Practice worksheet for finding mean, median, mode, and range with four number sets.

To solve the problem, we need to calculate the mean, median, mode, and range for each set of numbers provided. Let's go through each part step by step.

---

Part a: 3, 4, 9, 7, 7

#### Mean
The mean is the average of the numbers. It is calculated as:
\[
\text{Mean} = \frac{\text{Sum of all numbers}}{\text{Total number of values}}
\]
- Sum of the numbers: \(3 + 4 + 9 + 7 + 7 = 30\)
- Total number of values: 5
\[
\text{Mean} = \frac{30}{5} = 6
\]

#### Median
The median is the middle number when the numbers are arranged in ascending order.
- Arranged in ascending order: \(3, 4, 7, 7, 9\)
- Since there are 5 numbers (odd count), the median is the middle number: \(7\)

#### Mode
The mode is the number that appears most frequently.
- In the set \(3, 4, 9, 7, 7\), the number \(7\) appears twice, which is more frequent than any other number.
\[
\text{Mode} = 7
\]

#### Range
The range is the difference between the largest and smallest numbers.
- Largest number: \(9\)
- Smallest number: \(3\)
\[
\text{Range} = 9 - 3 = 6
\]

#### Final Answers for Part a:
\[
\text{Mean} = 6, \quad \text{Median} = 7, \quad \text{Mode} = 7, \quad \text{Range} = 6
\]

---

Part b: 15, 3, 3, 3

#### Mean
\[
\text{Mean} = \frac{\text{Sum of all numbers}}{\text{Total number of values}}
\]
- Sum of the numbers: \(15 + 3 + 3 + 3 = 24\)
- Total number of values: 4
\[
\text{Mean} = \frac{24}{4} = 6
\]

#### Median
- Arranged in ascending order: \(3, 3, 3, 15\)
- Since there are 4 numbers (even count), the median is the average of the two middle numbers (\(3\) and \(3\)):
\[
\text{Median} = \frac{3 + 3}{2} = 3
\]

#### Mode
The number \(3\) appears three times, which is more frequent than any other number.
\[
\text{Mode} = 3
\]

#### Range
- Largest number: \(15\)
- Smallest number: \(3\)
\[
\text{Range} = 15 - 3 = 12
\]

#### Final Answers for Part b:
\[
\text{Mean} = 6, \quad \text{Median} = 3, \quad \text{Mode} = 3, \quad \text{Range} = 12
\]

---

Part c: 3, 0, 0, 2, 0

#### Mean
\[
\text{Mean} = \frac{\text{Sum of all numbers}}{\text{Total number of values}}
\]
- Sum of the numbers: \(3 + 0 + 0 + 2 + 0 = 5\)
- Total number of values: 5
\[
\text{Mean} = \frac{5}{5} = 1
\]

#### Median
- Arranged in ascending order: \(0, 0, 0, 2, 3\)
- Since there are 5 numbers (odd count), the median is the middle number: \(0\)

#### Mode
The number \(0\) appears three times, which is more frequent than any other number.
\[
\text{Mode} = 0
\]

#### Range
- Largest number: \(3\)
- Smallest number: \(0\)
\[
\text{Range} = 3 - 0 = 3
\]

#### Final Answers for Part c:
\[
\text{Mean} = 1, \quad \text{Median} = 0, \quad \text{Mode} = 0, \quad \text{Range} = 3
\]

---

Part d: 5, 6, 5, 2, 4, 1

#### Mean
\[
\text{Mean} = \frac{\text{Sum of all numbers}}{\text{Total number of values}}
\]
- Sum of the numbers: \(5 + 6 + 5 + 2 + 4 + 1 = 23\)
- Total number of values: 6
\[
\text{Mean} = \frac{23}{6} \approx 3.83
\]

#### Median
- Arranged in ascending order: \(1, 2, 4, 5, 5, 6\)
- Since there are 6 numbers (even count), the median is the average of the two middle numbers (\(4\) and \(5\)):
\[
\text{Median} = \frac{4 + 5}{2} = 4.5
\]

#### Mode
The number \(5\) appears twice, which is more frequent than any other number.
\[
\text{Mode} = 5
\]

#### Range
- Largest number: \(6\)
- Smallest number: \(1\)
\[
\text{Range} = 6 - 1 = 5
\]

#### Final Answers for Part d:
\[
\text{Mean} \approx 3.83, \quad \text{Median} = 4.5, \quad \text{Mode} = 5, \quad \text{Range} = 5
\]

---

Part e: 10, 6, 3, 10, 1

#### Mean
\[
\text{Mean} = \frac{\text{Sum of all numbers}}{\text{Total number of values}}
\]
- Sum of the numbers: \(10 + 6 + 3 + 10 + 1 = 30\)
- Total number of values: 5
\[
\text{Mean} = \frac{30}{5} = 6
\]

#### Median
- Arranged in ascending order: \(1, 3, 6, 10, 10\)
- Since there are 5 numbers (odd count), the median is the middle number: \(6\)

#### Mode
The number \(10\) appears twice, which is more frequent than any other number.
\[
\text{Mode} = 10
\]

#### Range
- Largest number: \(10\)
- Smallest number: \(1\)
\[
\text{Range} = 10 - 1 = 9
\]

#### Final Answers for Part e:
\[
\text{Mean} = 6, \quad \text{Median} = 6, \quad \text{Mode} = 10, \quad \text{Range} = 9
\]

---

Part f: 4, 6, 2, 6, 9, 3, 5

#### Mean
\[
\text{Mean} = \frac{\text{Sum of all numbers}}{\text{Total number of values}}
\]
- Sum of the numbers: \(4 + 6 + 2 + 6 + 9 + 3 + 5 = 35\)
- Total number of values: 7
\[
\text{Mean} = \frac{35}{7} = 5
\]

#### Median
- Arranged in ascending order: \(2, 3, 4, 5, 6, 6, 9\)
- Since there are 7 numbers (odd count), the median is the middle number: \(5\)

#### Mode
The number \(6\) appears twice, which is more frequent than any other number.
\[
\text{Mode} = 6
\]

#### Range
- Largest number: \(9\)
- Smallest number: \(2\)
\[
\text{Range} = 9 - 2 = 7
\]

#### Final Answers for Part f:
\[
\text{Mean} = 5, \quad \text{Median} = 5, \quad \text{Mode} = 6, \quad \text{Range} = 7
\]

---

Final Answer Summary:

\[
\boxed{
\begin{array}{l}
\text{a. Mean} = 6, \text{Median} = 7, \text{Mode} = 7, \text{Range} = 6 \\
\text{b. Mean} = 6, \text{Median} = 3, \text{Mode} = 3, \text{Range} = 12 \\
\text{c. Mean} = 1, \text{Median} = 0, \text{Mode} = 0, \text{Range} = 3 \\
\text{d. Mean} \approx 3.83, \text{Median} = 4.5, \text{Mode} = 5, \text{Range} = 5 \\
\text{e. Mean} = 6, \text{Median} = 6, \text{Mode} = 10, \text{Range} = 9 \\
\text{f. Mean} = 5, \text{Median} = 5, \text{Mode} = 6, \text{Range} = 7 \\
\end{array}
}
\]