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Let’s go step by step to solve this problem.

We are told that each food item has a certain number of “units” (like points or values) based on how much protein, carbs, fat, etc., it contains. We need to pick foods so that the total units for lunch and dinner both add up to exactly 10 — because we’re making two balanced meals from one set of foods.

Here’s what each food is worth:

- Boiled egg = 2 units
- Cottage cheese = 3 units
- Plain cheese = 4 units
- Beef steak = 6 units
- Grilled lamb chop = 5 units
- Chicken drumstick = 3 units
- Lettuce = 1 unit
- Spinach = 2 units
- Broccoli = 2 units
- Fried egg = 3 units
- Peas = 2 units
- Potato = 3 units

Total units if you eat ALL these foods:
Let’s add them up:

Lunch/dinner combo must use all 12 items? Wait — no! The task says: “Decide which food items you would like to make each part of a balanced diet. Write the name of the item and check how many it is in.”

Actually, re-reading: “There are some meals with at least ten minutes away from each other. Decide which food items you would like to make each part of a balanced diet. Write the name of the item and check how many it is in.”

Wait — maybe I misread. Let me look again.

Actually, the key sentence is: “Each meal should contain about 10 units.” And we have to choose foods for LUNCH and DINNER such that each adds up to 10 units.

But do we have to use all the foods? Or can we pick any combination?

Looking at the layout: there are 12 foods listed, and we’re supposed to assign them to either Lunch or Dinner — but probably not all need to be used? Or maybe we split them into two groups of 10 units each?

Wait — let’s check the total sum of all 12 foods:

Boiled egg (2) + Cottage cheese (3) + Plain cheese (4) + Beef steak (6) + Grilled lamb chop (5) + Chicken drumstick (3) + Lettuce (1) + Spinach (2) + Broccoli (2) + Fried egg (3) + Peas (2) + Potato (3)

Add step by step:

Start with 2 (boiled egg)
+3 = 5
+4 = 9
+6 = 15
+5 = 20
+3 = 23
+1 = 24
+2 = 26
+2 = 28
+3 = 31
+2 = 33
+3 = 36

Total = 36 units.

If we want two meals of 10 units each, that’s only 20 units — so we don’t have to use all foods. But the worksheet says “make each part of a balanced diet” — and shows boxes for Lunch and Dinner with space to write names and check marks.

Also, note: the Science activity says “Decide which food items you would like to make each part of a balanced diet.” So likely, we are to select subsets of foods for Lunch and Dinner, each totaling 10 units.

And since it’s a balancing act, probably we should try to use as many different foods as possible, or maybe just find any valid combinations.

But let’s see — perhaps the goal is to divide the 12 foods into two groups (Lunch and Dinner), each summing to 18? Because 36 ÷ 2 = 18. But the text says “about 10 units”. Hmm.

Wait — rereading the top: “A balancing act” — and under Background knowledge: “Most diets consist of varied combinations of food for growth and repair... You may not get enough food through a single type of food.”

Then Science activity: “There are some meals with at least ten minutes away from each other. Decide which food items you would like to make each part of a balanced diet. Write the name of the item and check how many it is in.”

This is confusing. Maybe “ten minutes” is a typo? Probably meant “ten units”? That makes more sense.

In many school worksheets like this, they give you a list of foods with point values, and you have to create two meals (lunch and dinner) where each meal totals 10 points.

So let’s assume that’s the goal: Pick foods for Lunch that add to 10, and pick other foods for Dinner that also add to 10. You don’t have to use all foods — just make two balanced meals.

But then why list 12 foods? Maybe to give options.

Alternatively, maybe we are to use all 12 foods, splitting them into two groups of 18 each? But 18 isn’t mentioned.

Wait — look at the bottom left: “Science investigation: Collect pictures of real and fake advertisements for healthy eating...” — that’s separate.

Back to the main table.

Perhaps the instruction is: For each meal (lunch and dinner), choose foods that add up to 10 units. You can reuse foods? No, probably not — each food is listed once, so likely you assign each food to either lunch or dinner or neither.

But 36 total, so if we make two meals of 10, we leave out 16 units — which seems odd.

Another idea: maybe “each part” means breakfast, lunch, dinner? But only lunch and dinner are shown.

Wait — the table has two columns: one labeled “Lunch” with 4 rows, and one labeled “Dinner” with 4 rows. So probably, we are to fill in 4 foods for lunch and 4 for dinner, each group summing to 10.

That makes sense! 4 foods per meal, each meal = 10 units.

Let me verify: 4 foods for lunch adding to 10, 4 foods for dinner adding to 10. Total 8 foods used, leaving 4 unused. Possible.

Total sum is 36, so if we use 8 foods summing to 20, the remaining 4 sum to 16 — fine.

So goal: Select 4 foods for Lunch that add to 10, and 4 different foods for Dinner that add to 10.

Now, let’s list the foods with their values again for clarity:

Foods and values:
1. Boiled egg - 2
2. Cottage cheese - 3
3. Plain cheese - 4
4. Beef steak - 6
5. Grilled lamb chop - 5
6. Chicken drumstick - 3
7. Lettuce - 1
8. Spinach - 2
9. Broccoli - 2
10. Fried egg - 3
11. Peas - 2
12. Potato - 3

We need two sets of four foods each, each set summing to 10.

Let’s try to find a combination for Lunch first.

Try including low-value foods to reach 10 with four items.

For example, suppose we take Lettuce (1), then we need three more foods summing to 9.

Possible: Boiled egg (2), Spinach (2), and something else? 1+2+2=5, need 5 more — too big for one food max is 6, but we need three foods already? No, we have four slots.

Better approach: list all possible combinations of four foods that sum to 10.

Since numbers are small, we can try.

Start with smallest: Lettuce (1). Then we need three foods summing to 9.

Possible triples summing to 9:

- 2,2,5 → Boiled egg, Spinach, Grilled lamb chop? Values: 2+2+5=9 → plus Lettuce 1 = 10. Foods: Lettuce, Boiled egg, Spinach, Grilled lamb chop. Sum: 1+2+2+5=10. Good.

Check if these are available: yes.

So Lunch could be: Lettuce (1), Boiled egg (2), Spinach (2), Grilled lamb chop (5) → total 10.

Now for Dinner, we need four other foods summing to 10.

Remaining foods: Cottage cheese (3), Plain cheese (4), Beef steak (6), Chicken drumstick (3), Broccoli (2), Fried egg (3), Peas (2), Potato (3)

List: 3,4,6,3,2,3,2,3

Need four that sum to 10.

Try: Broccoli (2), Peas (2), and two others.

2+2=4, need 6 more from two foods.

Possible pairs: 3+3=6 → e.g., Cottage cheese and Chicken drumstick? 3+3=6.

So: Broccoli (2), Peas (2), Cottage cheese (3), Chicken drumstick (3) → 2+2+3+3=10. Perfect.

Foods used: for Lunch: Lettuce, Boiled egg, Spinach, Grilled lamb chop

For Dinner: Broccoli, Peas, Cottage cheese, Chicken drumstick

Leftover: Plain cheese (4), Beef steak (6), Fried egg (3), Potato (3) — sum 4+6+3+3=16, which is fine.

Is this balanced? Well, it meets the unit requirement.

But let’s see if there’s another combination that might be more "balanced" in terms of food types, but the problem doesn’t specify, so this should work.

We could try to include higher protein or something, but since it’s based on units given, we just follow the numbers.

Another combination for variety.

Suppose for Lunch: Lettuce (1), Boiled egg (2), Peas (2), Potato (3) → 1+2+2+3=8, need 2 more — but we have only four slots. 8<10.

Not enough.

Lettuce (1), Spinach (2), Broccoli (2), and Plain cheese (4) → 1+2+2+4=9, still need 1 more — no food is 1 except Lettuce already used.

Not good.

Cottage cheese (3), Chicken drumstick (3), Fried egg (3), and Lettuce (1) → 3+3+3+1=10. Oh, that’s good.

Foods: Cottage cheese, Chicken drumstick, Fried egg, Lettuce → sum 3+3+3+1=10.

Then for Dinner, remaining: Boiled egg (2), Plain cheese (4), Beef steak (6), Grilled lamb chop (5), Spinach (2), Broccoli (2), Peas (2), Potato (3)

Need four summing to 10.

Try: Boiled egg (2), Spinach (2), Broccoli (2), Potato (3) → 2+2+2+3=9, need 1 more — no.

Boiled egg (2), Peas (2), Broccoli (2), and something — same.

Plain cheese (4), and three small: say Boiled egg (2), Spinach (2), Lettuce but Lettuce used.

Available: 2,4,6,5,2,2,2,3

Try: Boiled egg (2), Peas (2), Broccoli (2), and Potato (3) → 2+2+2+3=9 — still 9.

Need 10.

What about Spinach (2), Peas (2), Broccoli (2), and Plain cheese (4)? 2+2+2+4=10. Yes!

Foods: Spinach, Peas, Broccoli, Plain cheese → sum 2+2+2+4=10.

Perfect.

So Lunch: Cottage cheese (3), Chicken drumstick (3), Fried egg (3), Lettuce (1) → 10

Dinner: Spinach (2), Peas (2), Broccoli (2), Plain cheese (4) → 10

Leftover: Boiled egg (2), Beef steak (6), Grilled lamb chop (5), Potato (3) — sum 16.

Also valid.

But in this case, Dinner has three vegetables and cheese, Lunch has dairy, meat, egg, veg — might be less balanced, but again, the problem is about units.

To make it more varied, perhaps mix.

But since the question doesn't specify, either is fine.

I think the first combination I found is good.

But let’s confirm the values.

First solution:

Lunch:
- Lettuce: 1
- Boiled egg: 2
- Spinach: 2
- Grilled lamb chop: 5
Sum: 1+2+2+5=10

Dinner:
- Broccoli: 2
- Peas: 2
- Cottage cheese: 3
- Chicken drumstick: 3
Sum: 2+2+3+3=10

All foods distinct, no repeats.

We can write it as:

Lunch: Lettuce, Boiled egg, Spinach, Grilled lamb chop

Dinner: Broccoli, Peas, Cottage cheese, Chicken drumstick

Now, to present the answer.

The worksheet has boxes to write the name and check the value, but since we’re providing the answer, we’ll list them.

Final Answer:

Lunch: Lettuce (1), Boiled egg (2), Spinach (2), Grilled lamb chop (5)
Dinner: Broccoli (2), Peas (2), Cottage cheese (3), Chicken drumstick (3)

Each meal sums to 10 units.