Long division practice worksheet with 12 problems to find remainders.

To solve the problem, we need to perform long division for each of the given divisions and identify the remainder. Let's go through each division step by step.

1. \( 2 \div 4892 \)

- Divide: \( 4892 \div 2 = 2446 \)
- Remainder: \( 0 \)

2. \( 3 \div 9287 \)

- Divide: \( 9287 \div 3 = 3095 \) with a remainder of \( 2 \)
- Remainder: \( 2 \)

3. \( 7 \div 2784 \)

- Divide: \( 2784 \div 7 = 397 \) with a remainder of \( 5 \)
- Remainder: \( 5 \)

4. \( 8 \div 7891 \)

- Divide: \( 7891 \div 8 = 986 \) with a remainder of \( 3 \)
- Remainder: \( 3 \)

5. \( 9 \div 3862 \)

- Divide: \( 3862 \div 9 = 429 \) with a remainder of \( 1 \)
- Remainder: \( 1 \)

6. \( 4 \div 5288 \)

- Divide: \( 5288 \div 4 = 1322 \) with a remainder of \( 0 \)
- Remainder: \( 0 \)

7. \( 6 \div 7483 \)

- Divide: \( 7483 \div 6 = 1247 \) with a remainder of \( 1 \)
- Remainder: \( 1 \)

8. \( 5 \div 7389 \)

- Divide: \( 7389 \div 5 = 1477 \) with a remainder of \( 4 \)
- Remainder: \( 4 \)

9. \( 2 \div 1294 \)

- Divide: \( 1294 \div 2 = 647 \) with a remainder of \( 0 \)
- Remainder: \( 0 \)

10. \( 9 \div 8120 \)

- Divide: \( 8120 \div 9 = 902 \) with a remainder of \( 2 \)
- Remainder: \( 2 \)

11. \( 3 \div 8946 \)

- Divide: \( 8946 \div 3 = 2982 \) with a remainder of \( 0 \)
- Remainder: \( 0 \)

12. \( 8 \div 2689 \)

- Divide: \( 2689 \div 8 = 336 \) with a remainder of \( 1 \)
- Remainder: \( 1 \)

13. \( 7 \div 4575 \)

- Divide: \( 4575 \div 7 = 653 \) with a remainder of \( 4 \)
- Remainder: \( 4 \)

14. \( 9 \div 5579 \)

- Divide: \( 5579 \div 9 = 619 \) with a remainder of \( 8 \)
- Remainder: \( 8 \)

15. \( 4 \div 2584 \)

- Divide: \( 2584 \div 4 = 646 \) with a remainder of \( 0 \)
- Remainder: \( 0 \)

Final Answer:

The remainders for each division are as follows:

\[
\begin{array}{c|c|c|c|c}
2 \div 4892 & 3 \div 9287 & 7 \div 2784 & 8 \div 7891 & 9 \div 3862 \\
\hline
0 & 2 & 5 & 3 & 1 \\
\hline
4 \div 5288 & 6 \div 7483 & 5 \div 7389 & 2 \div 1294 & 9 \div 8120 \\
\hline
0 & 1 & 4 & 0 & 2 \\
\hline
3 \div 8946 & 8 \div 2689 & 7 \div 4575 & 9 \div 5579 & 4 \div 2584 \\
\hline
0 & 1 & 4 & 8 & 0 \\
\end{array}
\]

Thus, the final answer is:

\[
\boxed{0, 2, 5, 3, 1, 0, 1, 4, 0, 2, 0, 1, 4, 8, 0}
\]