To solve the given simple linear equations, we will isolate the variable on one side of the equation. Let's solve each equation step by step.
First Row:
1.
\( 3x - 3 = 24 \)
\[
3x - 3 = 24
\]
Add 3 to both sides:
\[
3x = 27
\]
Divide by 3:
\[
x = 9
\]
2.
\( 3v - 6 = 3 \)
\[
3v - 6 = 3
\]
Add 6 to both sides:
\[
3v = 9
\]
Divide by 3:
\[
v = 3
\]
3.
\( 3z - 2 = 16 \)
\[
3z - 2 = 16
\]
Add 2 to both sides:
\[
3z = 18
\]
Divide by 3:
\[
z = 6
\]
Second Row:
4.
\( 3x + 10 = 31 \)
\[
3x + 10 = 31
\]
Subtract 10 from both sides:
\[
3x = 21
\]
Divide by 3:
\[
x = 7
\]
5.
\( 2z + 8 = 18 \)
\[
2z + 8 = 18
\]
Subtract 8 from both sides:
\[
2z = 10
\]
Divide by 2:
\[
z = 5
\]
6.
\( 3u + 6 = 9 \)
\[
3u + 6 = 9
\]
Subtract 6 from both sides:
\[
3u = 3
\]
Divide by 3:
\[
u = 1
\]
Third Row:
7.
\( 3z + 8 = 23 \)
\[
3z + 8 = 23
\]
Subtract 8 from both sides:
\[
3z = 15
\]
Divide by 3:
\[
z = 5
\]
8.
\( 2u - 3 = 5 \)
\[
2u - 3 = 5
\]
Add 3 to both sides:
\[
2u = 8
\]
Divide by 2:
\[
u = 4
\]
9.
\( 3x + 9 = 21 \)
\[
3x + 9 = 21
\]
Subtract 9 from both sides:
\[
3x = 12
\]
Divide by 3:
\[
x = 4
\]
Fourth Row:
10.
\( 3v - 4 = 5 \)
\[
3v - 4 = 5
\]
Add 4 to both sides:
\[
3v = 9
\]
Divide by 3:
\[
v = 3
\]
11.
\( 2x + 1 = 21 \)
\[
2x + 1 = 21
\]
Subtract 1 from both sides:
\[
2x = 20
\]
Divide by 2:
\[
x = 10
\]
12.
\( 3z - 7 = 5 \)
\[
3z - 7 = 5
\]
Add 7 to both sides:
\[
3z = 12
\]
Divide by 3:
\[
z = 4
\]
Fifth Row:
13.
\( 2c - 1 = 3 \)
\[
2c - 1 = 3
\]
Add 1 to both sides:
\[
2c = 4
\]
Divide by 2:
\[
c = 2
\]
14.
\( 2u + 6 = 16 \)
\[
2u + 6 = 16
\]
Subtract 6 from both sides:
\[
2u = 10
\]
Divide by 2:
\[
u = 5
\]
15.
\( 2a - 10 = 2 \)
\[
2a - 10 = 2
\]
Add 10 to both sides:
\[
2a = 12
\]
Divide by 2:
\[
a = 6
\]
Final Answers:
\[
\boxed{
\begin{array}{ccc}
x = 9 & v = 3 & z = 6 \\
x = 7 & z = 5 & u = 1 \\
z = 5 & u = 4 & x = 4 \\
v = 3 & x = 10 & z = 4 \\
c = 2 & u = 5 & a = 6 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of math problems for 7th graders worksheet.