Explanation:
Let’s solve each problem one by one, carefully.
Problem 19: $-4 - \frac{2}{9}$
We are subtracting a positive fraction from a negative integer.
Think of $-4$ as $-\frac{36}{9}$ (since $4 = \frac{36}{9}$).
So:
$$
-4 - \frac{2}{9} = -\frac{36}{9} - \frac{2}{9} = -\frac{38}{9}
$$
That’s an improper fraction. As a mixed number:
$38 \div 9 = 4$ remainder $2$, so $-\frac{38}{9} = -4\frac{2}{9}$.
Either form is fine, but since the question uses fractions, we’ll keep it as $-\frac{38}{9}$.
Problem 20: $-\frac{3}{10} - \frac{3}{5}$
First, get common denominators.
$\frac{3}{5} = \frac{6}{10}$, so:
$$
-\frac{3}{10} - \frac{6}{10} = -\frac{9}{10}
$$
Problem 21: $6 - (-7)$
Subtracting a negative is like adding the positive:
$$
6 - (-7) = 6 + 7 = 13
$$
Problem 22: $-10 - (-4)$
Again, subtracting a negative becomes addition:
$$
-10 - (-4) = -10 + 4 = -6
$$
Let me double-check all:
19) $-4 - \frac{2}{9} = -\frac{36}{9} - \frac{2}{9} = -\frac{38}{9}$
✔
20) $-\frac{3}{10} - \frac{6}{10} = -\frac{9}{10}$
✔
21) $6 + 7 = 13$
✔
22) $-10 + 4 = -6$
✔
All correct.
Final Answer:
19) $-\frac{38}{9}$
20) $-\frac{9}{10}$
21) $13$
22) $-6$
Parent Tip: Review the logic above to help your child master the concept of integers adding and subtracting fractions.
