- For problem 1:
- a) The graph starts at (0,0), rises linearly to (4,10), then falls linearly to (6,0).
- b) Total distance = area under the graph = area of triangle = (1/2) * 6 * 10 = 30 meters.
- For problem 2:
- a) Speed after 5 seconds = acceleration * time = 1.5 m/s² * 5 s = 7.5 m/s.
- b) The graph starts at (0,0), rises linearly to (5,7.5), then continues as a horizontal line from (5,7.5) onwards.
- For problem 3:
- a) The graph starts at (0,0), rises linearly to (12,24), continues horizontally to (42,24), then falls linearly to (60,0).
- b) Deceleration rate = change in speed / time = (24 m/s - 0 m/s) / (60 s - 42 s) = 24 / 18 = 1.33 m/s².
- For problem 4:
- a) The graph starts at (0,0), rises linearly to (8,40), continues horizontally to (18,40), then falls linearly to (22,28), and continues horizontally from (22,28) onwards.
- b) Distance during deceleration = area under the graph from t=18 to t=22 = average speed * time = ((40 + 28)/2) * 4 = 34 * 4 = 136 meters.
Parent Tip: Review the logic above to help your child master the concept of graphing speed worksheet.
