Worksheet for practicing naming and writing formulas of binary ionic compounds.

It looks like you've uploaded a chemistry worksheet titled "Nomenclature Packet", specifically Worksheet 1: Binary Ionic Compounds (representative metals). The task involves naming ionic compounds and writing chemical formulas based on their names.

Let’s go through each section step by step and solve the problems with explanations.

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Section 1: Name the following ionic compounds

We are given chemical formulas and need to name them using proper ionic compound nomenclature rules.

#### Rules for Naming Binary Ionic Compounds:
- The cation (metal) is named first, using its elemental name.
- The anion (nonmetal) is named second, with the suffix *-ide*.
- For representative metals (Group 1, 2, and some in Group 13), charges are predictable:
- Group 1: +1
- Group 2: +2
- Aluminum (Al): +3
- So we don't need Roman numerals for these.

Now let's solve:

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a. Al₂O₃ → Aluminum oxide
- Al³⁺ and O²⁻ → Charge balance: 2×(+3) = +6, 3×(-2) = -6 → neutral
✔ Correct

b. CaO → Calcium oxide
- Ca²⁺ and O²⁻ → neutral
✔ Correct

c. MgCl₂ → Magnesium chloride
- Mg²⁺ and Cl⁻ → two Cl⁻ needed
✔ Correct

d. CaS → Calcium sulfide
- Ca²⁺ and S²⁻ → neutral
✔ Correct

e. SrI₂ → Strontium iodide
- Sr²⁺ and I⁻ → two I⁻ needed
✔ Correct

f. Cs₂S → Cesium sulfide
- Cs⁺ and S²⁻ → two Cs⁺ needed
✔ Correct

g. Al₂S₃ → Aluminum sulfide
- Al³⁺ and S²⁻ → LCM of 3 and 2 is 6 → 2 Al³⁺ and 3 S²⁻
✔ Correct

h. LiBr → Lithium bromide
- Li⁺ and Br⁻ → neutral
✔ Correct

i. Mg₃N₂ → Magnesium nitride
- Mg²⁺ and N³⁻ → LCM of 2 and 3 is 6 → 3 Mg²⁺ and 2 N³⁻
✔ Correct

j. CaF₂ → Calcium fluoride
- Ca²⁺ and F⁻ → two F⁻ needed
✔ Correct

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✔ All answers in Section 1 are already correct as written.

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Section 2: Write the chemical formula for the following ionic compounds

Now we reverse the process — from name to formula.

#### Rules:
- Determine the charge of each ion.
- Use subscripts to balance the total positive and negative charges.
- Simplify subscripts to lowest terms (if needed).

Let’s go one by one:

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a. Barium nitride
- Ba²⁺, N³⁻
- LCM of 2 and 3 is 6 → 3 Ba²⁺ = +6, 2 N³⁻ = -6
→ Ba₃N₂

✔ Answer: Ba₃N₂

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b. Sodium fluoride
- Na⁺, F⁻ → 1:1 ratio
→ NaF

✔ Answer: NaF

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c. Calcium oxide
- Ca²⁺, O²⁻ → 1:1 ratio
→ CaO

✔ Answer: CaO

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d. Sodium nitride
- Na⁺, N³⁻
- LCM of 1 and 3 is 3 → 3 Na⁺, 1 N³⁻
→ Na₃N

✔ Answer: Na₃N

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e. Magnesium chloride
- Mg²⁺, Cl⁻
- Need 2 Cl⁻ for one Mg²⁺
→ MgCl₂

✔ Answer: MgCl₂

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f. Potassium iodide
- K⁺, I⁻ → 1:1
→ KI

✔ Answer: KI

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g. Magnesium oxide
- Mg²⁺, O²⁻ → 1:1
→ MgO

✔ Answer: MgO

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h. Potassium sulfide
- K⁺, S²⁻
- Need 2 K⁺ for one S²⁻
→ K₂S

✔ Answer: K₂S

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i. Lithium nitride
- Li⁺, N³⁻
- 3 Li⁺ for 1 N³⁻
→ Li₃N

✔ Answer: Li₃N

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j. Strontium fluoride
- Sr²⁺, F⁻
- Need 2 F⁻ for one Sr²⁺
→ SrF₂

✔ Answer: SrF₂

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k. Aluminum sulfide
- Al³⁺, S²⁻
- LCM of 3 and 2 is 6 → 2 Al³⁺ = +6, 3 S²⁻ = -6
→ Al₂S₃

✔ Answer: Al₂S₃

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l. Calcium oxide
- Already done: Ca²⁺, O²⁻ → CaO

✔ Answer: CaO

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✔ Final Answers for Section 2:

| Compound | Formula |
|-----------------------|-------------|
| a. Barium nitride | Ba₃N₂ |
| b. Sodium fluoride | NaF |
| c. Calcium oxide | CaO |
| d. Sodium nitride | Na₃N |
| e. Magnesium chloride | MgCl₂ |
| f. Potassium iodide | KI |
| g. Magnesium oxide | MgO |
| h. Potassium sulfide | K₂S |
| i. Lithium nitride | Li₃N |
| j. Strontium fluoride | SrF₂ |
| k. Aluminum sulfide | Al₂S₃ |
| l. Calcium oxide | CaO |

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✔ Summary:

All answers in the original worksheet are correct. You can use this completed version to check your work or submit it.

If you were asking for help verifying or understanding any part, feel free to ask!