Let x be the number of 4.2 kg packets and y be the number of 5.8 kg packets.
We are given two conditions:
1. The total number of packets is 50: x + y = 50
2. The total weight of rice is 234 kg: 4.2x + 5.8y = 234
Solve the first equation for x: x = 50 - y
Substitute into the second equation:
4.2(50 - y) + 5.8y = 234
210 - 4.2y + 5.8y = 234
210 + 1.6y = 234
1.6y = 24
y = 15
Now substitute back to find x:
x = 50 - 15 = 35
So, Mr. Singh packs 35 packets of 4.2 kg and 15 packets of 5.8 kg.
Calculate the total money collected:
Money from 4.2 kg packets: 35 × $10.50 = $367.50
Money from 5.8 kg packets: 15 × $12.30 = $184.50
Total money collected: $367.50 + $184.50 = $552.00
Parent Tip: Review the logic above to help your child master the concept of hard math word problems.