mean,median,mode class 7 | eonwo - Free Printable

Let's solve each problem step by step. For each set of numbers, we will calculate:

- Mean: The average of the numbers = (Sum of all numbers) ÷ (Number of values)
- Median: The middle number when the numbers are arranged in order. If there is an even number of values, it’s the average of the two middle numbers.
- Mode: The number that appears most frequently. If no number repeats, there is no mode.

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1. 32, 33, 22, 85, 58

Step 1: Order the numbers:
22, 32, 33, 58, 85

Mean:
(22 + 32 + 33 + 58 + 85) ÷ 5 = 230 ÷ 5 = 46

Median:
Middle number (3rd in ordered list): 33

Mode:
No number repeats → No mode

✔ Mean: 46, Median: 33, Mode: No mode

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2. 18, 18, 26, 36, 64

Order: 18, 18, 26, 36, 64

Mean:
(18 + 18 + 26 + 36 + 64) ÷ 5 = 162 ÷ 5 = 32.4

Median:
Middle number: 26

Mode:
18 appears twice → 18

✔ Mean: 32.4, Median: 26, Mode: 18

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3. 58, 84, 90, 90, 97

Order: 58, 84, 90, 90, 97

Mean:
(58 + 84 + 90 + 90 + 97) ÷ 5 = 419 ÷ 5 = 83.8

Median:
Middle number: 90

Mode:
90 appears twice → 90

✔ Mean: 83.8, Median: 90, Mode: 90

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4. 9, 15, 28, 10, 8

Order: 8, 9, 10, 15, 28

Mean:
(8 + 9 + 10 + 15 + 28) ÷ 5 = 70 ÷ 5 = 14

Median:
Middle number: 10

Mode:
All numbers appear once → No mode

✔ Mean: 14, Median: 10, Mode: No mode

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5. 21, 15, 16, 25, 13, 18

Order: 13, 15, 16, 18, 21, 25

Mean:
(13 + 15 + 16 + 18 + 21 + 25) ÷ 6 = 108 ÷ 6 = 18

Median:
Even count → Average of 3rd and 4th: (16 + 18) ÷ 2 = 17

Mode:
All numbers appear once → No mode

✔ Mean: 18, Median: 17, Mode: No mode

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6. 53, 44, 10, 45, 59, 97, 77

Order: 10, 44, 45, 53, 59, 77, 97

Mean:
(10 + 44 + 45 + 53 + 59 + 77 + 97) ÷ 7 = 435 ÷ 7 ≈ 62.14

Median:
Middle number (4th): 53

Mode:
All numbers unique → No mode

✔ Mean: ~62.14, Median: 53, Mode: No mode

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7. 5, 3, 2, 6, 5, 2, 5

Order: 2, 2, 3, 5, 5, 5, 6

Mean:
(2 + 2 + 3 + 5 + 5 + 5 + 6) ÷ 7 = 28 ÷ 7 = 4

Median:
Middle number (4th): 5

Mode:
5 appears 3 times → 5

✔ Mean: 4, Median: 5, Mode: 5

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8. 6, 6, 6, 7, 7, 5, 4

Order: 4, 5, 6, 6, 6, 7, 7

Mean:
(4 + 5 + 6 + 6 + 6 + 7 + 7) ÷ 7 = 41 ÷ 7 ≈ 5.86

Median:
Middle number (4th): 6

Mode:
6 appears 3 times → 6

✔ Mean: ~5.86, Median: 6, Mode: 6

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9. 9, 19, 16, 9, 16, 2, 14, 8, 2

Order: 2, 2, 8, 9, 9, 14, 16, 16, 19

Mean:
(2 + 2 + 8 + 9 + 9 + 14 + 16 + 16 + 19) ÷ 9 = 95 ÷ 9 ≈ 10.56

Median:
Middle number (5th): 9

Mode:
2, 9, 16 each appear twice → No single mode (bimodal or multimodal — but usually say "no mode" unless specified)

But since multiple numbers repeat equally, No mode (or if allowed: 2, 9, 16)

Typically in basic math: No mode

✔ Mean: ~10.56, Median: 9, Mode: No mode

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10. 19, 5, 9, 12, 10, 5

Order: 5, 5, 9, 10, 12, 19

Mean:
(5 + 5 + 9 + 10 + 12 + 19) ÷ 6 = 60 ÷ 6 = 10

Median:
Average of 3rd and 4th: (9 + 10) ÷ 2 = 9.5

Mode:
5 appears twice → 5

✔ Mean: 10, Median: 9.5, Mode: 5

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✔ Final Answers:

| Problem | Mean | Median | Mode |
|--------|----------|--------|------------|
| 1 | 46 | 33 | No mode |
| 2 | 32.4 | 26 | 18 |
| 3 | 83.8 | 90 | 90 |
| 4 | 14 | 10 | No mode |
| 5 | 18 | 17 | No mode |
| 6 | 62.14 | 53 | No mode |
| 7 | 4 | 5 | 5 |
| 8 | 5.86 | 6 | 6 |
| 9 | 10.56 | 9 | No mode |
| 10 | 10 | 9.5 | 5 |

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