Solved You In the worksheet below you will draw the Lewis | Chegg.com - Free Printable

- BCl₃: Boron has 3 valence electrons, each Cl contributes 1 electron for bonding. Total valence electrons = 3 + 3×7 = 24. Lewis structure: B central atom with three single bonds to Cl atoms, no lone pairs on B. Each Cl has 3 lone pairs.
- NF₃: Nitrogen has 5 valence electrons, each F contributes 1 electron for bonding. Total valence electrons = 5 + 3×7 = 26. Lewis structure: N central atom with three single bonds to F atoms and one lone pair on N. Each F has 3 lone pairs.
- PH₃: Phosphorus has 5 valence electrons, each H contributes 1 electron for bonding. Total valence electrons = 5 + 3×1 = 8. Lewis structure: P central atom with three single bonds to H atoms and one lone pair on P.
- SBr₂: Sulfur has 6 valence electrons, each Br contributes 1 electron for bonding. Total valence electrons = 6 + 2×7 = 20. Lewis structure: S central atom with two single bonds to Br atoms and two lone pairs on S. Each Br has 3 lone pairs.
- BaI₂: Barium is a metal, iodine is a nonmetal. This is an ionic compound. Lewis structure: [Ba]²⁺ and two [I]⁻ ions. Each I⁻ has 8 valence electrons (4 lone pairs).
- Li₂O: Lithium is a metal, oxygen is a nonmetal. This is an ionic compound. Lewis structure: two [Li]⁺ ions and [O]²⁻ ion. O²⁻ has 8 valence electrons (4 lone pairs).
- CBr₄: Carbon has 4 valence electrons, each Br contributes 1 electron for bonding. Total valence electrons = 4 + 4×7 = 32. Lewis structure: C central atom with four single bonds to Br atoms. Each Br has 3 lone pairs.
- AlH₃: Aluminum has 3 valence electrons, each H contributes 1 electron for bonding. Total valence electrons = 3 + 3×1 = 6. Lewis structure: Al central atom with three single bonds to H atoms, no lone pairs on Al.
- NBr₃: Nitrogen has 5 valence electrons, each Br contributes 1 electron for bonding. Total valence electrons = 5 + 3×7 = 26. Lewis structure: N central atom with three single bonds to Br atoms and one lone pair on N. Each Br has 3 lone pairs.
- CH₂Cl₂: Carbon has 4 valence electrons, each H contributes 1, each Cl contributes 1 for bonding. Total valence electrons = 4 + 2×1 + 2×7 = 20. Lewis structure: C central atom with two single bonds to H atoms and two single bonds to Cl atoms. Each Cl has 3 lone pairs.
- CaBr₂: Calcium is a metal, bromine is a nonmetal. This is an ionic compound. Lewis structure: [Ca]²⁺ and two [Br]⁻ ions. Each Br⁻ has 8 valence electrons (4 lone pairs).
- H₂Se: Selenium has 6 valence electrons, each H contributes 1 electron for bonding. Total valence electrons = 6 + 2×1 = 8. Lewis structure: Se central atom with two single bonds to H atoms and two lone pairs on Se.
- NO₃⁻: Nitrogen has 5 valence electrons, each O has 6, plus 1 for the charge. Total valence electrons = 5 + 3×6 + 1 = 24. Lewis structure: N central atom with one double bond to O and two single bonds to O atoms. The single-bonded O atoms each have 3 lone pairs and a negative formal charge. The double-bonded O has 2 lone pairs. Resonance structures exist.
- NO₂Cl: Nitrogen has 5 valence electrons, each O has 6, Cl has 7. Total valence electrons = 5 + 2×6 + 7 = 24. Lewis structure: N central atom with one double bond to O, one single bond to O, and one single bond to Cl. The single-bonded O has 3 lone pairs and a negative formal charge, N has a positive formal charge. Cl has 3 lone pairs. Resonance structures exist.
- SCF₂: Sulfur has 6 valence electrons, C has 4, each F has 7. Total valence electrons = 6 + 4 + 2×7 = 24. Lewis structure: C central atom bonded to S and two F atoms. Double bond between C and S, single bonds between C and each F. S has 2 lone pairs, each F has 3 lone pairs. Formal charges: S=0, C=0, F=0.
- SO₃: Sulfur has 6 valence electrons, each O has 6. Total valence electrons = 6 + 3×6 = 24. Lewis structure: S central atom with three double bonds to O atoms. Each O has 2 lone pairs. Resonance structures exist.
- P₂: Each phosphorus has 5 valence electrons. Total valence electrons = 2×5 = 10. Lewis structure: Triple bond between two P atoms, each P has one lone pair.
- ClO₂⁻: Chlorine has 7 valence electrons, each O has 6, plus 1 for the charge. Total valence electrons = 7 + 2×6 + 1 = 20. Lewis structure: Cl central atom with one double bond to O and one single bond to O. The single-bonded O has 3 lone pairs and a negative formal charge. Cl has 2 lone pairs and a positive formal charge. Resonance structures exist.
- BrO₃⁻: Bromine has 7 valence electrons, each O has 6, plus 1 for the charge. Total valence electrons = 7 + 3×6 + 1 = 26. Lewis structure: Br central atom with one double bond to O and two single bonds to O atoms. The single-bonded O atoms each have 3 lone pairs and a negative formal charge. Br has 1 lone pair. Resonance structures exist.
- ClO₄⁻: Chlorine has 7 valence electrons, each O has 6, plus 1 for the charge. Total valence electrons = 7 + 4×6 + 1 = 32. Lewis structure: Cl central atom with four single bonds to O atoms. Each O has 3 lone pairs. One O has a negative formal charge, Cl has a positive formal charge. Resonance structures exist where one bond is double and others are single.
- SiS₂: Silicon has 4 valence electrons, each S has 6. Total valence electrons = 4 + 2×6 = 16. Lewis structure: Si central atom with two double bonds to S atoms. Each S has 2 lone pairs.
- S₃: Each sulfur has 6 valence electrons. Total valence electrons = 3×6 = 18. Lewis structure: Central S atom single bonded to two terminal S atoms. Central S has 2 lone pairs, each terminal S has 3 lone pairs. Formal charges: terminal S = -1, central S = +1. Resonance structures exist.
- NH₄⁺: Nitrogen has 5 valence electrons, each H contributes 1, minus 1 for the charge. Total valence electrons = 5 + 4×1 - 1 = 8. Lewis structure: N central atom with four single bonds to H atoms, no lone pairs on N. Positive charge on N.