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Ionic Bonding Worksheet featuring Lewis Dot Diagrams for ionic compounds.

Worksheet titled "Ionic Bonding Worksheet" with examples and exercises for drawing Lewis Dot Diagrams of ionic compounds, including Li⁺, F⁻, Ca²⁺, O²⁻, Be²⁺, F⁻, K⁺, and F⁻.

Worksheet titled "Ionic Bonding Worksheet" with examples and exercises for drawing Lewis Dot Diagrams of ionic compounds, including Li⁺, F⁻, Ca²⁺, O²⁻, Be²⁺, F⁻, K⁺, and F⁻.

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Show Answer Key & Explanations Step-by-step solution for: Ionic Bonds Worksheet by DeCicco Science worksheets library
It looks like you've uploaded a chemistry worksheet focused on Lewis Dot Structures and chemical bonding, specifically for ionic and covalent compounds. The task is to:

1. Draw Lewis dot structures for the atoms involved.
2. Show electron transfer or sharing during bond formation.
3. Fill in a table with atomic numbers, valence electrons, and the number of electrons lost/gained or shared.

Let’s go through each problem step by step.

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🔹 Example: Li + F → LiF



- Li (Lithium): Atomic number = 3 → Electron configuration: 1s² 2s¹ → 1 valence electron
- F (Fluorine): Atomic number = 9 → Electron configuration: 1s² 2s² 2p⁵ → 7 valence electrons

In the reaction:
- Li loses 1 electron to become Li⁺
- F gains 1 electron to become F⁻
- Forms an ionic bond

| Atom | Atomic Number | Valence Electrons | # of e⁻ lost/gained or shared |
|------|----------------|--------------------|-------------------------------|
| Li | 3 | 1 | 1 lost |
| F | 9 | 7 | 1 gained |

This matches the example.

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Now let's solve each of the problems.

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🔹 1. Li + Cl → LiCl



- Li: Atomic number = 3 → Valence electrons = 1
- Cl (Chlorine): Atomic number = 17 → Electron config: [Ne] 3s² 3p⁵ → Valence electrons = 7

→ Li transfers 1 electron to Cl → Ionic compound

| Atom | Atomic Number | Valence Electrons | # of e⁻ lost/gained or shared |
|------|----------------|--------------------|-------------------------------|
| Li | 3 | 1 | 1 lost |
| Cl | 17 | 7 | 1 gained |

📌 Lewis Structure:
- Li: `Li•` → becomes `Li⁺`
- Cl: `:Cl:•` (with 7 dots) → becomes `[:Cl:]⁻` (8 dots, octet)

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🔹 2. Ca + O → CaO



- Ca (Calcium): Atomic number = 20 → Electron config: [Ar] 4s² → Valence electrons = 2
- O (Oxygen): Atomic number = 8 → Electron config: 1s² 2s² 2p⁴ → Valence electrons = 6

→ Ca donates 2 electrons → O accepts 2 electrons → Ionic bond

| Atom | Atomic Number | Valence Electrons | # of e⁻ lost/gained or shared |
|------|----------------|--------------------|-------------------------------|
| Ca | 20 | 2 | 2 lost |
| O | 8 | 6 | 2 gained |

📌 Lewis Structure:
- Ca: `Ca:` → becomes `Ca²⁺`
- O: `:Ö:` (6 dots) → becomes `[:Ö:]²⁻` (8 dots)

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🔹 3. Ba + F → BaF₂



- Ba (Barium): Atomic number = 56 → Group 2 → Valence electrons = 2
- F (Fluorine): Atomic number = 9 → Valence electrons = 7

→ Ba loses 2 electrons → Each F gains 1 electron → So two F atoms needed

→ Formula: BaF₂

| Atom | Atomic Number | Valence Electrons | # of e⁻ lost/gained or shared |
|------|----------------|--------------------|-------------------------------|
| Ba | 56 | 2 | 2 lost |
| F | 9 | 7 | 1 gained (each F atom) |

⚠️ Note: Since two F atoms are involved, we write this as:

- One Ba atom loses 2 electrons
- Two F atoms each gain 1 electron

So total: 2 electrons transferred

📌 Lewis Structure:
- Ba: `Ba:` → becomes `Ba²⁺`
- F: `:F:•` → becomes `[:F:]⁻`

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🔹 4. K + F → KF



- K (Potassium): Atomic number = 19 → Group 1 → Valence electrons = 1
- F (Fluorine): Atomic number = 9 → Valence electrons = 7

→ K loses 1 electron → F gains 1 electron → Ionic bond

| Atom | Atomic Number | Valence Electrons | # of e⁻ lost/gained or shared |
|------|----------------|--------------------|-------------------------------|
| K | 19 | 1 | 1 lost |
| F | 9 | 7 | 1 gained |

📌 Lewis Structure:
- K: `K•` → becomes `K⁺`
- F: `:F:•` → becomes `[:F:]⁻`

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Final Answer Table:



| Problem | Atom | Atomic Number | Valence Electrons | # of e⁻ lost/gained or shared |
|--------|------|----------------|--------------------|-------------------------------|
| 1. Li + Cl → LiCl | Li | 3 | 1 | 1 lost |
| | Cl | 17 | 7 | 1 gained |
| 2. Ca + O → CaO | Ca | 20 | 2 | 2 lost |
| | O | 8 | 6 | 2 gained |
| 3. Ba + F → BaF₂ | Ba | 56 | 2 | 2 lost |
| | F | 9 | 7 | 1 gained (per F atom) |
| 4. K + F → KF | K | 19 | 1 | 1 lost |
| | F | 9 | 7 | 1 gained |

> 💡 Notes:
> - All these are ionic compounds (metal + nonmetal).
> - Electrons are transferred, not shared.
> - Metals lose electrons → form cations
> - Nonmetals gain electrons → form anions
> - The number of electrons lost must equal electrons gained.

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🧠 Summary:



- Use periodic table to find atomic number and valence electrons.
- For ionic bonds: metal transfers electrons to nonmetal.
- Write charges accordingly.
- In Lewis structures, show dots for valence electrons and arrows showing electron transfer.

Let me know if you'd like the actual drawings of the Lewis structures!
Parent Tip: Review the logic above to help your child master the concept of ionic bond worksheet.
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