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Nuclear decay worksheet featuring problems on alpha and beta particle emissions with blank spaces for writing nuclear equations.

Worksheet titled "Nuclear Decay" with exercises on alpha and beta particle emissions, requiring students to write complete nuclear equations.

Worksheet titled "Nuclear Decay" with exercises on alpha and beta particle emissions, requiring students to write complete nuclear equations.

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You’ve uploaded a worksheet titled “Nuclear Decay” that asks you to complete nuclear equations for three types of radioactive decay:

1. Alpha particle emission (α-decay)
2. Beta particle emission (β⁻-decay)
3. Electron capture (EC)

I’ll solve each section step-by-step and explain the reasoning.

---

## 🔹 SECTION 1: ALPHA PARTICLE EMISSION (α-decay)

In alpha decay, an atom emits an alpha particle, which is a helium nucleus:
⁴₂He (mass number = 4, atomic number = 2)

So, when a nucleus emits an alpha particle:
- Its mass number decreases by 4
- Its atomic number decreases by 2

---

1. ²³⁰₉₀Th → ___ + ___



- Mass: 230 – 4 = 226
- Atomic number: 90 – 2 = 88
- Element with Z=88 is Radium (Ra)

Answer:
²³⁰₉₀Th → ²²⁶₈₈Ra + ⁴₂He

---

2. ²³⁸₉₂U → ___ + ___



- Mass: 238 – 4 = 234
- Atomic number: 92 – 2 = 90
- Element with Z=90 is Thorium (Th)

Answer:
²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He

---

3. ²³⁸₉₈U? Wait — typo? Probably meant ²³⁸₉₂U again? But written as ²³⁸₉₈U? That doesn’t make sense — Uranium is always Z=92.



Wait — looking at your image, it says:

> ²³⁸₉₈U → ___ + ___

That’s likely a typo — uranium is Z=92, not 98. Element 98 is Cf (Californium).

But let’s assume it's ²³⁸₉₂U (common isotope), since ²³⁸₉₈U doesn’t exist naturally.

If it’s really ²³⁸₉₈Cf (Californium-238), then:

- Mass: 238 – 4 = 234
- Atomic number: 98 – 2 = 96
- Element 96 is Curium (Cm)

So if it’s Cf:
²³⁸₉₈Cf → ²³⁴₉₆Cm + ⁴₂He

BUT — given context, this is probably a typo and should be ²³⁸₉₂U → same as #2.

However, since you wrote “²³⁸₉₈U”, I’ll go with Cf to match the subscript.

Final answer (assuming typo corrected to Cf):
²³⁸₉₈Cf → ²³⁴₉₆Cm + ⁴₂He

---

4. ²²²₈₆Rn → ___ + ___



- Mass: 222 – 4 = 218
- Atomic number: 86 – 2 = 84
- Element 84 is Polonium (Po)

Answer:
²²²₈₆Rn → ²¹⁸₈₄Po + ⁴₂He

---

## 🔹 SECTION 2: BETA PARTICLE EMISSION (β⁻-decay)

In beta-minus decay, a neutron turns into a proton, emitting an electron (beta particle):
⁰₋₁e or ⁰₋₁β

So:
- Mass number stays the same
- Atomic number increases by 1

---

1. ¹⁴₆C → ___ + ___



- Mass: 14 (unchanged)
- Atomic number: 6 + 1 = 7
- Element 7 is Nitrogen (N)

Answer:
¹⁴₆C → ¹⁴₇N + ⁰₋₁e

---

2. ⁹⁰₃₈Sr → ___ + ___



- Mass: 90
- Atomic number: 38 + 1 = 39
- Element 39 is Yttrium (Y)

Answer:
⁹⁰₃₈Sr → ⁹⁰₃₉Y + ⁰₋₁e

---

3. ⁴⁰₁₉K → ___ + ___



- Mass: 40
- Atomic number: 19 + 1 = 20
- Element 20 is Calcium (Ca)

Answer:
⁴⁰₁₉K → ⁴⁰₂₀Ca + ⁰₋₁e

---

4. ¹³₇N → ___ + ___



- Mass: 13
- Atomic number: 7 + 1 = 8
- Element 8 is Oxygen (O)

Answer:
¹³₇N → ¹³₈O + ⁰₋₁e

*(Note: Nitrogen-13 actually decays via positron emission, but per instructions, we’re doing beta-minus decay — so this is hypothetical.)*

---

## 🔹 SECTION 3: ELECTRON CAPTURE (EC)

In electron capture, the nucleus captures an inner-shell electron:
⁰₋₁e is absorbed

So:
- Mass number stays the same
- Atomic number decreases by 1

It’s like the reverse of beta-minus decay.

---

1. ¹⁹⁶₇₈Pt + ___ → ___



- Mass: 196 (unchanged)
- Atomic number: 78 – 1 = 77
- Element 77 is Iridium (Ir)

Answer:
¹⁹⁶₇₈Pt + ⁰₋₁e → ¹⁹⁶₇₇Ir

---

2. ¹¹⁰₄₉In + ___ → ___



- Mass: 110
- Atomic number: 49 – 1 = 48
- Element 48 is Cadmium (Cd)

Answer:
¹¹⁰₄₉In + ⁰₋₁e → ¹¹⁰₄₈Cd

---

3. ¹⁹⁶₇₈Pt + ___ → ___



Same as #1? Typo? Or maybe different isotope?

Wait — in your image, it says:

> ¹⁹⁶₇₈Pt + ___ → ___
> ¹⁹⁶₇₈Pt + ___ → ___

Probably duplicate? Or maybe second one is different?

Looking at your image again — it seems like the third one is:

> ¹⁹⁶₇₈Pt + ___ → ___
> ¹⁹⁶₇₈Pt + ___ → ___

Actually, looking closely — the last one is:

> ¹²³₅₃I + ___ → ___

Ah! The last one is Iodine-123

So:

4. ¹²³₅₃I + ___ → ___



- Mass: 123
- Atomic number: 53 – 1 = 52
- Element 52 is Tellurium (Te)

Answer:
¹²³₅₃I + ⁰₋₁e → ¹²³₅₂Te

---

## FINAL ANSWERS SUMMARY

---

Alpha Decay:



1. ²³⁰₉₀Th → ²²⁶₈₈Ra + ⁴₂He
2. ²³⁸₉₂U → ²³⁴₉₀Th + ⁴₂He
3. ²³⁸₉₈Cf → ²³⁴₉₆Cm + ⁴₂He *(assuming typo — U should be Cf)*
4. ²²²₈₆Rn → ²¹⁸₈₄Po + ⁴₂He

---

Beta Decay:



1. ¹⁴₆C → ¹⁴₇N + ⁰₋₁e
2. ⁹⁰₃₈Sr → ⁹⁰₃₉Y + ⁰₋₁e
3. ⁴⁰₁₉K → ⁴⁰₂₀Ca + ⁰₋₁e
4. ¹³₇N → ¹³₈O + ⁰₋₁e

---

Electron Capture:



1. ¹⁹⁶₇₈Pt + ⁰₋₁e → ¹⁹⁶₇₇Ir
2. ¹¹⁰₄₉In + ⁰₋₁e → ¹¹⁰₄₈Cd
3. ¹²³₅₃I + ⁰₋₁e → ¹²³₅₂Te

---

## 🧠 KEY CONCEPTS REMEMBERED:

- Alpha decay: loses He nucleus → mass -4, atomic # -2
- Beta decay: neutron → proton + e⁻ → mass same, atomic # +1
- Electron capture: absorbs e⁻ → mass same, atomic # -1

Let me know if you’d like these explained with diagrams or real-world examples!
Parent Tip: Review the logic above to help your child master the concept of nuclear decay worksheet answers.
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