Ionic Bonding Worksheet demonstrating electron transfer and ion formation in chemical reactions.

Problem Overview:

The task involves analyzing ionic bonding reactions between pairs of elements. For each reaction, you need to:
1. Draw atomic diagrams showing the electron configurations of the atoms involved.
2. Indicate the transfer of electrons during the chemical reaction.
3. Show the resulting ions formed in the product.
4. Fill in a table summarizing the valence electrons, electron transfer, and ions formed.

Solution Explanation:

#### General Approach:
1. Identify Valence Electrons: Determine the number of valence electrons for each atom based on its position in the periodic table.
2. Electron Transfer: In ionic bonding, electrons are transferred from the metal (less electronegative) to the nonmetal (more electronegative) to achieve a stable electron configuration (usually 8 electrons in the outer shell).
3. Form Ions: After electron transfer, the metal forms a positively charged cation, and the nonmetal forms a negatively charged anion.
4. Balance Charges: The compound is electrically neutral, so the total positive charge must equal the total negative charge.

#### Detailed Analysis for Each Reaction:

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Reaction 1: Li + Cl → LiCl

- Li (Lithium):
- Valence electrons: 1
- Transfers 1 electron to Cl.
- Forms \( \text{Li}^+ \) ion.
- Cl (Chlorine):
- Valence electrons: 7
- Accepts 1 electron from Li.
- Forms \( \text{Cl}^- \) ion.
- Resulting Compound: \( \text{LiCl} \)

| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|-------------------------------------|-----------------------------|
| Li | 1 | 1 to Cl | \( \text{Li}^+ \) |
| Cl | 7 | 1 from Li | \( \text{Cl}^- \) |

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Reaction 2: Ca + O → CaO

- Ca (Calcium):
- Valence electrons: 2
- Transfers 2 electrons to O.
- Forms \( \text{Ca}^{2+} \) ion.
- O (Oxygen):
- Valence electrons: 6
- Accepts 2 electrons from Ca.
- Forms \( \text{O}^{2-} \) ion.
- Resulting Compound: \( \text{CaO} \)

| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|-------------------------------------|-----------------------------|
| Ca | 2 | 2 to O | \( \text{Ca}^{2+} \) |
| O | 6 | 2 from Ca | \( \text{O}^{2-} \) |

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Reaction 3: Be + F → BeF₂

- Be (Beryllium):
- Valence electrons: 2
- Transfers 1 electron to each F atom.
- Forms \( \text{Be}^{2+} \) ion.
- F (Fluorine):
- Valence electrons: 7
- Each F accepts 1 electron from Be.
- Forms \( \text{F}^- \) ions.
- Resulting Compound: \( \text{BeF}_2 \)

| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|-------------------------------------|-----------------------------|
| Be | 2 | 1 to each F | \( \text{Be}^{2+} \) |
| F | 7 | Each F gets 1 from Be | \( \text{F}^- \) |

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Reaction 4: Mg + S → MgS

- Mg (Magnesium):
- Valence electrons: 2
- Transfers 2 electrons to S.
- Forms \( \text{Mg}^{2+} \) ion.
- S (Sulfur):
- Valence electrons: 6
- Accepts 2 electrons from Mg.
- Forms \( \text{S}^{2-} \) ion.
- Resulting Compound: \( \text{MgS} \)

| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|-------------------------------------|-----------------------------|
| Mg | 2 | 2 to S | \( \text{Mg}^{2+} \) |
| S | 6 | 2 from Mg | \( \text{S}^{2-} \) |

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Reaction 5: K + F → KF

- K (Potassium):
- Valence electrons: 1
- Transfers 1 electron to F.
- Forms \( \text{K}^+ \) ion.
- F (Fluorine):
- Valence electrons: 7
- Accepts 1 electron from K.
- Forms \( \text{F}^- \) ion.
- Resulting Compound: \( \text{KF} \)

| Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-------|-------------------|-------------------------------------|-----------------------------|
| K | 1 | 1 to F | \( \text{K}^+ \) |
| F | 7 | 1 from K | \( \text{F}^- \) |

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Final Answer:

The completed table for all reactions is as follows:

| Reactions | Atoms | Valence electrons | Electron transfer from/to each atom | Ions formed in the product |
|-----------|-------|-------------------|-------------------------------------|-----------------------------|
| 1) Li + Cl → LiCl | Li | 1 | 1 to Cl | \( \text{Li}^+ \) |
| | Cl | 7 | 1 from Li | \( \text{Cl}^- \) |
| 2) Ca + O → CaO | Ca | 2 | 2 to O | \( \text{Ca}^{2+} \) |
| | O | 6 | 2 from Ca | \( \text{O}^{2-} \) |
| 3) Be + F → BeF₂ | Be | 2 | 1 to each F | \( \text{Be}^{2+} \) |
| | F | 7 | Each F gets 1 from Be | \( \text{F}^- \) |
| 4) Mg + S → MgS | Mg | 2 | 2 to S | \( \text{Mg}^{2+} \) |
| | S | 6 | 2 from Mg | \( \text{S}^{2-} \) |
| 5) K + F → KF | K | 1 | 1 to F | \( \text{K}^+ \) |
| | F | 7 | 1 from K | \( \text{F}^- \) |

\boxed{\text{See the completed table above.}}