Math worksheet for practicing fraction reduction and finding equivalent fractions.

Final Answer:
1. $\frac{11}{53}$
2. $\frac{18}{19}$
3. $\frac{7}{9}$
4. $\frac{5}{14.5}$ → Wait, 116 ÷ 8 = 14.5? No — let’s fix that. Actually, 40 and 116 can both be divided by 4: $\frac{10}{29}$
5. $\frac{7}{11}$
6. $\frac{29}{34}$
7. $\frac{4}{5} = \frac{40}{50} = \frac{60}{75}$
8. $\frac{37}{37} = \frac{74}{74} = \frac{111}{111}$ → That’s just 1. But if it’s meant to be equivalent fractions with same value, maybe typo? Let’s assume it’s $\frac{37}{37} = 1$, so all are 1. But more likely, the first number is numerator? If it’s $\frac{?}{37} = \frac{?}{74} = \frac{?}{111}$, then since 74 = 2×37, 111=3×37, so it’s $\frac{1}{1}, \frac{2}{2}, \frac{3}{3}$ — but that doesn’t fit. Wait — perhaps it’s $\frac{37}{37} = \frac{74}{74} = \frac{111}{111}$ — all equal to 1. So answer is 1 for all.
But looking at others, like #7: 4/5 = ?/50 → 40/50, ?/75 → 60/75. So for #8: if it’s $\frac{?}{37} = \frac{?}{74} = \frac{?}{111}$, and we want same fraction, then multiply numerator and denominator by same number. 37→74 is ×2, 37→111 is ×3. So if original is 1/1, then 2/2, 3/3 — but denominators are given. So numerators should be 37, 74, 111 — meaning the fraction is 1. So:
8. $\frac{37}{37} = \frac{74}{74} = \frac{111}{111}$ → all = 1
9. $\frac{1}{5} = \frac{5}{25} = \frac{9}{45}$
10. $\frac{6}{9} = \frac{10}{15} = \frac{14}{21}$
11. $\frac{1}{4} = \frac{9}{36} = \frac{3}{12}$
12. $\frac{62}{62} = \frac{31}{31} = \frac{93}{93}$ → all = 1

Wait — problem #12 says: 62 = 31 = 93 — that doesn’t make sense. Probably it’s $\frac{?}{62} = \frac{?}{31} = \frac{?}{93}$. Since 62 = 2×31, 93=3×31, so if we take 1/1, then 2/2, 3/3 — but denominators are 62,31,93. So numerators should be 62, 31, 93 — again, all equal to 1. So same as #8.

Actually, let’s re-read: “Complete the equivalent fractions.” So for #8: it’s written as “37 = 74 = 111” — that must mean $\frac{?}{37} = \frac{?}{74} = \frac{?}{111}$, and we need to fill in numerators so they’re equivalent. Since 74 = 2×37, 111=3×37, then if we start with 1/1, then 2/2, 3/3 — but denominators are fixed. So to have same value, say x/37 = y/74 = z/111. The simplest is to set them all equal to 1: so 37/37, 74/74, 111/111. But that seems redundant. Perhaps it’s a typo, and it’s supposed to be like #7: $\frac{4}{5} = \frac{?}{50} = \frac{?}{75}$. For #8, if it’s $\frac{?}{37} = \frac{?}{74} = \frac{?}{111}$, then the common value could be 1, so numerators are 37,74,111. But that’s trivial. Alternatively, maybe the first number is the numerator? Like in #7, it’s 4/5 = ?/50 = ?/75. So for #8, it might be 37/? = 74/? = 111/? — but that doesn’t match the format. Looking at the image description, it’s written as “37 = 74 = 111” under “Complete the equivalent fractions.” — probably it’s $\frac{37}{x} = \frac{74}{y} = \frac{111}{z}$, but that doesn’t help. I think there’s a formatting issue. In many worksheets, it’s written as: $\frac{4}{5} = \frac{}{50} = \frac{}{75}$, so blanks to fill. Similarly, for #8: $\frac{}{37} = \frac{}{74} = \frac{}{111}$. And since 74 = 2×37, 111=3×37, the fraction is 1/1, so numerators are 37,74,111. But that’s not standard. Perhaps it’s meant to be the same fraction value, so for example, if we take 1/1, then 37/37, etc. But let's check #12: “62 = 31 = 93” — same issue. Perhaps it’s $\frac{62}{?} = \frac{31}{?} = \frac{93}{?}$, but that would require different denominators. I think the most reasonable interpretation is that for #8, it’s $\frac{a}{37} = \frac{b}{74} = \frac{c}{111}$, and a,b,c are to be found such that the fractions are equivalent. The simplest is to set them all equal to 1, so a=37, b=74, c=111. Similarly for #12: a=62, b=31, c=93 for $\frac{a}{62} = \frac{b}{31} = \frac{c}{93}$ — but 62/62=1, 31/31=1, 93/93=1, so yes. But for #11: $\frac{1}{4} = \frac{}{36} = \frac{}{12}$ — 36÷4=9, so 9/36, 12÷4=3, so 3/12. So for #8, if it’s $\frac{}{37} = \frac{}{74} = \frac{}{111}$, and we want the same fraction, say k, then k*37, k*74, k*111. But what k? The only way to have integers is if k=1, so 37,74,111. But that seems odd. Perhaps it's a mistake, and it's supposed to be like #7. Another possibility: in some worksheets, they write the fraction as "numerator denominator" without slash, but here it's clear from context. I think for consistency, I'll assume that for #8, it's $\frac{37}{37} = \frac{74}{74} = \frac{111}{111} = 1$, and similarly for #12. But let's look at #9: $\frac{1}{5} = \frac{}{25} = \frac{}{45}$ — 25÷5=5, so 5/25, 45÷5=9, so 9/45. So for #8, if it's $\frac{}{37} = \frac{}{74} = \frac{}{111}$, then to have the same value as a fraction, we need to choose a common value. The GCD of 37,74,111 is 37, since 37 is prime, 74=2*37, 111=3*37. So the fraction could be 1/1, so numerators are 37,74,111. Or if we want a reduced form, but 1/1 is reduced. I think it's correct.

So final answers:

1. $\frac{44}{212} = \frac{11}{53}$ (divided by 4)
2. $\frac{36}{38} = \frac{18}{19}$ (divided by 2)
3. $\frac{56}{72} = \frac{7}{9}$ (divided by 8)
4. $\frac{40}{116} = \frac{10}{29}$ (divided by 4)
5. $\frac{35}{55} = \frac{7}{11}$ (divided by 5)
6. $\frac{58}{68} = \frac{29}{34}$ (divided by 2)
7. $\frac{4}{5} = \frac{40}{50} = \frac{60}{75}$ (multiplied numerator and denominator by 10 and 15 respectively)
8. $\frac{37}{37} = \frac{74}{74} = \frac{111}{111}$ or simply 1,1,1 — but to fill the blanks, if it's $\frac{}{37} = \frac{}{74} = \frac{}{111}$, then 37,74,111
9. $\frac{1}{5} = \frac{5}{25} = \frac{9}{45}$ (multiplied by 5 and 9)
10. $\frac{6}{9} = \frac{10}{15} = \frac{14}{21}$ (simplified 6/9 to 2/3, then 2/3 = 10/15, 14/21)
11. $\frac{1}{4} = \frac{9}{36} = \frac{3}{12}$ (multiplied by 9 and 3)
12. $\frac{62}{62} = \frac{31}{31} = \frac{93}{93}$ or 62,31,93 for the numerators if denominators are given.

But for #12, if it's "62 = 31 = 93", and it's under "complete the equivalent fractions", likely it's $\frac{62}{x} = \frac{31}{y} = \frac{93}{z}$, but that doesn't specify. Perhaps it's $\frac{}{62} = \frac{}{31} = \frac{}{93}$, and we need numerators. Since 62=2*31, 93=3*31, so if we set the fraction to 1, then 62,31,93. But 31/31=1, 62/62=1, 93/93=1, so yes.

To avoid confusion, I'll provide the answers as per standard interpretation.

Final Answer:
1. $\frac{11}{53}$
2. $\frac{18}{19}$
3. $\frac{7}{9}$
4. $\frac{10}{29}$
5. $\frac{7}{11}$
6. $\frac{29}{34}$
7. $\frac{40}{50}, \frac{60}{75}$
8. $\frac{37}{37}, \frac{74}{74}, \frac{111}{111}$ or if blanks are for numerators, 37, 74, 111
9. $\frac{5}{25}, \frac{9}{45}$
10. $\frac{10}{15}, \frac{14}{21}$
11. $\frac{9}{36}, \frac{3}{12}$
12. $\frac{62}{62}, \frac{31}{31}, \frac{93}{93}$ or 62, 31, 93

Since the user didn't specify which parts to solve, and it's a worksheet, I'll provide all.

But for the response, since ExplainAnswer, TeachTopic, GeneratePractice are false, I only need Final Answer.

So I'll list them clearly.

Final Answer:
1. $\frac{11}{53}$
2. $\frac{18}{19}$
3. $\frac{7}{9}$
4. $\frac{10}{29}$
5. $\frac{7}{11}$
6. $\frac{29}{34}$
7. $\frac{40}{50}$ and $\frac{60}{75}$
8. $\frac{37}{37}$, $\frac{74}{74}$, $\frac{111}{111}$ (or numerators: 37, 74, 111)
9. $\frac{5}{25}$ and $\frac{9}{45}$
10. $\frac{10}{15}$ and $\frac{14}{21}$
11. $\frac{9}{36}$ and $\frac{3}{12}$
12. $\frac{62}{62}$, $\frac{31}{31}$, $\frac{93}{93}$ (or numerators: 62, 31, 93)

To make it neat, I'll write as per the format.

Since the instruction is to provide only the final correct answer, and it's multiple problems, I'll list them.

But perhaps for simplicity, I can box each or list.

Given the constraints, I'll write:

Final Answer:
1. $\frac{11}{53}$
2. $\frac{18}{19}$
3. $\frac{7}{9}$
4. $\frac{10}{29}$
5. $\frac{7}{11}$
6. $\frac{29}{34}$
7. $\frac{40}{50}, \frac{60}{75}$
8. $37, 74, 111$ (assuming numerators for denominators 37,74,111)
9. $5, 9$ (numerators for denominators 25,45)
10. $10, 14$ (numerators for denominators 15,21)
11. $9, 3$ (numerators for denominators 36,12)
12. $62, 31, 93$ (numerators for denominators 62,31,93)

For #8, if it's "37 = 74 = 111", and it's to complete equivalent fractions, likely it's to find the numerators when denominators are given, so 37,74,111 for the respective denominators.

Similarly for others.

I think this is acceptable.

So final answer as above.