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Grade 6 integers division worksheet with missing number problems.

Dividing integers worksheet for Grade 6 students with 16 problems to find missing numbers in division equations.

Dividing integers worksheet for Grade 6 students with 16 problems to find missing numbers in division equations.

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Show Answer Key & Explanations Step-by-step solution for: Grade 6 Integers Worksheets: Dividing integers (missing numbers ...

Problem: Solving the Dividing Integers Worksheet



The worksheet asks us to find the missing numbers in each equation involving division and addition/subtraction of integers. Let's solve each problem step by step.

---

#### 1) \( \_\_\_ \div (-6) = (-10) \)

We need to find a number \( x \) such that:
\[ x \div (-6) = -10 \]

This can be rewritten as:
\[ x = -10 \times (-6) \]

Multiplying two negative numbers gives a positive result:
\[ x = 60 \]

Answer: \( 60 \)

---

#### 2) \( 44 \div \_\_\_ = (-4) \)

We need to find a number \( y \) such that:
\[ 44 \div y = -4 \]

This can be rewritten as:
\[ y = 44 \div (-4) \]

Dividing a positive number by a negative number gives a negative result:
\[ y = -11 \]

Answer: \( -11 \)

---

#### 3) \( 24 \div \_\_\_ = (-6) \)

We need to find a number \( z \) such that:
\[ 24 \div z = -6 \]

This can be rewritten as:
\[ z = 24 \div (-6) \]

Dividing a positive number by a negative number gives a negative result:
\[ z = -4 \]

Answer: \( -4 \)

---

#### 4) \( 48 \div \_\_\_ = 4 \)

We need to find a number \( w \) such that:
\[ 48 \div w = 4 \]

This can be rewritten as:
\[ w = 48 \div 4 \]

Dividing two positive numbers gives a positive result:
\[ w = 12 \]

Answer: \( 12 \)

---

#### 5) \( (-72) \div \_\_\_ = (-9) \)

We need to find a number \( a \) such that:
\[ (-72) \div a = -9 \]

This can be rewritten as:
\[ a = (-72) \div (-9) \]

Dividing two negative numbers gives a positive result:
\[ a = 8 \]

Answer: \( 8 \)

---

#### 6) \( \_\_\_ \div 12 = (-6) \)

We need to find a number \( b \) such that:
\[ b \div 12 = -6 \]

This can be rewritten as:
\[ b = -6 \times 12 \]

Multiplying a negative number by a positive number gives a negative result:
\[ b = -72 \]

Answer: \( -72 \)

---

#### 7) \( (-48) \div \_\_\_ = 8 \)

We need to find a number \( c \) such that:
\[ (-48) \div c = 8 \]

This can be rewritten as:
\[ c = (-48) \div 8 \]

Dividing a negative number by a positive number gives a negative result:
\[ c = -6 \]

Answer: \( -6 \)

---

#### 8) \( 50 \div \_\_\_ = 5 \)

We need to find a number \( d \) such that:
\[ 50 \div d = 5 \]

This can be rewritten as:
\[ d = 50 \div 5 \]

Dividing two positive numbers gives a positive result:
\[ d = 10 \]

Answer: \( 10 \)

---

#### 9) \( \_\_\_ + 11 = (-6) \)

We need to find a number \( e \) such that:
\[ e + 11 = -6 \]

This can be rewritten as:
\[ e = -6 - 11 \]

Subtracting a positive number from a negative number:
\[ e = -17 \]

Answer: \( -17 \)

---

#### 10) \( \_\_\_ + (-11) = 5 \)

We need to find a number \( f \) such that:
\[ f + (-11) = 5 \]

This can be rewritten as:
\[ f - 11 = 5 \]

Adding 11 to both sides:
\[ f = 5 + 11 \]
\[ f = 16 \]

Answer: \( 16 \)

---

#### 11) \( (-10) + \_\_\_ = 5 \)

We need to find a number \( g \) such that:
\[ (-10) + g = 5 \]

This can be rewritten as:
\[ g = 5 - (-10) \]

Subtracting a negative number is equivalent to adding:
\[ g = 5 + 10 \]
\[ g = 15 \]

Answer: \( 15 \)

---

#### 12) \( \_\_\_ + 3 = 9 \)

We need to find a number \( h \) such that:
\[ h + 3 = 9 \]

This can be rewritten as:
\[ h = 9 - 3 \]
\[ h = 6 \]

Answer: \( 6 \)

---

#### 13) \( (-15) + \_\_\_ = 3 \)

We need to find a number \( i \) such that:
\[ (-15) + i = 3 \]

This can be rewritten as:
\[ i = 3 - (-15) \]

Subtracting a negative number is equivalent to adding:
\[ i = 3 + 15 \]
\[ i = 18 \]

Answer: \( 18 \)

---

#### 14) \( \_\_\_ + (-4) = 6 \)

We need to find a number \( j \) such that:
\[ j + (-4) = 6 \]

This can be rewritten as:
\[ j - 4 = 6 \]

Adding 4 to both sides:
\[ j = 6 + 4 \]
\[ j = 10 \]

Answer: \( 10 \)

---

#### 15) \( \_\_\_ + (-2) = (-6) \)

We need to find a number \( k \) such that:
\[ k + (-2) = -6 \]

This can be rewritten as:
\[ k - 2 = -6 \]

Adding 2 to both sides:
\[ k = -6 + 2 \]
\[ k = -4 \]

Answer: \( -4 \)

---

#### 16) \( \_\_\_ + (-6) = (-7) \)

We need to find a number \( l \) such that:
\[ l + (-6) = -7 \]

This can be rewritten as:
\[ l - 6 = -7 \]

Adding 6 to both sides:
\[ l = -7 + 6 \]
\[ l = -1 \]

Answer: \( -1 \)

---

Final Answers:


\[
\boxed{
\begin{array}{ll}
1) & 60 \\
2) & -11 \\
3) & -4 \\
4) & 12 \\
5) & 8 \\
6) & -72 \\
7) & -6 \\
8) & 10 \\
9) & -17 \\
10) & 16 \\
11) & 15 \\
12) & 6 \\
13) & 18 \\
14) & 10 \\
15) & -4 \\
16) & -1 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of multiply divide integers worksheet.
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