100+ Free Math Games for Grade 4 ONLINE Practice - Free Printable

Let’s solve this step by step.

We are adding:

```
328
+ 6_1
------
___
```

The blank in the second number (the tens place) must be filled with one of the digits on the left: 0, 9, 2, or 9 — but since we’re building a valid addition problem that likely results in a clean sum, and we have to pick *one* digit to fill the blank, let’s test each possibility logically.

But wait — actually, looking at the layout, it seems like we are meant to choose one digit from the left column to fill the blank in “6 _ 1”, and then compute the full sum. The three blanks below are for the result.

So our goal is:
Pick one digit from {0, 9, 2, 9} → put it in the middle of 6_1 → add to 328 → get a 3-digit answer.

Let’s try each option:

---

Option 1: Use 0 → 601

328 + 601 = ?

8 + 1 = 9
2 + 0 = 2
3 + 6 = 9
→ Sum = 929

That’s a valid 3-digit number. And look — the digits 9, 2, 9 are available on the left! So maybe we use those to fill the answer? But the problem doesn’t say we have to use them — it just shows them as options for the blank.

Wait — perhaps the task is:
Fill the blank in “6 _ 1” using one of the given digits (0,9,2,9), then calculate the sum, and write the sum in the bottom three boxes.

Since 328 + 601 = 929, and 9,2,9 are among the choices, that fits nicely.

Let’s check other options to make sure.

---

Option 2: Use 9 → 691

328 + 691 = ?

8 + 1 = 9
2 + 9 = 11 → write 1, carry 1
3 + 6 + 1 = 10 → write 0, carry 1 → but now we’d need a 4th digit! Result would be 1019 — too big. Not 3 digits. ✘

---

Option 3: Use 2 → 621

328 + 621 = ?

8 + 1 = 9
2 + 2 = 4
3 + 6 = 9
→ Sum = 949

Digits 9,4,9 — but 4 is not in the left column. Also, 949 is fine numerically, but if the game expects us to use only provided digits for the answer, this might not fit. However, the problem doesn’t specify that the answer digits must come from the left — only the blank in the addend does.

But wait — 949 uses 9 and 4 — 4 isn’t available. Whereas 929 uses 9,2,9 — which ARE available. That suggests 601 is the intended choice.

Also, note: there are two 9s on the left — so even if we used 9 for the blank, we still have another 9 and 2 and 0 left — but again, 691 gives 1019 which is invalid.

What about using the second 9? Same as first 9 → same result.

So only 0 and 2 give 3-digit sums.

Between 601 → 929 and 621 → 949...

Now, here’s the key: the answer boxes are empty, and we have to fill them. If we pick 0 for the blank, we get 929 — and 9,2,9 are exactly the digits shown on the left (except 0 is used in the addend). That feels intentional.

If we pick 2, we get 949 — but 4 is not among the available digits on the left. Since the interface shows only 0,9,2,9 as selectable, and the answer has to be written in boxes (probably expecting digits you can select?), 929 makes more sense because all its digits are available.

Moreover, 328 + 601 = 929 is correct arithmetic.

Let me double-check:

328
+601
= 929 ✔

Yes.

Therefore, the missing digit in “6 _ 1” is 0, and the sum is 929.

Final Answer:
929