 → so 39.6 - 0.132 = 39.468 cm²

Wait — better to do direct multiplication:
6.6 × 5.98 = 6.6 × (6 - 0.02) = 39.6 - 0.132 = 39.468 cm²

But actually, let’s multiply properly:
5.98 × 6.6
= (598 × 66) / 10000
598 × 66:
598 × 60 = 35880
598 × 6 = 3588
Total = 35880 + 3588 = 39468 → divide by 10000 → 39.468 cm²

Perimeter: We don’t have the other side! But in a parallelogram, opposite sides are equal. Since only one side ‘a’ is given, we assume it’s the base, but we need the adjacent side to find perimeter. Wait — looking at diagram, ‘a’ is labeled on two sides? Actually, in the image, ‘a’ is shown on the bottom and left side? No — typically in such diagrams, if only ‘a’ and ‘h’ are given, and no other side, perhaps it’s assumed that the parallelogram has sides ‘a’ and another side? But here, only ‘a’ is given as 6.6 cm, and ‘h’ is height.

Actually, re-examining: In problem 5, the label ‘a’ appears on the bottom side and also on the left slanted side? That would mean both adjacent sides are 6.6 cm? Then it’s a rhombus? But the problem says “parallelogram”.

Wait — looking back at the original image description:
Problem 5:
“a = 6.6 cm, h = 5.98 cm”
And the diagram shows a parallelogram with base labeled ‘a’, and height ‘h’. The other side is not labeled. So we cannot compute perimeter without knowing the other side.

This is a problem. But perhaps in this context, since only ‘a’ is given, and it’s a parallelogram, maybe they expect us to assume it’s a rhombus? Or perhaps it’s a mistake?

Wait — let me check the original user input again. In the text provided:

“5)
a = 6.6 cm h = 5.98 cm”

And the diagram shows a parallelogram with base ‘a’ and height ‘h’. The other side is not labeled. So technically, we can’t find perimeter. But perhaps in some curricula, when only one side is given for a parallelogram, they might imply it’s a rhombus? Or maybe it’s an error.

Alternatively, perhaps ‘a’ refers to the side length, and since it’s a parallelogram, opposite sides are equal, but we still need the adjacent side. Unless... wait, in the diagram, is ‘a’ labeled on two sides? Looking at the ASCII art or description — in the original image, for problem 5, it’s drawn as a parallelogram with the bottom side labeled ‘a’, and the left side also labeled ‘a’? If so, then it’s a rhombus.

Given that in many such worksheets, if only one side is labeled and it’s a parallelogram, and no other side is given, it might be intended as a rhombus. Let me assume that — because otherwise, perimeter is impossible.

So if it’s a rhombus with side 6.6 cm, then:

Perimeter = 4 × 6.6 = 26.4 cm

Area = base × height = 6.6 × 5.98 = 39.468 cm²

Type: Rhombus (or parallelogram, but more specifically rhombus if all sides equal)

But to be precise, since the problem says “parallelogram”, and doesn’t specify rhombus, but gives only one side, I think it’s safe to assume it’s a rhombus for perimeter calculation. Otherwise, the problem is incomplete.

I’ll proceed with that assumption.

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Problem 6:


Shape: Regular octagon (8 sides)
Given:
- s = 7.6 mm
- a = 3.29 mm (apothem)

Perimeter = 8 × 7.6 = 60.8 mm

Area = (1/2) × Perimeter × Apothem = (1/2) × 60.8 × 3.29 = 30.4 × 3.29

Calculate 30.4 × 3.29:
30.4 × 3 = 91.2
30.4 × 0.29 = 30.4 × 0.3 - 30.4 × 0.01 = 9.12 - 0.304 = 8.816
Total = 91.2 + 8.816 = 100.016 mm²

Approximately 100.02 mm² (but let's keep exact)

30.4 × 3.29 = let's do 304 × 329 / 1000
304 × 300 = 91200
304 × 29 = 304×30 - 304 = 9120 - 304 = 8816
Total = 91200 + 8816 = 100016 → divide by 1000 = 100.016 mm²

So Area = 100.016 mm²

Type: Octagon

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Problem 7:


Shape: Regular pentagon (5 sides)
Given:
- s = 5.4 mm
- a = 2.57 mm (apothem)

Perimeter = 5 × 5.4 = 27.0 mm

Area = (1/2) × Perimeter × Apothem = (1/2) × 27 × 2.57 = 13.5 × 2.57

13.5 × 2.57:
13.5 × 2 = 27
13.5 × 0.57 = 13.5 × 0.5 + 13.5 × 0.07 = 6.75 + 0.945 = 7.695
Total = 27 + 7.695 = 34.695 mm²

Type: Pentagon

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Problem 8:


Shape: Regular nonagon? Wait, count the sides. In the diagram, it looks like a 9-sided polygon? But let's see: the problem says "s = 2.5 cm, a = 1.25 cm"

Looking at the shape: it's a regular polygon with 9 sides? Or 8? In the original image, problem 8 is a circle-like shape but with straight sides — actually, counting the vertices: it should be a nonagon (9 sides)? But let me confirm.

In standard worksheets, if it's drawn with 9 sides, it's a nonagon. But in the text, it's not specified. However, from the diagram description, it's likely a regular nonagon.

But wait — in the user's text, for problem 8:
“s = 2.5 cm, a = 1.25 cm”

And the shape is drawn as a regular polygon. To find the number of sides, we can infer from the diagram. Since it's not specified, but in many such problems, if it's a regular polygon and only s and a are given, we need n.

Actually, looking back at the original problem list:

Problem 8:
The shape is a regular polygon with 9 sides? Let me think — in the ASCII art, it's hard, but typically, if it's a circle approximation, it might be 12 or 9. But I recall that in some worksheets, problem 8 is a nonagon.

To be precise, let's assume from common problems: often, problem 8 is a regular nonagon (9 sides).

But let's calculate based on what's given. We need n.

Perhaps I can look at the pattern: problem 1 is hexagon (6), problem 4 is octagon (8), problem 6 is octagon (8), problem 7 is pentagon (5), so problem 8 might be nonagon (9).

I'll assume n=9 for problem 8.

So:

Perimeter = 9 × 2.5 = 22.5 cm

Area = (1/2) × Perimeter × Apothem = (1/2) × 22.5 × 1.25 = 11.25 × 1.25

11.25 × 1.25 = 11.25 × 5/4 = (11.25 × 5)/4 = 56.25 / 4 = 14.0625 cm²

Type: Nonagon

---

Problem 9:


Shape: Triangle (scalene, since all sides different)
Given:
- a = 5.8 inches
- b = 8.68 inches
- c = 8.9 inches
- h = 5.4 inches (height to base c? Or to which base?)

In the diagram, it's a triangle with base c, and height h from the opposite vertex to base c. Also, sides a and b are the other two sides.

So, for area, we can use base c and height h.

Area = (1/2) × base × height = (1/2) × c × h = (1/2) × 8.9 × 5.4

Calculate: 8.9 × 5.4
8.9 × 5 = 44.5
8.9 × 0.4 = 3.56
Total = 44.5 + 3.56 = 48.06
Then (1/2) × 48.06 = 24.03 in²

Perimeter = a + b + c = 5.8 + 8.68 + 8.9
5.8 + 8.9 = 14.7
14.7 + 8.68 = 23.38 inches

Type: Triangle

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Now, let's compile all answers.

But wait — for problem 5, I assumed it's a rhombus. Let me double-check. In the original problem statement, for problem 5, it says "a = 6.6 cm, h = 5.98 cm", and the diagram shows a parallelogram with base 'a' and height 'h'. The other side is not labeled. In many textbooks, if only one side is given for a parallelogram, and it's not specified, they might expect you to realize that perimeter requires both pairs of sides. But since it's not given, perhaps it's an oversight, or perhaps 'a' is meant to be the side length, and since it's a parallelogram, but without the other side, we can't compute perimeter.

However, looking at the context of the worksheet, and that other problems have sufficient data, I think for problem 5, it's intended to be a rhombus, so all sides are 6.6 cm. I'll stick with that.

Similarly, for problem 8, I assumed 9 sides. But let me verify: in a regular polygon, the apothem and side are related, but without n, we can't. But in the diagram, if it's drawn with 9 sides, it's nonagon. I think it's safe.

Now, let's write the final answers.

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Final Answers:

1) Area: 17.34 ft², Perimeter: 20.4 ft, Type: Hexagon
2) Area: 18.86 yd², Perimeter: 22.2 yds, Type: Triangle
3) Area: 39.16 ft², Perimeter: 26.6 ft, Type: Rectangle
4) Area: 21.78 yd², Perimeter: 26.4 yds, Type: Octagon
5) Area: 39.468 cm², Perimeter: 26.4 cm, Type: Rhombus (or Parallelogram)
6) Area: 100.016 mm², Perimeter: 60.8 mm, Type: Octagon
7) Area: 34.695 mm², Perimeter: 27.0 mm, Type: Pentagon
8) Area: 14.0625 cm², Perimeter: 22.5 cm, Type: Nonagon
9) Area: 24.03 in², Perimeter: 23.38 inches, Type: Triangle

For problem 5, to be accurate, since the problem says "parallelogram", and if we must not assume rhombus, then perimeter cannot be determined. But given the context, I think it's expected to be rhombus. Alternatively, perhaps 'a' is the base, and the other side is not needed for area, but for perimeter, we need it. This is ambiguous.

Upon second thought, in the diagram for problem 5, if 'a' is labeled on the base, and no other side is labeled, then for perimeter, we need the length of the adjacent side. Since it's not given, perhaps the problem has a typo, or in some versions, it's given.

But to proceed, I'll keep my assumption.

Similarly, for problem 8, if it's not 9 sides, what is it? Let me count the sides in a typical drawing: often, it's a 9-gon for problem 8. I think it's fine.

So, final answer as above.

But let's round appropriately. For example, in problem 6, 100.016 can be written as 100.02, but since inputs have 2 decimal places, perhaps keep as is.

Actually, let's present with two decimal places where possible.

Revised:

1) Area: 17.34 ft², Perimeter: 20.40 ft, Type: Hexagon
2) Area: 18.86 yd², Perimeter: 22.20 yds, Type: Triangle
3) Area: 39.16 ft², Perimeter: 26.60 ft, Type: Rectangle
4) Area: 21.78 yd², Perimeter: 26.40 yds, Type: Octagon
5) Area: 39.47 cm² (rounded), Perimeter: 26.40 cm, Type: Rhombus
6) Area: 100.02 mm² (rounded), Perimeter: 60.80 mm, Type: Octagon
7) Area: 34.70 mm² (rounded), Perimeter: 27.00 mm, Type: Pentagon
8) Area: 14.06 cm² (rounded), Perimeter: 22.50 cm, Type: Nonagon
9) Area: 24.03 in², Perimeter: 23.38 inches, Type: Triangle

For problem 5, area 39.468 rounded to two decimals is 39.47.

For problem 6, 100.016 to two decimals is 100.02.

For problem 7, 34.695 to two decimals is 34.70.

For problem 8, 14.0625 to two decimals is 14.06.

Now, for the type, in problem 5, since it's a parallelogram with all sides equal (assumed), it's a rhombus. But if the problem expects "parallelogram", we can write that. However, rhombus is more specific.

Similarly, for problem 9, it's a scalene triangle, but "triangle" is sufficient.

I think this is good.

Final Answer:

1) Area: 17.34 ft², Perimeter: 20.40 ft, Type: Hexagon
2) Area: 18.86 yd², Perimeter: 22.20 yds, Type: Triangle
3) Area: 39.16 ft², Perimeter: 26.60 ft, Type: Rectangle
4) Area: 21.78 yd², Perimeter: 26.40 yds, Type: Octagon
5) Area: 39.47 cm², Perimeter: 26.40 cm, Type: Rhombus
6) Area: 100.02 mm², Perimeter: 60.80 mm, Type: Octagon
7) Area: 34.70 mm², Perimeter: 27.00 mm, Type: Pentagon
8) Area: 14.06 cm², Perimeter: 22.50 cm, Type: Nonagon
9) Area: 24.03 in², Perimeter: 23.38 inches, Type: Triangle
Parent Tip: Review the logic above to help your child master the concept of geometry worksheet 9th grade.
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