Students can practice multiplying fractions and mixed numbers while decoding this funny mummy riddle.
Math riddle worksheet for multiplying fractions titled Why Was The Mummy So Tense with a cartoon mummy.
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Show Answer Key & Explanations
Step-by-step solution for: 30 Free Halloween Fraction Worksheet Collection For Students
Let's solve this fun math riddle: "Why was the mummy so tense?"
We need to solve each multiplication problem, find the product, and then match it to the correct box at the bottom. Each letter corresponds to a problem, and we'll place that letter next to the correct answer.
---
We’ll go through each one:
---
A: $ \frac{1}{2} \times 5 = \frac{5}{2} = 2\frac{1}{2} $
✔ Match: $2\frac{1}{2}$
---
H: $ \frac{3}{4} \times 2 = \frac{6}{4} = \frac{3}{2} = 1\frac{1}{2} $
✔ Match: $1\frac{1}{2}$
---
P: $ 7 \times \frac{4}{7} = \frac{28}{7} = 4 $
✔ Match: 4
---
B: $ \frac{11}{12} \times 2 = \frac{22}{12} = \frac{11}{6} = 1\frac{5}{6} $
✔ Match: $1\frac{5}{6}$
---
U: $ \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} $
✔ Match: $\frac{1}{4}$
---
E: $ \frac{3}{5} \times \frac{2}{3} = \frac{6}{15} = \frac{2}{5} $
✔ Match: $\frac{2}{5}$
---
U: $ \frac{2}{7} \times \frac{3}{4} = \frac{6}{28} = \frac{3}{14} $
✔ Match: $\frac{3}{14}$
---
E: $ \frac{9}{10} \times \frac{20}{27} = \frac{180}{270} = \frac{2}{3} $
✔ Match: $\frac{2}{3}$
---
W: $ 1\frac{1}{4} \times \frac{1}{2} = \frac{5}{4} \times \frac{1}{2} = \frac{5}{8} $
✔ Match: $\frac{5}{8}$
---
L: $ 1\frac{2}{5} \times 2 = \frac{7}{5} \times 2 = \frac{14}{5} = 2\frac{4}{5} $
✔ Match: $2\frac{4}{5}$
---
W: $ 4 \times 2\frac{2}{3} = 4 \times \frac{8}{3} = \frac{32}{3} = 10\frac{2}{3} $
✔ Match: $10\frac{2}{3}$
---
C: $ 3\frac{2}{7} \times \frac{1}{5} = \frac{23}{7} \times \frac{1}{5} = \frac{23}{35} $
✔ Match: $\frac{23}{35}$
---
S: $ 4\frac{1}{2} \times 1\frac{1}{3} = \frac{9}{2} \times \frac{4}{3} = \frac{36}{6} = 6 $
✔ Match: 6
---
L: $ 1\frac{5}{6} \times 2\frac{2}{5} = \frac{11}{6} \times \frac{12}{5} = \frac{132}{30} = \frac{22}{5} = 4\frac{2}{5} $
✔ Match: $4\frac{2}{5}$
---
A: $ 3\frac{2}{3} \times 2\frac{1}{4} = \frac{11}{3} \times \frac{9}{4} = \frac{99}{12} = \frac{33}{4} = 8\frac{1}{4} $
✔ Match: $8\frac{1}{4}$
---
U: $ 3\frac{2}{5} \times 1\frac{1}{2} = \frac{17}{5} \times \frac{3}{2} = \frac{51}{10} = 5\frac{1}{10} $
✔ Match: $5\frac{1}{10}$
---
D: $ 3 \times 1\frac{1}{4} \times 2\frac{2}{3} = 3 \times \frac{5}{4} \times \frac{8}{3} $
First: $3 \times \frac{5}{4} = \frac{15}{4}$
Then: $\frac{15}{4} \times \frac{8}{3} = \frac{120}{12} = 10$
✔ Match: 10
---
E: $ \frac{7}{8} \times 1\frac{1}{7} = \frac{7}{8} \times \frac{8}{7} = 1 $
✔ Match: 1
---
S: $ 1\frac{1}{3} \times \frac{1}{2} \times 3 = \frac{4}{3} \times \frac{1}{2} \times 3 $
First: $ \frac{4}{3} \times \frac{1}{2} = \frac{4}{6} = \frac{2}{3} $
Then: $ \frac{2}{3} \times 3 = 2 $
✔ Match: 2
---
N: $ 1\frac{3}{4} \times \frac{1}{4} \times \frac{1}{2} = \frac{7}{4} \times \frac{1}{4} \times \frac{1}{2} = \frac{7}{32} $
✔ Match: $\frac{7}{32}$
---
A: $ 1\frac{2}{9} \times 0 \times \frac{27}{31} = 0 $ (Any number × 0 = 0)
✔ Match: 0
---
O: $ 2\frac{2}{5} \times 2 \times \frac{1}{3} = \frac{12}{5} \times 2 \times \frac{1}{3} $
First: $ \frac{12}{5} \times 2 = \frac{24}{5} $
Then: $ \frac{24}{5} \times \frac{1}{3} = \frac{24}{15} = \frac{8}{5} = 1\frac{3}{5} $
✔ Match: $1\frac{3}{5}$
---
Now, let’s assign each letter to its result:
| Answer | Letter(s) |
|------------------|-----------|
| $1\frac{5}{6}$ | B |
| $\frac{2}{3}$ | E |
| $\frac{23}{35}$ | C |
| $2\frac{1}{2}$ | A |
| $\frac{1}{4}$ | U |
| $\frac{2}{5}$ | E |
| $\frac{3}{14}$ | U |
| $\frac{5}{8}$ | W |
| $2\frac{4}{5}$ | L |
| $10\frac{2}{3}$ | W |
| 6 | S |
| $4\frac{2}{5}$ | L |
| $8\frac{1}{4}$ | A |
| $5\frac{1}{10}$ | U |
| 10 | D |
| 1 | E |
| 2 | S |
| $\frac{7}{32}$ | N |
| 0 | A |
| $1\frac{3}{5}$ | O |
---
Now, look at the grid at the bottom:
```
[1 5/6] [2/3] [23/35] [2 1/2] [1/4] [6] [1] [1 1/2] [2/5] [5/8] [8 1/4] [2]
[0] [2 4/5] [4 2/5] [10 2/3] [1 3/5] [3/14] [7/32] [10] [5 1/10] [4]
```
We now assign the letters to each box:
- $1\frac{5}{6}$ → B
- $\frac{2}{3}$ → E
- $\frac{23}{35}$ → C
- $2\frac{1}{2}$ → A
- $\frac{1}{4}$ → U
- 6 → S
- 1 → E
- $1\frac{1}{2}$ → H
- $\frac{2}{5}$ → E
- $\frac{5}{8}$ → W
- $8\frac{1}{4}$ → A
- 2 → S
- 0 → A
- $2\frac{4}{5}$ → L
- $4\frac{2}{5}$ → L
- $10\frac{2}{3}$ → W
- $1\frac{3}{5}$ → O
- $\frac{3}{14}$ → U
- $\frac{7}{32}$ → N
- 10 → D
- $5\frac{1}{10}$ → U
- 4 → P
Now, write the letters in order of the boxes:
Row 1:
1. $1\frac{5}{6}$ → B
2. $\frac{2}{3}$ → E
3. $\frac{23}{35}$ → C
4. $2\frac{1}{2}$ → A
5. $\frac{1}{4}$ → U
6. 6 → S
7. 1 → E
8. $1\frac{1}{2}$ → H
9. $\frac{2}{5}$ → E
10. $\frac{5}{8}$ → W
11. $8\frac{1}{4}$ → A
12. 2 → S
Row 2:
1. 0 → A
2. $2\frac{4}{5}$ → L
3. $4\frac{2}{5}$ → L
4. $10\frac{2}{3}$ → W
5. $1\frac{3}{5}$ → O
6. $\frac{3}{14}$ → U
7. $\frac{7}{32}$ → N
8. 10 → D
9. $5\frac{1}{10}$ → U
10. 4 → P
Now read all the letters in order:
B E C A U S E H E W A S L L W O U N D U P
Wait — that seems off. Let's check for errors.
But wait — maybe we need to rearrange or perhaps there are duplicates?
Wait — look at the answer slots: they are not in order of the problems. We must place the letter next to the product.
So the bottom grid has the products listed, and we place the letter corresponding to that product next to it.
So we should just list the letters in the same order as the answers appear in the grid.
Let’s re-express the grid with letters:
```
[1 5/6] → B
[2/3] → E
[23/35] → C
[2 1/2] → A
[1/4] → U
[6] → S
[1] → E
[1 1/2] → H
[2/5] → E
[5/8] → W
[8 1/4] → A
[2] → S
[0] → A
[2 4/5] → L
[4 2/5] → L
[10 2/3] → W
[1 3/5] → O
[3/14] → U
[7/32] → N
[10] → D
[5 1/10] → U
[4] → P
```
Now, reading the letters from left to right, top to bottom:
B E C A U S E H E W A S L L W O U N D U P
That’s not making sense yet.
Wait — "BECAUSE HE WAS LL WOUND UP"? That doesn’t make sense.
Wait — maybe it's "BECAUSE HE WAS ALL WOUND UP"?
Ah! There’s a typo: LL should be ALL.
But we have two Ls — from $2\frac{4}{5}$ and $4\frac{2}{5}$ both being L, but only one L in the word?
Wait — let’s check:
- $2\frac{4}{5}$ → L
- $4\frac{2}{5}$ → L
So two Ls — but “all” needs three letters.
Wait — no: "All wound up" — that would be A L L W O U N D U P
But we have:
- $2\frac{4}{5}$ → L
- $4\frac{2}{5}$ → L
So two Ls — good.
And before that: $0$ → A, then $2\frac{4}{5}$ → L, $4\frac{2}{5}$ → L → so A L L
Then $10\frac{2}{3}$ → W
Then $1\frac{3}{5}$ → O
Then $\frac{3}{14}$ → U
Then $\frac{7}{32}$ → N
Then $10$ → D
Then $5\frac{1}{10}$ → U
Then $4$ → P
So putting it together:
From the second row:
- 0 → A
- $2\frac{4}{5}$ → L
- $4\frac{2}{5}$ → L
- $10\frac{2}{3}$ → W
- $1\frac{3}{5}$ → O
- $\frac{3}{14}$ → U
- $\frac{7}{32}$ → N
- $10$ → D
- $5\frac{1}{10}$ → U
- $4$ → P
→ A L L W O U N D U P
Now first row:
- $1\frac{5}{6}$ → B
- $\frac{2}{3}$ → E
- $\frac{23}{35}$ → C
- $2\frac{1}{2}$ → A
- $\frac{1}{4}$ → U
- 6 → S
- 1 → E
- $1\frac{1}{2}$ → H
- $\frac{2}{5}$ → E
- $\frac{5}{8}$ → W
- $8\frac{1}{4}$ → A
- 2 → S
→ B E C A U S E H E W A S
Now combine:
BECAUSE HE WAS ALL WOUND UP
Yes!
So the full phrase is:
> Because he was all wound up.
---
Because he was all wound up.
This is a pun on "wound up" meaning both "wrapped in bandages" (like a mummy) and "nervous/tense".
---
We solved all the fraction multiplication problems, matched the results to the correct boxes, and revealed the joke:
> WHY WAS THE MUMMY SO TENSE?
> Because he was all wound up. 😄
We need to solve each multiplication problem, find the product, and then match it to the correct box at the bottom. Each letter corresponds to a problem, and we'll place that letter next to the correct answer.
---
Step 1: Solve Each Problem
We’ll go through each one:
---
A: $ \frac{1}{2} \times 5 = \frac{5}{2} = 2\frac{1}{2} $
✔ Match: $2\frac{1}{2}$
---
H: $ \frac{3}{4} \times 2 = \frac{6}{4} = \frac{3}{2} = 1\frac{1}{2} $
✔ Match: $1\frac{1}{2}$
---
P: $ 7 \times \frac{4}{7} = \frac{28}{7} = 4 $
✔ Match: 4
---
B: $ \frac{11}{12} \times 2 = \frac{22}{12} = \frac{11}{6} = 1\frac{5}{6} $
✔ Match: $1\frac{5}{6}$
---
U: $ \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} $
✔ Match: $\frac{1}{4}$
---
E: $ \frac{3}{5} \times \frac{2}{3} = \frac{6}{15} = \frac{2}{5} $
✔ Match: $\frac{2}{5}$
---
U: $ \frac{2}{7} \times \frac{3}{4} = \frac{6}{28} = \frac{3}{14} $
✔ Match: $\frac{3}{14}$
---
E: $ \frac{9}{10} \times \frac{20}{27} = \frac{180}{270} = \frac{2}{3} $
✔ Match: $\frac{2}{3}$
---
W: $ 1\frac{1}{4} \times \frac{1}{2} = \frac{5}{4} \times \frac{1}{2} = \frac{5}{8} $
✔ Match: $\frac{5}{8}$
---
L: $ 1\frac{2}{5} \times 2 = \frac{7}{5} \times 2 = \frac{14}{5} = 2\frac{4}{5} $
✔ Match: $2\frac{4}{5}$
---
W: $ 4 \times 2\frac{2}{3} = 4 \times \frac{8}{3} = \frac{32}{3} = 10\frac{2}{3} $
✔ Match: $10\frac{2}{3}$
---
C: $ 3\frac{2}{7} \times \frac{1}{5} = \frac{23}{7} \times \frac{1}{5} = \frac{23}{35} $
✔ Match: $\frac{23}{35}$
---
S: $ 4\frac{1}{2} \times 1\frac{1}{3} = \frac{9}{2} \times \frac{4}{3} = \frac{36}{6} = 6 $
✔ Match: 6
---
L: $ 1\frac{5}{6} \times 2\frac{2}{5} = \frac{11}{6} \times \frac{12}{5} = \frac{132}{30} = \frac{22}{5} = 4\frac{2}{5} $
✔ Match: $4\frac{2}{5}$
---
A: $ 3\frac{2}{3} \times 2\frac{1}{4} = \frac{11}{3} \times \frac{9}{4} = \frac{99}{12} = \frac{33}{4} = 8\frac{1}{4} $
✔ Match: $8\frac{1}{4}$
---
U: $ 3\frac{2}{5} \times 1\frac{1}{2} = \frac{17}{5} \times \frac{3}{2} = \frac{51}{10} = 5\frac{1}{10} $
✔ Match: $5\frac{1}{10}$
---
D: $ 3 \times 1\frac{1}{4} \times 2\frac{2}{3} = 3 \times \frac{5}{4} \times \frac{8}{3} $
First: $3 \times \frac{5}{4} = \frac{15}{4}$
Then: $\frac{15}{4} \times \frac{8}{3} = \frac{120}{12} = 10$
✔ Match: 10
---
E: $ \frac{7}{8} \times 1\frac{1}{7} = \frac{7}{8} \times \frac{8}{7} = 1 $
✔ Match: 1
---
S: $ 1\frac{1}{3} \times \frac{1}{2} \times 3 = \frac{4}{3} \times \frac{1}{2} \times 3 $
First: $ \frac{4}{3} \times \frac{1}{2} = \frac{4}{6} = \frac{2}{3} $
Then: $ \frac{2}{3} \times 3 = 2 $
✔ Match: 2
---
N: $ 1\frac{3}{4} \times \frac{1}{4} \times \frac{1}{2} = \frac{7}{4} \times \frac{1}{4} \times \frac{1}{2} = \frac{7}{32} $
✔ Match: $\frac{7}{32}$
---
A: $ 1\frac{2}{9} \times 0 \times \frac{27}{31} = 0 $ (Any number × 0 = 0)
✔ Match: 0
---
O: $ 2\frac{2}{5} \times 2 \times \frac{1}{3} = \frac{12}{5} \times 2 \times \frac{1}{3} $
First: $ \frac{12}{5} \times 2 = \frac{24}{5} $
Then: $ \frac{24}{5} \times \frac{1}{3} = \frac{24}{15} = \frac{8}{5} = 1\frac{3}{5} $
✔ Match: $1\frac{3}{5}$
---
Step 2: Match Letters to Answers
Now, let’s assign each letter to its result:
| Answer | Letter(s) |
|------------------|-----------|
| $1\frac{5}{6}$ | B |
| $\frac{2}{3}$ | E |
| $\frac{23}{35}$ | C |
| $2\frac{1}{2}$ | A |
| $\frac{1}{4}$ | U |
| $\frac{2}{5}$ | E |
| $\frac{3}{14}$ | U |
| $\frac{5}{8}$ | W |
| $2\frac{4}{5}$ | L |
| $10\frac{2}{3}$ | W |
| 6 | S |
| $4\frac{2}{5}$ | L |
| $8\frac{1}{4}$ | A |
| $5\frac{1}{10}$ | U |
| 10 | D |
| 1 | E |
| 2 | S |
| $\frac{7}{32}$ | N |
| 0 | A |
| $1\frac{3}{5}$ | O |
---
Step 3: Fill in the Bottom Grid
Now, look at the grid at the bottom:
```
[1 5/6] [2/3] [23/35] [2 1/2] [1/4] [6] [1] [1 1/2] [2/5] [5/8] [8 1/4] [2]
[0] [2 4/5] [4 2/5] [10 2/3] [1 3/5] [3/14] [7/32] [10] [5 1/10] [4]
```
We now assign the letters to each box:
- $1\frac{5}{6}$ → B
- $\frac{2}{3}$ → E
- $\frac{23}{35}$ → C
- $2\frac{1}{2}$ → A
- $\frac{1}{4}$ → U
- 6 → S
- 1 → E
- $1\frac{1}{2}$ → H
- $\frac{2}{5}$ → E
- $\frac{5}{8}$ → W
- $8\frac{1}{4}$ → A
- 2 → S
- 0 → A
- $2\frac{4}{5}$ → L
- $4\frac{2}{5}$ → L
- $10\frac{2}{3}$ → W
- $1\frac{3}{5}$ → O
- $\frac{3}{14}$ → U
- $\frac{7}{32}$ → N
- 10 → D
- $5\frac{1}{10}$ → U
- 4 → P
Now, write the letters in order of the boxes:
Row 1:
1. $1\frac{5}{6}$ → B
2. $\frac{2}{3}$ → E
3. $\frac{23}{35}$ → C
4. $2\frac{1}{2}$ → A
5. $\frac{1}{4}$ → U
6. 6 → S
7. 1 → E
8. $1\frac{1}{2}$ → H
9. $\frac{2}{5}$ → E
10. $\frac{5}{8}$ → W
11. $8\frac{1}{4}$ → A
12. 2 → S
Row 2:
1. 0 → A
2. $2\frac{4}{5}$ → L
3. $4\frac{2}{5}$ → L
4. $10\frac{2}{3}$ → W
5. $1\frac{3}{5}$ → O
6. $\frac{3}{14}$ → U
7. $\frac{7}{32}$ → N
8. 10 → D
9. $5\frac{1}{10}$ → U
10. 4 → P
Now read all the letters in order:
B E C A U S E H E W A S L L W O U N D U P
Wait — that seems off. Let's check for errors.
But wait — maybe we need to rearrange or perhaps there are duplicates?
Wait — look at the answer slots: they are not in order of the problems. We must place the letter next to the product.
So the bottom grid has the products listed, and we place the letter corresponding to that product next to it.
So we should just list the letters in the same order as the answers appear in the grid.
Let’s re-express the grid with letters:
Final Answer Grid:
```
[1 5/6] → B
[2/3] → E
[23/35] → C
[2 1/2] → A
[1/4] → U
[6] → S
[1] → E
[1 1/2] → H
[2/5] → E
[5/8] → W
[8 1/4] → A
[2] → S
[0] → A
[2 4/5] → L
[4 2/5] → L
[10 2/3] → W
[1 3/5] → O
[3/14] → U
[7/32] → N
[10] → D
[5 1/10] → U
[4] → P
```
Now, reading the letters from left to right, top to bottom:
B E C A U S E H E W A S L L W O U N D U P
That’s not making sense yet.
Wait — "BECAUSE HE WAS LL WOUND UP"? That doesn’t make sense.
Wait — maybe it's "BECAUSE HE WAS ALL WOUND UP"?
Ah! There’s a typo: LL should be ALL.
But we have two Ls — from $2\frac{4}{5}$ and $4\frac{2}{5}$ both being L, but only one L in the word?
Wait — let’s check:
- $2\frac{4}{5}$ → L
- $4\frac{2}{5}$ → L
So two Ls — but “all” needs three letters.
Wait — no: "All wound up" — that would be A L L W O U N D U P
But we have:
- $2\frac{4}{5}$ → L
- $4\frac{2}{5}$ → L
So two Ls — good.
And before that: $0$ → A, then $2\frac{4}{5}$ → L, $4\frac{2}{5}$ → L → so A L L
Then $10\frac{2}{3}$ → W
Then $1\frac{3}{5}$ → O
Then $\frac{3}{14}$ → U
Then $\frac{7}{32}$ → N
Then $10$ → D
Then $5\frac{1}{10}$ → U
Then $4$ → P
So putting it together:
From the second row:
- 0 → A
- $2\frac{4}{5}$ → L
- $4\frac{2}{5}$ → L
- $10\frac{2}{3}$ → W
- $1\frac{3}{5}$ → O
- $\frac{3}{14}$ → U
- $\frac{7}{32}$ → N
- $10$ → D
- $5\frac{1}{10}$ → U
- $4$ → P
→ A L L W O U N D U P
Now first row:
- $1\frac{5}{6}$ → B
- $\frac{2}{3}$ → E
- $\frac{23}{35}$ → C
- $2\frac{1}{2}$ → A
- $\frac{1}{4}$ → U
- 6 → S
- 1 → E
- $1\frac{1}{2}$ → H
- $\frac{2}{5}$ → E
- $\frac{5}{8}$ → W
- $8\frac{1}{4}$ → A
- 2 → S
→ B E C A U S E H E W A S
Now combine:
BECAUSE HE WAS ALL WOUND UP
Yes!
So the full phrase is:
> Because he was all wound up.
---
✔ Final Answer:
Because he was all wound up.
This is a pun on "wound up" meaning both "wrapped in bandages" (like a mummy) and "nervous/tense".
---
Summary:
We solved all the fraction multiplication problems, matched the results to the correct boxes, and revealed the joke:
> WHY WAS THE MUMMY SO TENSE?
> Because he was all wound up. 😄
Parent Tip: Review the logic above to help your child master the concept of multiplying fractions by whole numbers worksheet riddle 32.