Fill in the blanks to solve the mixed operations math puzzle.

This is a mathematics cross-number puzzle involving mixed operations (addition, subtraction, multiplication, and division). The goal is to fill in the blanks by solving the given equations. Let's solve it step by step.

Step 1: Analyze the grid and start with known values

The grid contains equations that need to be solved. We will work row by row and column by column, filling in the blanks as we go.

#### Row 1:
- 6 × 3 = ?
- \( 6 \times 3 = 18 \)
- Fill in 18 in the next cell.

#### Row 2:
- ? + ? = 10
- This equation depends on the values from other rows or columns. We will revisit it later.

#### Row 3:
- 1 × ? = 12
- \( 1 \times 12 = 12 \)
- Fill in 12 in the next cell.
- 12 ÷ ? = 10
- This equation is not possible with integer values since 12 cannot be divided by any integer to get 10. There might be a typo or misunderstanding. Let's assume it's a different operation or value and revisit it later.

#### Row 4:
- ? + 8 = ?
- This equation depends on other values. We will revisit it later.

#### Row 5:
- 7 + 12 = ?
- \( 7 + 12 = 19 \)
- Fill in 19 in the next cell.
- 46 - 25 = ?
- \( 46 - 25 = 21 \)
- Fill in 21 in the next cell.

#### Row 6:
- ? + ? = 17
- This equation depends on other values. We will revisit it later.
- 17 - ? = 13
- \( 17 - 4 = 13 \)
- Fill in 4 in the next cell.

#### Row 7:
- ? = ?
- This equation depends on other values. We will revisit it later.
- ? + ? = ?
- This equation depends on other values. We will revisit it later.

#### Row 8:
- 56 - 42 = ?
- \( 56 - 42 = 14 \)
- Fill in 14 in the next cell.
- ? + 35 = ?
- This equation depends on other values. We will revisit it later.

#### Row 9:
- ? × 3 × 16 = 65
- This equation is not possible with integer values since 65 cannot be factored into three integers where one of them is 3 and another is 16. There might be a typo. Let's assume it's a different operation or value and revisit it later.

#### Row 10:
- 17 + ? = ?
- This equation depends on other values. We will revisit it later.
- 4 × ? = 32
- \( 4 \times 8 = 32 \)
- Fill in 8 in the next cell.

#### Row 11:
- 21 - 16 = ?
- \( 21 - 16 = 5 \)
- Fill in 5 in the next cell.
- 7 + ? = ?
- This equation depends on other values. We will revisit it later.

#### Row 12:
- ? × 3 = 60
- \( 20 \times 3 = 60 \)
- Fill in 20 in the next cell.

Step 2: Revisit dependent equations

Now that we have filled in some values, let's revisit the dependent equations:

#### Row 2:
- ? + ? = 10
- From Column 2, we see \( 1 + 9 = 10 \).
- Fill in 9 in the next cell.

#### Row 3:
- 1 × ? = 12
- Already solved as 12.
- 12 ÷ ? = 10
- This equation is not possible with integer values. Let's assume it's a typo and skip it for now.

#### Row 4:
- ? + 8 = ?
- From Column 4, we see \( 2 + 8 = 10 \).
- Fill in 2 in the first cell and 10 in the last cell.

#### Row 6:
- ? + ? = 17
- From Column 6, we see \( 9 + 8 = 17 \).
- Fill in 9 in the first cell and 8 in the second cell.
- 17 - ? = 13
- Already solved as 4.

#### Row 7:
- ? = ?
- From Column 7, we see \( 5 = 5 \).
- Fill in 5 in both cells.
- ? + ? = ?
- From Column 8, we see \( 3 + 2 = 5 \).
- Fill in 3 in the first cell and 2 in the second cell.

#### Row 8:
- 56 - 42 = ?
- Already solved as 14.
- ? + 35 = ?
- From Column 9, we see \( 14 + 35 = 49 \).
- Fill in 49 in the last cell.

#### Row 9:
- ? × 3 × 16 = 65
- This equation is not possible with integer values. Let's assume it's a typo and skip it for now.

#### Row 10:
- 17 + ? = ?
- From Column 10, we see \( 17 + 10 = 27 \).
- Fill in 10 in the second cell and 27 in the last cell.
- 4 × ? = 32
- Already solved as 8.

#### Row 11:
- 21 - 16 = ?
- Already solved as 5.
- 7 + ? = ?
- From Column 11, we see \( 7 + 15 = 22 \).
- Fill in 15 in the second cell and 22 in the last cell.

Final Answer:

After filling in all the values, the completed grid looks like this:

```
6 × 3 = 18
- + -
1 9 10
= = =
2 8 10
+ 8
7 + 12 = 19
× + +
9 17 27
= = =
14 49 84
56 - 42 = 14
= =
3 16
× ×
17 10 27
+ × -
21 - 16 = 5
= = =
7 22
× =
20 60
```

Thus, the final answer is:
\[
\boxed{
\begin{array}{|c|c|c|c|c|c|c|c|c|c|}
\hline
6 & \times & 3 & = & 18 & & & & & \\
\hline
- & & + & & - & & & & & \\
\hline
1 & & 9 & & 10 & & & & & \\
\hline
= & & = & & = & & & & & \\
\hline
2 & & 8 & & 10 & & & & & \\
\hline
& & + & & 8 & & & & & \\
\hline
7 & + & 12 & = & 19 & & & & & \\
\hline
\times & & + & & + & & & & & \\
\hline
9 & & 17 & & 27 & & & & & \\
\hline
= & & = & & = & & & & & \\
\hline
14 & & 49 & & 84 & & & & & \\
\hline
56 & - & 42 & = & 14 & & & & & \\
\hline
& & = & & = & & & & & \\
\hline
& & 3 & & 16 & & & & & \\
\hline
& & \times & & \times & & & & & \\
\hline
17 & & 10 & & 27 & & & & & \\
\hline
+ & & \times & & - & & & & & \\
\hline
21 & - & 16 & = & 5 & & & & & \\
\hline
= & & = & & = & & & & & \\
\hline
& & 7 & & 22 & & & & & \\
\hline
& & \times & & = & & & & & \\
\hline
& & 20 & & 60 & & & & & \\
\hline
\end{array}
}
\]