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Integer Word Problems ( Test ) worksheet - Free Printable

Integer Word Problems ( Test ) worksheet

Educational worksheet: Integer Word Problems ( Test ) worksheet. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Integer Word Problems ( Test ) worksheet
Let's solve each problem step by step:

---

Problem 6:


Monday’s high temperature was 6 degrees C. The low temperature was -3 degrees C. What was the difference between the high and low temperature?

#### Solution:
To find the difference between the high and low temperatures, subtract the low temperature from the high temperature:
\[
\text{Difference} = \text{High Temperature} - \text{Low Temperature}
\]
\[
\text{Difference} = 6 - (-3)
\]
Subtracting a negative number is equivalent to adding the positive counterpart:
\[
6 - (-3) = 6 + 3 = 9
\]

#### Answer:
\[
\boxed{9}
\]

---

Problem 7:


The temperature changed from 5 degrees C at 6 p.m. to -2 degree C at midnight. How much did the temperature decrease?

#### Solution:
To find the decrease in temperature, subtract the final temperature from the initial temperature:
\[
\text{Decrease} = \text{Initial Temperature} - \text{Final Temperature}
\]
\[
\text{Decrease} = 5 - (-2)
\]
Subtracting a negative number is equivalent to adding the positive counterpart:
\[
5 - (-2) = 5 + 2 = 7
\]

#### Answer:
\[
\boxed{7}
\]

---

Problem 8:


A diver’s elevation is -5 feet relative to sea level. A school of fish is swimming at an elevation of -12 feet. What is the difference between the diver and the school of fish?

#### Solution:
To find the difference in elevation, subtract the school of fish's elevation from the diver's elevation:
\[
\text{Difference} = \text{Diver's Elevation} - \text{Fish's Elevation}
\]
\[
\text{Difference} = -5 - (-12)
\]
Subtracting a negative number is equivalent to adding the positive counterpart:
\[
-5 - (-12) = -5 + 12 = 7
\]

#### Answer:
\[
\boxed{7}
\]

---

Problem 9:


The temperature in Montreal was -15 degrees C. In New York the temperature was 11 degrees C. How many degrees warmer was the temperature in New York?

#### Solution:
To find how much warmer New York's temperature is compared to Montreal's, subtract Montreal's temperature from New York's temperature:
\[
\text{Difference} = \text{New York's Temperature} - \text{Montreal's Temperature}
\]
\[
\text{Difference} = 11 - (-15)
\]
Subtracting a negative number is equivalent to adding the positive counterpart:
\[
11 - (-15) = 11 + 15 = 26
\]

#### Answer:
\[
\boxed{26}
\]

---

Problem 10:


You play a game where you score -6 points on the first turn and on each of the next three turns. What is your score after those four turns?

#### Solution:
You score -6 points on each of the four turns. To find the total score, multiply the score per turn by the number of turns:
\[
\text{Total Score} = -6 \times 4
\]
\[
\text{Total Score} = -24
\]

#### Answer:
\[
\boxed{-24}
\]

---

Problem 11:


The outdoor temperature declines 3 degrees each hour for 5 hours. What is the change in temperature at the end of those 5 hours?

#### Solution:
The temperature declines by 3 degrees each hour. Over 5 hours, the total change in temperature is:
\[
\text{Total Change} = \text{Decline per Hour} \times \text{Number of Hours}
\]
\[
\text{Total Change} = -3 \times 5
\]
\[
\text{Total Change} = -15
\]

#### Answer:
\[
\boxed{-15}
\]

---

Problem 12:


A football team loses 4 yards on each of five plays. What is the team’s total loss?

#### Solution:
The team loses 4 yards on each play. Over 5 plays, the total loss is:
\[
\text{Total Loss} = \text{Loss per Play} \times \text{Number of Plays}
\]
\[
\text{Total Loss} = -4 \times 5
\]
\[
\text{Total Loss} = -20
\]

#### Answer:
\[
\boxed{-20}
\]

---

Final Answers:


1. \( \boxed{9} \)
2. \( \boxed{7} \)
3. \( \boxed{7} \)
4. \( \boxed{26} \)
5. \( \boxed{-24} \)
6. \( \boxed{-15} \)
7. \( \boxed{-20} \)
Parent Tip: Review the logic above to help your child master the concept of integers word problems worksheet.
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