Long Division Worksheets (with and without Remainders) - Aussie ... - Free Printable

Problem Description:

The image shows a division worksheet with several division problems. The task is to solve the division problems step by step, similar to the sample problem provided.

Sample Problem (Highlighted):

The sample problem is:
$$
2 \longdiv{161}
$$
The solution is shown as:
$$
\begin{array}{r|l}
2 & 161 \\
\hline
& 80 \\
& -160 \\
\hline
& 1 \\
\end{array}
$$
This indicates that \( 161 \div 2 = 80 \) with a remainder of 1.

Task:

Solve the remaining division problems on the worksheet using the same method as the sample.

---

Solution:

#### 1. Problem 1: \( 2 \longdiv{714} \)
We divide 714 by 2 step by step:
- Step 1: Divide the first digit, 7, by 2. \( 7 \div 2 = 3 \) with a remainder of 1.
- Step 2: Bring down the next digit, 1, to make it 11. \( 11 \div 2 = 5 \) with a remainder of 1.
- Step 3: Bring down the next digit, 4, to make it 14. \( 14 \div 2 = 7 \) with no remainder.

Thus, \( 714 \div 2 = 357 \).

#### 2. Problem 2: \( 3 \longdiv{882} \)
We divide 882 by 3 step by step:
- Step 1: Divide the first digit, 8, by 3. \( 8 \div 3 = 2 \) with a remainder of 2.
- Step 2: Bring down the next digit, 8, to make it 28. \( 28 \div 3 = 9 \) with a remainder of 1.
- Step 3: Bring down the next digit, 2, to make it 12. \( 12 \div 3 = 4 \) with no remainder.

Thus, \( 882 \div 3 = 294 \).

#### 3. Problem 3: \( 3 \longdiv{100} \)
We divide 100 by 3 step by step:
- Step 1: Divide the first digit, 1, by 3. Since 1 is less than 3, we consider the first two digits, 10.
- Step 2: \( 10 \div 3 = 3 \) with a remainder of 1.
- Step 3: Bring down the next digit, 0, to make it 10. \( 10 \div 3 = 3 \) with a remainder of 1.

Thus, \( 100 \div 3 = 33 \) with a remainder of 1.

#### 4. Problem 4: \( 2 \longdiv{916} \)
We divide 916 by 2 step by step:
- Step 1: Divide the first digit, 9, by 2. \( 9 \div 2 = 4 \) with a remainder of 1.
- Step 2: Bring down the next digit, 1, to make it 11. \( 11 \div 2 = 5 \) with a remainder of 1.
- Step 3: Bring down the next digit, 6, to make it 16. \( 16 \div 2 = 8 \) with no remainder.

Thus, \( 916 \div 2 = 458 \).

#### 5. Problem 5: \( 4 \longdiv{120} \)
We divide 120 by 4 step by step:
- Step 1: Divide the first digit, 1, by 4. Since 1 is less than 4, we consider the first two digits, 12.
- Step 2: \( 12 \div 4 = 3 \) with no remainder.
- Step 3: Bring down the next digit, 0. \( 0 \div 4 = 0 \) with no remainder.

Thus, \( 120 \div 4 = 30 \).

#### 6. Problem 6: \( 8 \longdiv{150} \)
We divide 150 by 8 step by step:
- Step 1: Divide the first digit, 1, by 8. Since 1 is less than 8, we consider the first two digits, 15.
- Step 2: \( 15 \div 8 = 1 \) with a remainder of 7.
- Step 3: Bring down the next digit, 0, to make it 70. \( 70 \div 8 = 8 \) with a remainder of 6.

Thus, \( 150 \div 8 = 18 \) with a remainder of 6.

#### 7. Problem 7: \( 4 \longdiv{140} \)
We divide 140 by 4 step by step:
- Step 1: Divide the first digit, 1, by 4. Since 1 is less than 4, we consider the first two digits, 14.
- Step 2: \( 14 \div 4 = 3 \) with a remainder of 2.
- Step 3: Bring down the next digit, 0, to make it 20. \( 20 \div 4 = 5 \) with no remainder.

Thus, \( 140 \div 4 = 35 \).

#### 8. Problem 8: \( 5 \longdiv{125} \)
We divide 125 by 5 step by step:
- Step 1: Divide the first digit, 1, by 5. Since 1 is less than 5, we consider the first two digits, 12.
- Step 2: \( 12 \div 5 = 2 \) with a remainder of 2.
- Step 3: Bring down the next digit, 5, to make it 25. \( 25 \div 5 = 5 \) with no remainder.

Thus, \( 125 \div 5 = 25 \).

#### 9. Problem 9: \( 9 \longdiv{190} \)
We divide 190 by 9 step by step:
- Step 1: Divide the first digit, 1, by 9. Since 1 is less than 9, we consider the first two digits, 19.
- Step 2: \( 19 \div 9 = 2 \) with a remainder of 1.
- Step 3: Bring down the next digit, 0, to make it 10. \( 10 \div 9 = 1 \) with a remainder of 1.

Thus, \( 190 \div 9 = 21 \) with a remainder of 1.

#### 10. Problem 10: \( 3 \longdiv{180} \)
We divide 180 by 3 step by step:
- Step 1: Divide the first digit, 1, by 3. Since 1 is less than 3, we consider the first two digits, 18.
- Step 2: \( 18 \div 3 = 6 \) with no remainder.
- Step 3: Bring down the next digit, 0. \( 0 \div 3 = 0 \) with no remainder.

Thus, \( 180 \div 3 = 60 \).

#### 11. Problem 11: \( 6 \longdiv{155} \)
We divide 155 by 6 step by step:
- Step 1: Divide the first digit, 1, by 6. Since 1 is less than 6, we consider the first two digits, 15.
- Step 2: \( 15 \div 6 = 2 \) with a remainder of 3.
- Step 3: Bring down the next digit, 5, to make it 35. \( 35 \div 6 = 5 \) with a remainder of 5.

Thus, \( 155 \div 6 = 25 \) with a remainder of 5.

---

Final Answers:

1. \( 714 \div 2 = 357 \)
2. \( 882 \div 3 = 294 \)
3. \( 100 \div 3 = 33 \) R1
4. \( 916 \div 2 = 458 \)
5. \( 120 \div 4 = 30 \)
6. \( 150 \div 8 = 18 \) R6
7. \( 140 \div 4 = 35 \)
8. \( 125 \div 5 = 25 \)
9. \( 190 \div 9 = 21 \) R1
10. \( 180 \div 3 = 60 \)
11. \( 155 \div 6 = 25 \) R5

Boxed Final Answer:

\[
\boxed{
\begin{aligned}
1. & \ 357 \\
2. & \ 294 \\
3. & \ 33 \text{ R1} \\
4. & \ 458 \\
5. & \ 30 \\
6. & \ 18 \text{ R6} \\
7. & \ 35 \\
8. & \ 25 \\
9. & \ 21 \text{ R1} \\
10. & \ 60 \\
11. & \ 25 \text{ R5} \\
\end{aligned}
}
\]