This worksheet challenges students to calculate the correct change for various purchases using $50 bills.

Final Answer:
1. $21.00
2. 1 bill ($20) and 3 coins (3 quarters = $0.75), total 4 pieces
3. Yes
4. 5 nickels (or any combination totaling $0.50 with 5 coins, e.g., 2 dimes + 3 pennies is $0.23 — wait, that’s not $0.50; correct answer: 5 dimes = $0.50, but that’s 5 coins — actually, $40.00 − $35.50 = $4.50 change? Wait — re-read: Andrea paid with two $20 bills = $40.00 for a $35.50 shirt → change = $4.50. She got 5 coins. So $4.50 in change, 5 coins → must be 5 coins totaling $4.50? Impossible with standard U.S. coins (max coin is $1). Ah—mistake: *She got 5 coins in change* — meaning the coin part of her change was 5 coins, and the rest was bills. But question asks: “What coins were they?” implying the 5 coins make up the *entire* change? That can’t be unless it’s a trick. Let’s compute: $40.00 − $35.50 = $4.50. To make $4.50 with exactly 5 coins: only possible if using half-dollars or dollar coins. Standard U.S. coins: penny, nickel, dime, quarter, half-dollar ($0.50), dollar coin ($1.00). With 5 coins totaling $4.50: e.g., 4 × $1.00 coins + 1 × $0.50 = $4.50 (5 coins). So answer: four dollar coins and one half-dollar. But many curricula assume only up to quarters. Re-check problem: likely expects change = $4.50, and 5 coins → must be 5 dimes? No, 5 dimes = $0.50. Wait—maybe typo? Alternative: perhaps she paid with two $20 bills = $40, shirt $35.50, change $4.50. If she received 5 coins, those coins must total the *fractional* part: $0.50, and the $4 was in bills. So 5 coins = $0.50 → possible with 5 dimes, or 2 quarters + 5 pennies (7 coins), no. 5 dimes = $0.50, exactly 5 coins. Yes! So the 5 coins are dimes, making $0.50, and she also got $4 in bills (e.g., four $1 bills). The question asks only: “What coins were they?” → answer: 5 dimes.

But let’s verify all:

1. Shoes $32.00 + socks $7.00 = $39.00. Paid $50.00 → change = $11.00? Wait! $50 − $39 = $11.00 — earlier I said $21.00 — that’s wrong!

Correct calculations:

1. $32.00 + $7.00 = $39.00. $50.00 − $39.00 = $11.00

2. CD $17.89, paid $50.00 → change = $50.00 − $17.89 = $32.11. Least number of coins and bills: use largest denominations. $32.11 = one $20 bill, one $10 bill, two $1 bills, one dime, one penny → that’s 5 bills + 2 coins = 7 pieces. But question asks “least amount of coins and bills” — maybe they want minimal *total pieces*. Better: $32.11 = one $20, one $10, two $1s = $32, then 11¢ = one dime + one penny → total 5 bills + 2 coins = 7. Can we do fewer? Use $5 bills? $20 + $5 + $5 + $1 + $1 = $32 (4 bills) + 11¢ (2 coins) = 6 pieces. Even better: $20 + $5 + $5 + $1 + $1 = 5 bills? No, that’s 5 bills. Wait: $20, $10, $1, $1 = 4 bills for $32, plus 2 coins = 6 total. Using two $5s instead of $10 doesn’t help. Minimum is 6 pieces: 4 bills ($20, $10, $1, $1) and 2 coins (dime, penny). But maybe they expect just the coin part? Re-read: “What is the least amount of coins and bills he could get for change?” → total number of pieces. $32.11 → optimal: one $20, one $10, two $1s (4 bills), one dime, one penny (2 coins) = 6 pieces. Cannot do 5: because $32 needs at least 2 bills if using $20s and $10s, but $20+$10=$30, need $2 more → two $1s, so 4 bills minimum, plus ≥2 coins for 11¢ → 6 min.

3. Skateboard $27.29, paid $50 → change should be $50 − $27.29 = $22.71. He got $23.71 → that’s $1.00 too much → No, he did *not* get the right change.

4. Shirt $35.50, paid $40.00 (two $20s) → change = $4.50. She got 5 coins. Since coins can’t make $4.50 alone (unless using dollar coins), but typical elementary problems assume coins are pennies, nickels, dimes, quarters. So likely the 5 coins make the *cents part*: $0.50. So 5 coins = $0.50 → only way: 5 dimes. Yes.

So correct final answers:
1. $11.00
2. 6 pieces (e.g., $20, $10, $1, $1, dime, penny) — but question asks “least amount of coins and bills”, so answer is 6
3. No
4. 5 dimes

But the instruction says: “Provide only the final correct answer.” — and list all four.

Let me finalize with precise answers as expected in grade school:

1. $11.00
2. 6 (1 twenty, 1 ten, 2 ones, 1 dime, 1 penny)
3. No
4. 5 dimes

Since the format says “Final Answer: [Provide only the final correct answer.]”, and there are 4 questions, list them clearly.

Final Answer:
1. $11.00
2. 6
3. No
4. 5 dimes