Finding Angles in Regular Polygons Worksheet, perfect angles ... - Free Printable
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Step-by-step solution for: Finding Angles in Regular Polygons Worksheet, perfect angles ...
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Step-by-step solution for: Finding Angles in Regular Polygons Worksheet, perfect angles ...
Here are the solutions to the problems on the worksheet, broken down by section.
1) Find the size of each interior angle in a regular hexagon.
* Step 1: A hexagon has 6 sides ($n=6$).
* Step 2: Calculate the sum of interior angles: $(6 - 2) \times 180^{\circ} = 4 \times 180^{\circ} = 720^{\circ}$.
* Step 3: Divide by the number of angles to find one angle: $720^{\circ} \div 6 = 120^{\circ}$.
* Answer: $120^{\circ}$
2) Find the size of each interior angle in a regular nonagon.
* Step 1: A nonagon has 9 sides ($n=9$).
* Step 2: Calculate the sum of interior angles: $(9 - 2) \times 180^{\circ} = 7 \times 180^{\circ} = 1260^{\circ}$.
* Step 3: Divide by the number of angles: $1260^{\circ} \div 9 = 140^{\circ}$.
* Answer: $140^{\circ}$
3) Find the size of each exterior angle in a regular dodecagon.
* Step 1: A dodecagon has 12 sides ($n=12$).
* Step 2: The sum of exterior angles for any polygon is always $360^{\circ}$.
* Step 3: Divide by the number of sides: $360^{\circ} \div 12 = 30^{\circ}$.
* Answer: $30^{\circ}$
4) Write an expression for the sum of the interior angles in a polygon with n sides.
* Rule: Sum $= (n - 2) \times 180$.
* Answer: $(n - 2) \times 180$
5) Write an expression for the size of each interior angle in a polygon with n sides.
* Rule: Take the sum from question 4 and divide by $n$.
* Answer: $\frac{(n - 2) \times 180}{n}$
6) Write an expression for the size of each exterior angle in a polygon with n sides.
* Rule: Divide total exterior degrees ($360$) by $n$.
* Answer: $\frac{360}{n}$
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1) Regular Pentagon
* Angle a (Interior):
* Sides $n=5$. Interior angle $= \frac{(5-2) \times 180}{5} = \frac{540}{5} = 108^{\circ}$.
* a = $108^{\circ}$
* Angle b (Exterior):
* Exterior angle $= \frac{360}{5} = 72^{\circ}$ (or $180 - 108$).
* b = $72^{\circ}$
2) Regular Pentagon with a diagonal
* Angle c:
* The triangle at the top is formed by two sides of the pentagon and a diagonal. It is an isosceles triangle because the two sides are equal length.
* The top angle is an interior angle of the pentagon ($108^{\circ}$).
* The base angles ($c$ and the other one) are equal.
* Calculation: $(180 - 108) \div 2 = 72 \div 2 = 36^{\circ}$.
* c = $36^{\circ}$
* Angle d:
* Angle $d$ plus angle $c$ make up the full interior angle of the pentagon ($108^{\circ}$).
* Calculation: $108 - 36 = 72^{\circ}$.
* d = $72^{\circ}$
3) Regular Hexagon with diagonals
* Angle e:
* This angle is inside a triangle formed by three vertices of the hexagon.
* The triangle is isosceles. The top angle is an interior angle of the hexagon ($120^{\circ}$).
* Base angles calculation: $(180 - 120) \div 2 = 30^{\circ}$.
* e = $30^{\circ}$
* Angle f:
* This angle is part of the corner vertex. The full interior angle is $120^{\circ}$.
* The diagonal cuts off a triangle identical to the one used for angle $e$, so the "slice" taken away is $30^{\circ}$.
* Calculation: $120 - 30 = 90^{\circ}$.
* f = $90^{\circ}$
4) Regular Hexagon divided into triangles
* Angle g (Exterior):
* Exterior angle of a hexagon $= \frac{360}{6} = 60^{\circ}$.
* g = $60^{\circ}$
* Angle h:
* The lines meet at the center. The angle around the center is $360^{\circ}$, split into 6 equal triangles.
* Calculation: $360 \div 6 = 60^{\circ}$.
* h = $60^{\circ}$
5) Regular Octagon
* Angle i:
* Interior angle of an octagon ($n=8$): $\frac{(8-2) \times 180}{8} = \frac{1080}{8} = 135^{\circ}$.
* i = $135^{\circ}$
* Angle j:
* This angle is inside a triangle formed by connecting vertices. The triangle spans 3 sides of the octagon.
* The vertex angle of this triangle (at the top right) corresponds to an interior angle of $135^{\circ}$.
* The triangle is isosceles. The two base angles are equal. One base angle is $j$.
* Wait, let's look closer. The chord connects vertex 1 to vertex 4. The triangle involved has vertices 1, 2, and 4? No, usually these diagrams imply symmetry.
* Let's use the circle method. An octagon fits in a circle. Each side subtends $\frac{360}{8} = 45^{\circ}$ at the center.
* Angle $j$ is an inscribed angle subtending 2 sides (from bottom-right to top-left via the right side).
* Inscribed angle = Half the central angle. Central angle for 2 sides $= 2 \times 45 = 90^{\circ}$.
* Angle $j = 90 \div 2 = 45^{\circ}$.
* j = $45^{\circ}$
6) Regular Decagon (10 sides)
* Angle k:
* Interior angle of decagon ($n=10$): $\frac{(10-2) \times 180}{10} = \frac{1440}{10} = 144^{\circ}$.
* Angle $k$ is inside an isosceles triangle formed by two sides and a short diagonal.
* Top angle is $144^{\circ}$. Base angles $= (180 - 144) \div 2 = 18^{\circ}$.
* k = $18^{\circ}$
* Angle l:
* This angle is formed by two intersecting diagonals.
* Using the circle rule again: Each side is $36^{\circ}$ ($\frac{360}{10}$).
* Angle $l$ faces an arc of 3 sides (looking at the geometry, it spans 3 segments of the perimeter).
* Central angle for 3 sides $= 3 \times 36 = 108^{\circ}$.
* Inscribed angle $l = 108 \div 2 = 54^{\circ}$.
* l = $54^{\circ}$
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Final Answer:
Section A
1) 120°
2) 140°
3) 30°
4) (n - 2) × 180
5) ((n - 2) × 180) / n
6) 360 / n
Section B
1) a = 108°, b = 72°
2) c = 36°, d = 72°
3) e = 30°, f = 90°
4) g = 60°, h = 60°
5) i = 135°, j = 45°
6) k = 18°, l = 54°
Section A
1) Find the size of each interior angle in a regular hexagon.
* Step 1: A hexagon has 6 sides ($n=6$).
* Step 2: Calculate the sum of interior angles: $(6 - 2) \times 180^{\circ} = 4 \times 180^{\circ} = 720^{\circ}$.
* Step 3: Divide by the number of angles to find one angle: $720^{\circ} \div 6 = 120^{\circ}$.
* Answer: $120^{\circ}$
2) Find the size of each interior angle in a regular nonagon.
* Step 1: A nonagon has 9 sides ($n=9$).
* Step 2: Calculate the sum of interior angles: $(9 - 2) \times 180^{\circ} = 7 \times 180^{\circ} = 1260^{\circ}$.
* Step 3: Divide by the number of angles: $1260^{\circ} \div 9 = 140^{\circ}$.
* Answer: $140^{\circ}$
3) Find the size of each exterior angle in a regular dodecagon.
* Step 1: A dodecagon has 12 sides ($n=12$).
* Step 2: The sum of exterior angles for any polygon is always $360^{\circ}$.
* Step 3: Divide by the number of sides: $360^{\circ} \div 12 = 30^{\circ}$.
* Answer: $30^{\circ}$
4) Write an expression for the sum of the interior angles in a polygon with n sides.
* Rule: Sum $= (n - 2) \times 180$.
* Answer: $(n - 2) \times 180$
5) Write an expression for the size of each interior angle in a polygon with n sides.
* Rule: Take the sum from question 4 and divide by $n$.
* Answer: $\frac{(n - 2) \times 180}{n}$
6) Write an expression for the size of each exterior angle in a polygon with n sides.
* Rule: Divide total exterior degrees ($360$) by $n$.
* Answer: $\frac{360}{n}$
---
Section B
1) Regular Pentagon
* Angle a (Interior):
* Sides $n=5$. Interior angle $= \frac{(5-2) \times 180}{5} = \frac{540}{5} = 108^{\circ}$.
* a = $108^{\circ}$
* Angle b (Exterior):
* Exterior angle $= \frac{360}{5} = 72^{\circ}$ (or $180 - 108$).
* b = $72^{\circ}$
2) Regular Pentagon with a diagonal
* Angle c:
* The triangle at the top is formed by two sides of the pentagon and a diagonal. It is an isosceles triangle because the two sides are equal length.
* The top angle is an interior angle of the pentagon ($108^{\circ}$).
* The base angles ($c$ and the other one) are equal.
* Calculation: $(180 - 108) \div 2 = 72 \div 2 = 36^{\circ}$.
* c = $36^{\circ}$
* Angle d:
* Angle $d$ plus angle $c$ make up the full interior angle of the pentagon ($108^{\circ}$).
* Calculation: $108 - 36 = 72^{\circ}$.
* d = $72^{\circ}$
3) Regular Hexagon with diagonals
* Angle e:
* This angle is inside a triangle formed by three vertices of the hexagon.
* The triangle is isosceles. The top angle is an interior angle of the hexagon ($120^{\circ}$).
* Base angles calculation: $(180 - 120) \div 2 = 30^{\circ}$.
* e = $30^{\circ}$
* Angle f:
* This angle is part of the corner vertex. The full interior angle is $120^{\circ}$.
* The diagonal cuts off a triangle identical to the one used for angle $e$, so the "slice" taken away is $30^{\circ}$.
* Calculation: $120 - 30 = 90^{\circ}$.
* f = $90^{\circ}$
4) Regular Hexagon divided into triangles
* Angle g (Exterior):
* Exterior angle of a hexagon $= \frac{360}{6} = 60^{\circ}$.
* g = $60^{\circ}$
* Angle h:
* The lines meet at the center. The angle around the center is $360^{\circ}$, split into 6 equal triangles.
* Calculation: $360 \div 6 = 60^{\circ}$.
* h = $60^{\circ}$
5) Regular Octagon
* Angle i:
* Interior angle of an octagon ($n=8$): $\frac{(8-2) \times 180}{8} = \frac{1080}{8} = 135^{\circ}$.
* i = $135^{\circ}$
* Angle j:
* This angle is inside a triangle formed by connecting vertices. The triangle spans 3 sides of the octagon.
* The vertex angle of this triangle (at the top right) corresponds to an interior angle of $135^{\circ}$.
* The triangle is isosceles. The two base angles are equal. One base angle is $j$.
* Wait, let's look closer. The chord connects vertex 1 to vertex 4. The triangle involved has vertices 1, 2, and 4? No, usually these diagrams imply symmetry.
* Let's use the circle method. An octagon fits in a circle. Each side subtends $\frac{360}{8} = 45^{\circ}$ at the center.
* Angle $j$ is an inscribed angle subtending 2 sides (from bottom-right to top-left via the right side).
* Inscribed angle = Half the central angle. Central angle for 2 sides $= 2 \times 45 = 90^{\circ}$.
* Angle $j = 90 \div 2 = 45^{\circ}$.
* j = $45^{\circ}$
6) Regular Decagon (10 sides)
* Angle k:
* Interior angle of decagon ($n=10$): $\frac{(10-2) \times 180}{10} = \frac{1440}{10} = 144^{\circ}$.
* Angle $k$ is inside an isosceles triangle formed by two sides and a short diagonal.
* Top angle is $144^{\circ}$. Base angles $= (180 - 144) \div 2 = 18^{\circ}$.
* k = $18^{\circ}$
* Angle l:
* This angle is formed by two intersecting diagonals.
* Using the circle rule again: Each side is $36^{\circ}$ ($\frac{360}{10}$).
* Angle $l$ faces an arc of 3 sides (looking at the geometry, it spans 3 segments of the perimeter).
* Central angle for 3 sides $= 3 \times 36 = 108^{\circ}$.
* Inscribed angle $l = 108 \div 2 = 54^{\circ}$.
* l = $54^{\circ}$
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Final Answer:
Section A
1) 120°
2) 140°
3) 30°
4) (n - 2) × 180
5) ((n - 2) × 180) / n
6) 360 / n
Section B
1) a = 108°, b = 72°
2) c = 36°, d = 72°
3) e = 30°, f = 90°
4) g = 60°, h = 60°
5) i = 135°, j = 45°
6) k = 18°, l = 54°
Parent Tip: Review the logic above to help your child master the concept of interior angle worksheet.