Alkanes and Cycloalkanes - ppt video online download - Free Printable

To solve the problem of giving IUPAC names for the given cycloalkanes, we need to follow the systematic rules of IUPAC nomenclature. Here's a step-by-step explanation for each compound:

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(a)


#### Analysis:
- The parent ring is a cyclohexane.
- There are two methyl groups attached to the ring.
- The positions of the substituents must be numbered to give the lowest possible numbering.

#### Steps:
1. Identify the parent ring: Cyclohexane.
2. Identify the substituents: Two methyl groups.
3. Number the ring to give the lowest locants for the substituents. Starting from any position, the two methyl groups are at C-1 and C-2.

#### IUPAC Name:
1,2-Dimethylcyclohexane

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(b)


#### Analysis:
- The parent ring is a cyclopentane.
- There is one propyl group attached to the ring.
- The position of the substituent must be specified.

#### Steps:
1. Identify the parent ring: Cyclopentane.
2. Identify the substituent: Propyl group.
3. Number the ring to give the lowest locant for the propyl group. The propyl group is at C-1.

#### IUPAC Name:
1-Propylcyclopentane

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(c)


#### Analysis:
- The parent ring is a cyclobutane.
- There is one sec-butyl group attached to the ring.
- The position of the substituent must be specified.

#### Steps:
1. Identify the parent ring: Cyclobutane.
2. Identify the substituent: Sec-butyl group (CH₃CH(CH₃)CH₂–).
3. Number the ring to give the lowest locant for the substituent. The sec-butyl group is at C-1.

#### IUPAC Name:
1-Sec-butylcyclobutane

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(d)


#### Analysis:
- The parent ring is a cycloheptane.
- There is one ethyl group and one bromine atom attached to the ring.
- The positions of the substituents must be specified to give the lowest possible numbering.

#### Steps:
1. Identify the parent ring: Cycloheptane.
2. Identify the substituents: Ethyl group and bromine atom.
3. Number the ring to give the lowest locants for the substituents. Starting from any position, the ethyl group is at C-1 and the bromine atom is at C-3.

#### IUPAC Name:
1-Ethyl-3-bromocycloheptane

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(e)


#### Analysis:
- The parent ring is a cyclohexane.
- There are two alkyl substituents: One methyl group and one isopropyl group.
- The positions of the substituents must be specified to give the lowest possible numbering.

#### Steps:
1. Identify the parent ring: Cyclohexane.
2. Identify the substituents: Methyl group and isopropyl group.
3. Number the ring to give the lowest locants for the substituents. Starting from any position, the methyl group is at C-1 and the isopropyl group is at C-2.

#### IUPAC Name:
1-Methyl-2-isopropylcyclohexane

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(f)


#### Analysis:
- The parent ring is a cyclohexane.
- There are three substituents: One bromine atom, one tert-butyl group, and one isopropyl group.
- The positions of the substituents must be specified to give the lowest possible numbering.

#### Steps:
1. Identify the parent ring: Cyclohexane.
2. Identify the substituents: Bromine atom, tert-butyl group (C(CH₃)₃), and isopropyl group (CH(CH₃)₂).
3. Number the ring to give the lowest locants for the substituents. Starting from any position, the bromine atom is at C-1, the tert-butyl group is at C-2, and the isopropyl group is at C-3.

#### IUPAC Name:
1-Bromo-2-tert-butyl-3-isopropylcyclohexane

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Final Answers:

\[
\boxed{
\begin{array}{ll}
(a) & 1,2-\text{Dimethylcyclohexane} \\
(b) & 1-\text{Propylcyclopentane} \\
(c) & 1-\text{Sec-butylcyclobutane} \\
(d) & 1-\text{Ethyl-3-bromocycloheptane} \\
(e) & 1-\text{Methyl-2-isopropylcyclohexane} \\
(f) & 1-\text{Bromo-2-tert-butyl-3-isopropylcyclohexane}
\end{array}
}
\]