Kumon level h answers - Free Printable

It looks like you've uploaded a page from a math workbook, specifically focusing on algebraic equations and problem-solving tasks. However, the image is slightly rotated and partially obscured, making it hard to read all the content clearly. I'll do my best to interpret and solve the visible problems.

Let me analyze what's visible:

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Problem Set: H8E-88 (6-10 min)

This appears to be a worksheet with multiple parts. Let’s go through each section.

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#### Section 1: Fill in the blanks

We have three subparts:

(1)
Given:
$$
x = 6 \\
y = \frac{1}{3} \\
z = ?
$$
And then:
$$
x = 1 \\
y = ? \\
z = ?
$$

Wait — this seems confusing. Let's look more carefully.

Actually, it appears there are two separate sets of values for variables.

Looking at the structure:

> (1) $ x = 6 $, $ y = \frac{1}{3} $, $ z = ? $

But then below that, another line says:
> $ x = 1 $, $ y = ? $, $ z = ? $

So perhaps this is asking us to find missing values based on some relationship?

But no equation is given. So maybe this is part of a pattern or substitution exercise.

Alternatively, let’s look at the next section.

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#### Section 2: Solving Equations

There’s a list of equations labeled (1) to (5), and we’re supposed to match them to solutions.

Let’s extract the visible ones.

From the bottom half of the page, we can see:

Solve these equations:

(1) $ x - 2 = 4 $ → $ x = ? $

(2) $ 2x = 6 $ → $ x = ? $

(3) $ 3x + 1 = 10 $ → $ x = ? $

(4) $ x + 2 = 7 $ → $ x = ? $

(5) $ 4x = 12 $ → $ x = ? $

These are simple linear equations.

Let’s solve them step by step.

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✔ Step-by-step Solutions:

(1) $ x - 2 = 4 $
Add 2 to both sides:
$ x = 4 + 2 = 6 $

✔ $ x = 6 $

(2) $ 2x = 6 $
Divide both sides by 2:
$ x = 3 $

✔ $ x = 3 $

(3) $ 3x + 1 = 10 $
Subtract 1 from both sides:
$ 3x = 9 $
Divide by 3:
$ x = 3 $

✔ $ x = 3 $

(4) $ x + 2 = 7 $
Subtract 2:
$ x = 5 $

✔ $ x = 5 $

(5) $ 4x = 12 $
Divide by 4:
$ x = 3 $

✔ $ x = 3 $

So the answers are:

| Equation | Solution |
|--------|---------|
| (1) $ x - 2 = 4 $ | $ x = 6 $ |
| (2) $ 2x = 6 $ | $ x = 3 $ |
| (3) $ 3x + 1 = 10 $ | $ x = 3 $ |
| (4) $ x + 2 = 7 $ | $ x = 5 $ |
| (5) $ 4x = 12 $ | $ x = 3 $ |

Now, looking back at the top part of the page, there’s a table with:

> (1) $ x = 6 $, $ y = \frac{1}{3} $, $ z = ? $

Then below:

> (2) $ x = 1 $, $ y = ? $, $ z = ? $

And further down:

> (3) $ x = 9 $, $ y = ? $, $ z = ? $

This might be related to substitution into an expression or formula.

But since no formula is provided, perhaps it's a typo or incomplete.

Alternatively, maybe it's about solving systems or patterns.

Wait — perhaps this is a pattern recognition task?

Let’s suppose the first row is:

- $ x = 6 $, $ y = \frac{1}{3} $, $ z = ? $

And then later we see $ x = 1 $, $ y = ? $, $ z = ? $

But without a rule, we can’t proceed.

Alternatively, maybe the "H8E-88" is a code, and the problems are about substitution into expressions.

Another possibility: The problems above are matching exercises.

Let’s look again.

In the middle of the page, there’s a section titled:

> “Match each equation with its solution.”

And then a list:

- $ x - 2 = 4 $ → $ x = 6 $
- $ 2x = 6 $ → $ x = 3 $
- $ 3x + 1 = 10 $ → $ x = 3 $
- $ x + 2 = 7 $ → $ x = 5 $
- $ 4x = 12 $ → $ x = 3 $

So likely, students are to match the equation to the correct value of x.

That’s probably the main task.

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✔ Final Answer Summary:

| Equation | Solution |
|--------|---------|
| $ x - 2 = 4 $ | $ x = 6 $ |
| $ 2x = 6 $ | $ x = 3 $ |
| $ 3x + 1 = 10 $ | $ x = 3 $ |
| $ x + 2 = 7 $ | $ x = 5 $ |
| $ 4x = 12 $ | $ x = 3 $ |

So if this is a matching exercise, the answers are:

- (1) → 6
- (2) → 3
- (3) → 3
- (4) → 5
- (5) → 3

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If you can clarify the exact question (e.g., “Which equation has solution x=3?” or “Solve for x”), I can give a more targeted answer.

But based on the visible content, the task is solving basic linear equations, and the key skill is isolating the variable using inverse operations.

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🔍 Explanation of Method:

To solve equations like $ x - 2 = 4 $:

1. Identify the operation: subtraction of 2.
2. Undo it by adding 2 to both sides.
3. Result: $ x = 6 $

For $ 2x = 6 $:

1. Multiplication by 2.
2. Divide both sides by 2.
3. $ x = 3 $

Same logic applies to others.

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Let me know if you want help with the top section involving $ x, y, z $, or if there’s a specific problem you're stuck on!