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Grade 5 math worksheet with four word problems requiring students to solve equations using addition, subtraction, multiplication, and division.

Grade 5 Four Operations Word Problem Worksheet 2 featuring four math word problems involving multiplication, division, and real-life scenarios.

Grade 5 Four Operations Word Problem Worksheet 2 featuring four math word problems involving multiplication, division, and real-life scenarios.

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Show Answer Key & Explanations Step-by-step solution for: Grade 5 Word Problems | Free Printables | Worksheets
Let's solve each word problem step by step and explain the solution.

---

Problem 1:


Leticia started an online store selling handmade blankets. She sold 92 blankets in her first month. How much did she make if each blanket cost $49?

Solution:
We need to find the total money made by multiplying the number of blankets sold by the price per blanket.

$$
\text{Total earnings} = \text{Number of blankets} \times \text{Price per blanket}
$$
$$
= 92 \times 49
$$

Now calculate:
$$
92 \times 49 = 92 \times (50 - 1) = (92 \times 50) - (92 \times 1)
$$
$$
= 4600 - 92 = 4508
$$

Answer: $4,508

---

Problem 2:


Peter bought a box of 70 chocolates. Each chocolate had 12 square pieces on it. He wants to split the pieces up between himself and his 11 cousins. How many square pieces do they each get?

Step 1: Find the total number of square pieces.
$$
\text{Total pieces} = 70 \text{ chocolates} \times 12 \text{ pieces per chocolate} = 840 \text{ pieces}
$$

Step 2: Peter + 11 cousins = 12 people total.

$$
\text{Pieces per person} = \frac{840}{12} = 70
$$

Answer: 70 square pieces each

---

Problem 3:


A local mechanic on average services 14 cars a week. How many cars does he service over 4 years (52 weeks in a year)?

Step 1: Calculate total number of weeks in 4 years.
$$
52 \text{ weeks/year} \times 4 \text{ years} = 208 \text{ weeks}
$$

Step 2: Multiply by number of cars serviced per week.
$$
14 \text{ cars/week} \times 208 \text{ weeks} = 2912 \text{ cars}
$$

Answer: 2,912 cars

---

Problem 4:


Sheryl was organizing buses for a school trip. She had 171 children, 22 teachers & 13 parents. A bus could take 20 passengers. How many buses would she need and how many spare seats would be left for extra luggage?

Step 1: Total number of people:
$$
171 \text{ (children)} + 22 \text{ (teachers)} + 13 \text{ (parents)} = 206 \text{ people}
$$

Step 2: Each bus holds 20 passengers.

$$
\text{Number of buses needed} = \left\lceil \frac{206}{20} \right\rceil
$$
$$
\frac{206}{20} = 10.3
$$

Since you can't have a fraction of a bus, round up to the next whole number → 11 buses

Step 3: Total capacity of 11 buses:
$$
11 \times 20 = 220 \text{ seats}
$$

Step 4: Spare seats:
$$
220 - 206 = 14 \text{ spare seats}
$$

Answer: 11 buses are needed, with 14 spare seats for extra luggage.

---

Final Answers:



1. $4,508
2. 70 square pieces each
3. 2,912 cars
4. 11 buses, 14 spare seats

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Parent Tip: Review the logic above to help your child master the concept of math word problem worksheet.
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