Integer Word Problems HW online exercise for - Free Printable

Let's solve each problem step by step:

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Problem 1:

The elevation of Mt. Everest is 29,028 feet. The elevation of the Dead Sea is –485 feet. What is the difference in the elevation between Mt. Everest and the Dead Sea?

Solution:
To find the difference in elevation, subtract the elevation of the Dead Sea from the elevation of Mt. Everest:
\[
29,028 - (-485) = 29,028 + 485 = 29,513
\]
So, the difference in elevation is:
\[
\boxed{29513}
\]

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Problem 2:

A scuba diver swam 94 feet beneath the surface of the lake. He then climbs up 49 feet. What is his depth now?

Solution:
The diver starts at a depth of –94 feet (below the surface). Climbing up means adding 49 feet to his current depth:
\[
-94 + 49 = -45
\]
So, the diver's new depth is:
\[
\boxed{-45}
\]

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Problem 3:

The temperature was –3°C last night. It is now –5°C. What was the change in temperature?

Solution:
To find the change in temperature, subtract the current temperature from the previous temperature:
\[
-5 - (-3) = -5 + 3 = -2
\]
So, the change in temperature is:
\[
\boxed{-2}
\]

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Problem 4:

While watching a football game, Lin Chow decided to list yardage gained as positive integers and yardage lost as negative integers. After these plays, Lin recorded 14, –7, and –9. What was the net gain or loss?

Solution:
To find the net gain or loss, sum the recorded yardages:
\[
14 + (-7) + (-9) = 14 - 7 - 9 = -2
\]
So, the net gain or loss is:
\[
\boxed{-2}
\]

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Problem 5:

Two golfers completed one round of golf. The first golfer had a score of +6 and the second golfer had a score of –2. How many more shots did the first golfer take?

Solution:
The first golfer's score is +6, meaning he took 6 more shots than par. The second golfer's score is –2, meaning he took 2 fewer shots than par. To find how many more shots the first golfer took compared to the second golfer, subtract the second golfer's score from the first golfer's score:
\[
6 - (-2) = 6 + 2 = 8
\]
So, the first golfer took:
\[
\boxed{8}
\]
more shots.

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Problem 6:

What is the balance as a result of having a credit of $85 and a debit of $29?

Solution:
To find the balance, subtract the debit from the credit:
\[
85 - 29 = 56
\]
So, the balance is:
\[
\boxed{56}
\]

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Problem 7:

The freezing point of water is 32°F. Tim added potassium and found out that the freezing point went down by 12°F. What was the freezing point of the water with the added potassium?

Solution:
The original freezing point is 32°F. Adding potassium lowers the freezing point by 12°F:
\[
32 - 12 = 20
\]
So, the new freezing point is:
\[
\boxed{20}
\]

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Problem 8:

The city’s budget is $8,000,000. The city actually spends $10,000,000. What is the city’s deficit?

Solution:
The deficit is the amount spent minus the budget:
\[
10,000,000 - 8,000,000 = 2,000,000
\]
So, the city's deficit is:
\[
\boxed{2000000}
\]

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Problem 9:

When I woke up, my temperature was 101°F. Two hours later, it was 4°F lower. What was my temperature then?

Solution:
If your temperature was 101°F and it decreased by 4°F, the new temperature is:
\[
101 - 4 = 97
\]
So, your temperature two hours later was:
\[
\boxed{97}
\]

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Problem 10:

An elevator is on the 18th floor. It goes down 11 floors and then up 5 floors. What floor is the elevator on now?

Solution:
Starting on the 18th floor, going down 11 floors means:
\[
18 - 11 = 7
\]
Then, going up 5 floors means:
\[
7 + 5 = 12
\]
So, the elevator is now on the:
\[
\boxed{12}
\]
floor.

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Final Answers:

1. \(\boxed{29513}\)
2. \(\boxed{-45}\)
3. \(\boxed{-2}\)
4. \(\boxed{-2}\)
5. \(\boxed{8}\)
6. \(\boxed{56}\)
7. \(\boxed{20}\)
8. \(\boxed{2000000}\)
9. \(\boxed{97}\)
10. \(\boxed{12}\)