Grade 6 Math Worksheet for Wednesday with 20 diverse problems covering arithmetic, geometry, and measurement.

Let's solve each problem step by step:

---

1. What is the surface area?

The image shows a 3D shape made of 1-cm cubes. To find the surface area:
- Count the visible faces of the cubes.
- Each face is a square with an area of \(1 \, \text{cm}^2\).

From the image:
- There are 5 visible faces on the bottom layer.
- There are 4 visible faces on the top layer.

Total visible faces = \(5 + 4 = 9\).

Thus, the surface area is:
\[
\boxed{9 \, \text{cm}^2}
\]

---

2. \(6716 - 8 =\)

Perform the subtraction:
\[
6716 - 8 = 6708
\]
\[
\boxed{6708}
\]

---

3. \(100 + 70 =\)

Perform the addition:
\[
100 + 70 = 170
\]
\[
\boxed{170}
\]

---

4. \(\frac{2}{3} + \frac{2}{6} =\)

First, simplify \(\frac{2}{6}\):
\[
\frac{2}{6} = \frac{1}{3}
\]
Now add the fractions:
\[
\frac{2}{3} + \frac{1}{3} = \frac{3}{3} = 1
\]
\[
\boxed{1}
\]

---

5. Fold the net. Which letter is missing from the blank face of the cube?

The net of the cube is shown, and the folded cube is also shown. The letters on the cube are \(C\) and \(D\). By examining the net:
- \(C\) and \(D\) are adjacent in the net.
- The blank face must be opposite \(C\) or \(D\).

By folding the net, the blank face will be opposite \(E\). Therefore, the missing letter is:
\[
\boxed{E}
\]

---

6. \(1.08 = \_\_ + 0.\)

This is a simple equation:
\[
1.08 = x + 0
\]
\[
x = 1.08
\]
\[
\boxed{1.08}
\]

---

7. Is \(1.77\) closer to \(1.70\) or \(1.80\)?

Calculate the differences:
- Difference between \(1.77\) and \(1.70\):
\[
1.77 - 1.70 = 0.07
\]
- Difference between \(1.77\) and \(1.80\):
\[
1.80 - 1.77 = 0.03
\]

Since \(0.03 < 0.07\), \(1.77\) is closer to \(1.80\).
\[
\boxed{1.80}
\]

---

8. Area = \(\_\_ \, \text{m}^2\)

The shape is a triangle with base \(8 \, \text{m}\) and height \(3 \, \text{m}\). The formula for the area of a triangle is:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
Substitute the values:
\[
\text{Area} = \frac{1}{2} \times 8 \times 3 = 4 \times 3 = 12 \, \text{m}^2
\]
\[
\boxed{12}
\]

---

9. Simplify \(\frac{2}{10}\)

Simplify the fraction:
\[
\frac{2}{10} = \frac{1}{5}
\]
\[
\boxed{\frac{1}{5}}
\]

---

10. This angle is most likely:

The angle in the image appears to be acute and less than \(45^\circ\). The options are:
- \(45^\circ\)
- \(10^\circ\)
- \(80^\circ\)

The angle is closest to \(10^\circ\).
\[
\boxed{10^\circ}
\]

---

11. \(8 \times 9 = \_\_ = 4 \times \_\_ \)

First, calculate \(8 \times 9\):
\[
8 \times 9 = 72
\]
Now, solve for the second part:
\[
72 = 4 \times x \implies x = \frac{72}{4} = 18
\]
\[
\boxed{72, 18}
\]

---

12. \(\frac{6}{10} = \_\_ /_{100} = \_\_ \%\)

First, convert \(\frac{6}{10}\) to a fraction with denominator 100:
\[
\frac{6}{10} = \frac{60}{100}
\]
Next, convert to a percentage:
\[
\frac{60}{100} = 60\%
\]
\[
\boxed{60, 60}
\]

---

13. Which numeral has the lowest value?

The options are:
- (a) \(-4\)
- (b) \(2\)
- (c) \(0\)
- (d) \(-1\)

Among these, \(-4\) is the smallest.
\[
\boxed{-4}
\]

---

14. \(7 - \frac{1}{3} =\)

Convert \(7\) to a fraction with denominator 3:
\[
7 = \frac{21}{3}
\]
Now subtract:
\[
\frac{21}{3} - \frac{1}{3} = \frac{20}{3}
\]
\[
\boxed{\frac{20}{3}}
\]

---

15. Write the fifteenth of September in numerals.

The fifteenth of September is written as:
\[
\boxed{15/09}
\]

---

16. What type of triangle is this?

The triangle has one right angle (indicated by the square symbol). Therefore, it is a right triangle.
\[
\boxed{\text{Right triangle}}
\]

---

17. What is one-quarter of half a million?

Half a million is:
\[
500,000
\]
One-quarter of \(500,000\) is:
\[
\frac{1}{4} \times 500,000 = 125,000
\]
\[
\boxed{125,000}
\]

---

18. Write the mean (average) of these netball scores: \(3, 15, 20, 2\).

The mean is calculated as:
\[
\text{Mean} = \frac{\text{Sum of scores}}{\text{Number of scores}}
\]
Sum of scores:
\[
3 + 15 + 20 + 2 = 40
\]
Number of scores = 4.
\[
\text{Mean} = \frac{40}{4} = 10
\]
\[
\boxed{10}
\]

---

19. \(6, 12, 18, 24,\)

This is an arithmetic sequence with a common difference of 6. The next term is:
\[
24 + 6 = 30
\]
\[
\boxed{30}
\]

---

20. Shade the heavier weight.

The weights are:
- Left side: \(850 \, \text{kg} + 275 \, \text{kg} = 1125 \, \text{kg}\)
- Right side: \(1280 \, \text{kg}\)

The right side (\(1280 \, \text{kg}\)) is heavier. Shade the corresponding circle.

---

Final Answers:

\[
\boxed{
\begin{array}{l}
1. 9 \, \text{cm}^2 \\
2. 6708 \\
3. 170 \\
4. 1 \\
5. E \\
6. 1.08 \\
7. 1.80 \\
8. 12 \\
9. \frac{1}{5} \\
10. 10^\circ \\
11. 72, 18 \\
12. 60, 60 \\
13. -4 \\
14. \frac{20}{3} \\
15. 15/09 \\
16. \text{Right triangle} \\
17. 125,000 \\
18. 10 \\
19. 30 \\
20. \text{Shade the right circle (1280 kg)}
\end{array}
}
\]