Class 7 Maths Integers Worksheet - Free Printable
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Step-by-step solution for: Class 7 Maths Integers Worksheet
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Show Answer Key & Explanations
Step-by-step solution for: Class 7 Maths Integers Worksheet
Let's solve each question step by step.
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(a) $ 30 - \_\_\_\_\_\_ = 3 $
Let the missing number be $ x $.
So, $ 30 - x = 3 $
$ x = 30 - 3 = 27 $
✔ Answer: $ 27 $
---
(b) $ -89 + \_\_\_\_\_\_ = 89 $
Let the missing number be $ x $.
$ -89 + x = 89 $
$ x = 89 + 89 = 178 $
✔ Answer: $ 178 $
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(c) $ \_\_\_\_\_\_ + 1 = -205 $
Let the missing number be $ x $.
$ x + 1 = -205 $
$ x = -205 - 1 = -206 $
✔ Answer: $ -206 $
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(d) $ \_\_\_\_\_\_ \times (-12) = 120 $
Let the missing number be $ x $.
$ x \times (-12) = 120 $
$ x = \frac{120}{-12} = -10 $
✔ Answer: $ -10 $
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(e) $ 24 + 12 \div 4 - 5 \times 3 = ? $
Apply BODMAS (Brackets, Orders, Division/Multiplication, Addition/Subtraction):
- $ 12 \div 4 = 3 $
- $ 5 \times 3 = 15 $
Now:
$ 24 + 3 - 15 = 27 - 15 = 12 $
✔ Answer: $ 12 $
---
We have:
$ p \times (-9) = 135 $
$ p = \frac{135}{-9} = -15 $
✔ Answer: $ -15 $
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Additive inverse means a number that when added to the original gives 0.
For 0:
$ 0 + x = 0 $ → $ x = 0 $
So, the additive inverse of 0 is 0 itself.
✔ Answer: $ 0 $
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| Property | Match |
|--------|-------|
| (a) Distributive law over addition | (v) $ a \times (b + c) = a \times b + a \times c $ |
| (b) Associative law for multiplication | (iii) $ (a \times b) \times c = a \times (b \times c) $ |
| (c) Additive Identity | (i) $ a + 0 = a = 0 + a $ |
| (d) Commutative law over addition | (ii) $ a + b = b + a $ |
| (e) Multiplicative Identity | (iv) $ a \times 1 = 1 \times a = a $ |
✔ Matching:
- (a) → (v)
- (b) → (iii)
- (c) → (i)
- (d) → (ii)
- (e) → (iv)
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(a) $ 25 - 40 + 10 \_\_\_\_\_\_ 25 - 40 - 10 $
Left: $ 25 - 40 + 10 = -15 + 10 = -5 $
Right: $ 25 - 40 - 10 = -15 - 10 = -25 $
Since $ -5 > -25 $
✔ Answer: $ > $
---
(b) $ (-9) + (-6) \_\_\_\_\_\_ (-9) - (-6) $
Left: $ -9 + (-6) = -15 $
Right: $ -9 - (-6) = -9 + 6 = -3 $
Since $ -15 < -3 $
✔ Answer: $ < $
---
(c) $ 35 + (-70) - (-35) \_\_\_\_\_\_ (-24) - (15) + 39 $
Left:
$ 35 - 70 + 35 = (35 + 35) - 70 = 70 - 70 = 0 $
Right:
$ -24 - 15 + 39 = -39 + 39 = 0 $
So both sides are equal.
✔ Answer: $ = $
---
(a) $ (-1) \times (-2) \times (-3) \times (-4) \times (-5) $
Count negative signs: 5 negatives → odd number → result is negative
Multiply absolute values:
$ 1 \times 2 \times 3 \times 4 \times 5 = 120 $
So, $ -120 $
✔ Answer: $ -120 $
---
(b) $ 795 \times (-25) + (-795) \times 75 $
Factor out $ 795 $:
= $ 795 \times (-25) + (-795) \times 75 $
= $ 795 \times (-25) - 795 \times 75 $
= $ 795 \times [(-25) - 75] $
= $ 795 \times (-100) = -79500 $
✔ Answer: $ -79500 $
---
(c) $ (-59) + (-19) + 59 $
Group:
$ (-59 + 59) + (-19) = 0 - 19 = -19 $
✔ Answer: $ -19 $
---
Current position: $ +5 $ m
Final position: $ -20 $ m
Total distance descended = $ 5 - (-20) = 5 + 20 = 25 $ meters
Speed = 7 m/min
Time = $ \frac{25}{7} \approx 3.57 $ minutes
But let’s write it as fraction:
$ \frac{25}{7} $ minutes = $ 3 \frac{4}{7} $ minutes
Or in seconds: $ \frac{25}{7} \times 60 \approx 214.29 $ seconds
But likely expected in minutes.
✔ Answer: $ \frac{25}{7} $ minutes or approximately $ 3.57 $ minutes
---
On a number line:
- 3 is to the right of –3
- Distance between them: $ 3 - (-3) = 6 $
So, 3 is 6 units greater than –3.
✔ Answer: $ 6 $
---
Let the other number be $ x $.
Then:
$ x + 599 = -1500 $
$ x = -1500 - 599 = -2099 $
✔ Answer: $ -2099 $
---
## ✔ Final Answers Summary:
1. (a) 27
(b) 178
(c) -206
(d) -10
(e) 12
2. $ P = -15 $
3. Additive inverse of 0 is 0
4. Matching:
- (a) → (v)
- (b) → (iii)
- (c) → (i)
- (d) → (ii)
- (e) → (iv)
5. (a) >
(b) <
(c) =
6. (a) -120
(b) -79500
(c) -19
7. $ \frac{25}{7} $ minutes (≈ 3.57 min)
8. 6
9. -2099
Let me know if you'd like this explained with diagrams or further steps!
---
1. Fill in the blanks:
(a) $ 30 - \_\_\_\_\_\_ = 3 $
Let the missing number be $ x $.
So, $ 30 - x = 3 $
$ x = 30 - 3 = 27 $
✔ Answer: $ 27 $
---
(b) $ -89 + \_\_\_\_\_\_ = 89 $
Let the missing number be $ x $.
$ -89 + x = 89 $
$ x = 89 + 89 = 178 $
✔ Answer: $ 178 $
---
(c) $ \_\_\_\_\_\_ + 1 = -205 $
Let the missing number be $ x $.
$ x + 1 = -205 $
$ x = -205 - 1 = -206 $
✔ Answer: $ -206 $
---
(d) $ \_\_\_\_\_\_ \times (-12) = 120 $
Let the missing number be $ x $.
$ x \times (-12) = 120 $
$ x = \frac{120}{-12} = -10 $
✔ Answer: $ -10 $
---
(e) $ 24 + 12 \div 4 - 5 \times 3 = ? $
Apply BODMAS (Brackets, Orders, Division/Multiplication, Addition/Subtraction):
- $ 12 \div 4 = 3 $
- $ 5 \times 3 = 15 $
Now:
$ 24 + 3 - 15 = 27 - 15 = 12 $
✔ Answer: $ 12 $
---
2. Find the value of $ P $, if $ p \times (-9) = 135 $
We have:
$ p \times (-9) = 135 $
$ p = \frac{135}{-9} = -15 $
✔ Answer: $ -15 $
---
3. The additive inverse of zero (0) is ________
Additive inverse means a number that when added to the original gives 0.
For 0:
$ 0 + x = 0 $ → $ x = 0 $
So, the additive inverse of 0 is 0 itself.
✔ Answer: $ 0 $
---
4. Match the properties of Integers:
| Property | Match |
|--------|-------|
| (a) Distributive law over addition | (v) $ a \times (b + c) = a \times b + a \times c $ |
| (b) Associative law for multiplication | (iii) $ (a \times b) \times c = a \times (b \times c) $ |
| (c) Additive Identity | (i) $ a + 0 = a = 0 + a $ |
| (d) Commutative law over addition | (ii) $ a + b = b + a $ |
| (e) Multiplicative Identity | (iv) $ a \times 1 = 1 \times a = a $ |
✔ Matching:
- (a) → (v)
- (b) → (iii)
- (c) → (i)
- (d) → (ii)
- (e) → (iv)
---
5. Use the sign of >, < or = to make the statement true:
(a) $ 25 - 40 + 10 \_\_\_\_\_\_ 25 - 40 - 10 $
Left: $ 25 - 40 + 10 = -15 + 10 = -5 $
Right: $ 25 - 40 - 10 = -15 - 10 = -25 $
Since $ -5 > -25 $
✔ Answer: $ > $
---
(b) $ (-9) + (-6) \_\_\_\_\_\_ (-9) - (-6) $
Left: $ -9 + (-6) = -15 $
Right: $ -9 - (-6) = -9 + 6 = -3 $
Since $ -15 < -3 $
✔ Answer: $ < $
---
(c) $ 35 + (-70) - (-35) \_\_\_\_\_\_ (-24) - (15) + 39 $
Left:
$ 35 - 70 + 35 = (35 + 35) - 70 = 70 - 70 = 0 $
Right:
$ -24 - 15 + 39 = -39 + 39 = 0 $
So both sides are equal.
✔ Answer: $ = $
---
6. Evaluate:
(a) $ (-1) \times (-2) \times (-3) \times (-4) \times (-5) $
Count negative signs: 5 negatives → odd number → result is negative
Multiply absolute values:
$ 1 \times 2 \times 3 \times 4 \times 5 = 120 $
So, $ -120 $
✔ Answer: $ -120 $
---
(b) $ 795 \times (-25) + (-795) \times 75 $
Factor out $ 795 $:
= $ 795 \times (-25) + (-795) \times 75 $
= $ 795 \times (-25) - 795 \times 75 $
= $ 795 \times [(-25) - 75] $
= $ 795 \times (-100) = -79500 $
✔ Answer: $ -79500 $
---
(c) $ (-59) + (-19) + 59 $
Group:
$ (-59 + 59) + (-19) = 0 - 19 = -19 $
✔ Answer: $ -19 $
---
7. An elevator descends at 7 m/min from 5m above ground to –20m. How long?
Current position: $ +5 $ m
Final position: $ -20 $ m
Total distance descended = $ 5 - (-20) = 5 + 20 = 25 $ meters
Speed = 7 m/min
Time = $ \frac{25}{7} \approx 3.57 $ minutes
But let’s write it as fraction:
$ \frac{25}{7} $ minutes = $ 3 \frac{4}{7} $ minutes
Or in seconds: $ \frac{25}{7} \times 60 \approx 214.29 $ seconds
But likely expected in minutes.
✔ Answer: $ \frac{25}{7} $ minutes or approximately $ 3.57 $ minutes
---
8. With the help of number line find how much greater is 3 than –3
On a number line:
- 3 is to the right of –3
- Distance between them: $ 3 - (-3) = 6 $
So, 3 is 6 units greater than –3.
✔ Answer: $ 6 $
---
9. The sum of two integers is –1500. One is 599. Find the other.
Let the other number be $ x $.
Then:
$ x + 599 = -1500 $
$ x = -1500 - 599 = -2099 $
✔ Answer: $ -2099 $
---
## ✔ Final Answers Summary:
1. (a) 27
(b) 178
(c) -206
(d) -10
(e) 12
2. $ P = -15 $
3. Additive inverse of 0 is 0
4. Matching:
- (a) → (v)
- (b) → (iii)
- (c) → (i)
- (d) → (ii)
- (e) → (iv)
5. (a) >
(b) <
(c) =
6. (a) -120
(b) -79500
(c) -19
7. $ \frac{25}{7} $ minutes (≈ 3.57 min)
8. 6
9. -2099
Let me know if you'd like this explained with diagrams or further steps!
Parent Tip: Review the logic above to help your child master the concept of integers worksheet grade 7 pdf.