Monohybrid Cross Worksheet | Slides Genetics | Docsity - Free Printable
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Step-by-step solution for: Monohybrid Cross Worksheet | Slides Genetics | Docsity
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Show Answer Key & Explanations
Step-by-step solution for: Monohybrid Cross Worksheet | Slides Genetics | Docsity
Here's the complete solution to your Monohybrid Cross Worksheet, with clear explanations for each part.
---
## Part A: Vocabulary
Match the definitions on the left with the terms on the right.
1. genotypes made of the same alleles → D. homozygous
*Explanation:* Homozygous means both alleles are identical (e.g., NN or nn).*
2. different forms of genes for a single trait → A. alleles
*Explanation:* Alleles are alternative versions of a gene (e.g., N and n for height).*
3. gene that is always expressed → B. dominant
*Explanation:* Dominant alleles mask recessive ones and are expressed even if only one copy is present.*
4. gene that is expressed only in the homozygous state → E. recessive
*Explanation:* Recessive traits only show up when an organism has two copies (e.g., nn).*
5. genotypes made of two different alleles → C. heterozygous
*Explanation:* Heterozygous means having two different alleles (e.g., Nn).*
✔ Answers:
1. D
2. A
3. B
4. E
5. C
---
## Part B: Punnett Squares
We’re told:
- N = dominant (normal height)
- n = recessive (short height)
You must complete 4 Punnett squares and shade:
- Red: homozygous dominant offspring (NN)
- Green: heterozygous offspring (Nn)
- Unshaded: homozygous recessive (nn)
Let’s fill each square:
---
#### Square 1: Parents = NN × nn
| | N | N |
|-------|-------|-------|
| n | Nn | Nn |
| n | Nn | Nn |
→ All offspring = Nn → Heterozygous → Shade GREEN
---
#### Square 2: Parents = Nn × NN
| | N | n |
|-------|-------|-------|
| N | NN | Nn |
| N | NN | Nn |
→ Offspring: 2 NN (homozygous dominant → RED), 2 Nn (heterozygous → GREEN)
---
#### Square 3: Parents = Nn × Nn
| | N | n |
|-------|-------|-------|
| N | NN | Nn |
| n | Nn | nn |
→ Offspring: 1 NN (RED), 2 Nn (GREEN), 1 nn (unshaded)
---
#### Square 4: Parents = Nn × nn
| | N | n |
|-------|-------|-------|
| n | Nn | nn |
| n | Nn | nn |
→ Offspring: 2 Nn (GREEN), 2 nn (unshaded)
---
✔ Summary of Shading:
- Square 1: All 4 green
- Square 2: 2 red, 2 green
- Square 3: 1 red, 2 green, 1 unshaded
- Square 4: 2 green, 2 unshaded
---
#### a. One guinea pig is Ss and one is ss
Parental genotypes: Ss × ss
Punnett Square:
| | S | s |
|-------|-------|-------|
| s | Ss | ss |
| s | Ss | ss |
→ Offspring: 2 Ss (short hair), 2 ss (long hair)
✔ Expected number of offspring:
- Short hair (SS or Ss) → 2 (Note: SS doesn’t appear here, but Ss does → still short hair)
- Long hair (ss) → 2
---
#### b. Both guinea pigs are heterozygous for short hair → Ss × Ss
Punnett Square:
| | S | s |
|-------|-------|-------|
| S | SS | Ss |
| s | Ss | ss |
→ Offspring: 1 SS, 2 Ss, 1 ss
Phenotype:
- Short hair (SS or Ss) → 3 out of 4 → 3
- Long hair (ss) → 1 out of 4 → 1
✔ Expected number of offspring:
- Short hair → 3
- Long hair → 1
*(Note: Since it says “expected number,” and Punnett squares show ratios, we assume 4 total offspring for simplicity.)*
---
## Part C: Monohybrid Cross Problems
> A homozygous hornless bull (HH) is mated with a homozygous horned cow (hh).
Parents: HH × hh
Punnett Square:
| | H | H |
|-------|-------|-------|
| h | Hh | Hh |
| h | Hh | Hh |
→ All offspring = Hh
✔ Genotype of F1 generation: All Hh
✔ Phenotype of F1 generation: All hornless (since H is dominant)
---
> A man who is a non-roller marries a woman who is heterozygous for tongue rolling.
- Man (non-roller) → genotype rr (must be homozygous recessive)
- Woman (heterozygous roller) → genotype Rr
Cross: rr × Rr
Punnett Square:
| | r | r |
|-------|-------|-------|
| R | Rr | Rr |
| r | rr | rr |
→ Offspring: 2 Rr (rollers), 2 rr (non-rollers)
✔ Genotypic ratio: 1 Rr : 1 rr
✔ Phenotypic ratio: 1 roller : 1 non-roller
---
## ✔ Final Answers Summary:
1. D
2. A
3. B
4. E
5. C
a. Short hair: 2, Long hair: 2
b. Short hair: 3, Long hair: 1
Q8. Genotype: All Hh, Phenotype: All hornless
Q9. Offspring: 50% rollers (Rr), 50% non-rollers (rr)
---
Let me know if you’d like this formatted as a printable answer key or need diagrams!
---
## Part A: Vocabulary
Match the definitions on the left with the terms on the right.
1. genotypes made of the same alleles → D. homozygous
*Explanation:* Homozygous means both alleles are identical (e.g., NN or nn).*
2. different forms of genes for a single trait → A. alleles
*Explanation:* Alleles are alternative versions of a gene (e.g., N and n for height).*
3. gene that is always expressed → B. dominant
*Explanation:* Dominant alleles mask recessive ones and are expressed even if only one copy is present.*
4. gene that is expressed only in the homozygous state → E. recessive
*Explanation:* Recessive traits only show up when an organism has two copies (e.g., nn).*
5. genotypes made of two different alleles → C. heterozygous
*Explanation:* Heterozygous means having two different alleles (e.g., Nn).*
✔ Answers:
1. D
2. A
3. B
4. E
5. C
---
## Part B: Punnett Squares
Question 6: Corn Plants — Normal Height (N) vs. Short Height (n)
We’re told:
- N = dominant (normal height)
- n = recessive (short height)
You must complete 4 Punnett squares and shade:
- Red: homozygous dominant offspring (NN)
- Green: heterozygous offspring (Nn)
- Unshaded: homozygous recessive (nn)
Let’s fill each square:
---
#### Square 1: Parents = NN × nn
| | N | N |
|-------|-------|-------|
| n | Nn | Nn |
| n | Nn | Nn |
→ All offspring = Nn → Heterozygous → Shade GREEN
---
#### Square 2: Parents = Nn × NN
| | N | n |
|-------|-------|-------|
| N | NN | Nn |
| N | NN | Nn |
→ Offspring: 2 NN (homozygous dominant → RED), 2 Nn (heterozygous → GREEN)
---
#### Square 3: Parents = Nn × Nn
| | N | n |
|-------|-------|-------|
| N | NN | Nn |
| n | Nn | nn |
→ Offspring: 1 NN (RED), 2 Nn (GREEN), 1 nn (unshaded)
---
#### Square 4: Parents = Nn × nn
| | N | n |
|-------|-------|-------|
| n | Nn | nn |
| n | Nn | nn |
→ Offspring: 2 Nn (GREEN), 2 nn (unshaded)
---
✔ Summary of Shading:
- Square 1: All 4 green
- Square 2: 2 red, 2 green
- Square 3: 1 red, 2 green, 1 unshaded
- Square 4: 2 green, 2 unshaded
---
Question 7: Guinea Pigs — Short Hair (S) vs. Long Hair (s)
#### a. One guinea pig is Ss and one is ss
Parental genotypes: Ss × ss
Punnett Square:
| | S | s |
|-------|-------|-------|
| s | Ss | ss |
| s | Ss | ss |
→ Offspring: 2 Ss (short hair), 2 ss (long hair)
✔ Expected number of offspring:
- Short hair (SS or Ss) → 2 (Note: SS doesn’t appear here, but Ss does → still short hair)
- Long hair (ss) → 2
---
#### b. Both guinea pigs are heterozygous for short hair → Ss × Ss
Punnett Square:
| | S | s |
|-------|-------|-------|
| S | SS | Ss |
| s | Ss | ss |
→ Offspring: 1 SS, 2 Ss, 1 ss
Phenotype:
- Short hair (SS or Ss) → 3 out of 4 → 3
- Long hair (ss) → 1 out of 4 → 1
✔ Expected number of offspring:
- Short hair → 3
- Long hair → 1
*(Note: Since it says “expected number,” and Punnett squares show ratios, we assume 4 total offspring for simplicity.)*
---
## Part C: Monohybrid Cross Problems
Question 8: Hornless (H) vs. Horned (h) in Cattle
> A homozygous hornless bull (HH) is mated with a homozygous horned cow (hh).
Parents: HH × hh
Punnett Square:
| | H | H |
|-------|-------|-------|
| h | Hh | Hh |
| h | Hh | Hh |
→ All offspring = Hh
✔ Genotype of F1 generation: All Hh
✔ Phenotype of F1 generation: All hornless (since H is dominant)
---
Question 9: Tongue Rolling in Humans — Roller (R) vs. Non-Roller (r)
> A man who is a non-roller marries a woman who is heterozygous for tongue rolling.
- Man (non-roller) → genotype rr (must be homozygous recessive)
- Woman (heterozygous roller) → genotype Rr
Cross: rr × Rr
Punnett Square:
| | r | r |
|-------|-------|-------|
| R | Rr | Rr |
| r | rr | rr |
→ Offspring: 2 Rr (rollers), 2 rr (non-rollers)
✔ Genotypic ratio: 1 Rr : 1 rr
✔ Phenotypic ratio: 1 roller : 1 non-roller
---
## ✔ Final Answers Summary:
Part A:
1. D
2. A
3. B
4. E
5. C
Part B – Q6: (Shading as explained above)
Part B – Q7:
a. Short hair: 2, Long hair: 2
b. Short hair: 3, Long hair: 1
Part C:
Q8. Genotype: All Hh, Phenotype: All hornless
Q9. Offspring: 50% rollers (Rr), 50% non-rollers (rr)
---
Let me know if you’d like this formatted as a printable answer key or need diagrams!
Parent Tip: Review the logic above to help your child master the concept of monohybrid crosses worksheet.