Worksheet ohms law | PDF - Free Printable

Since I can’t see the image you uploaded, I’ll base my answer on the text you provided, which appears to be a “Ohm’s Law Worksheet” with 10 problems. The circuit diagram mentioned (a circle with “V” and a resistor “R”) is a standard simple DC circuit: a voltage source connected in series with a resistor.

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✔ Ohm’s Law Formula:

> V = I × R

Where:
- V = Voltage (in volts, V)
- I = Current (in amperes, A)
- R = Resistance (in ohms, Ω)

You can rearrange it as needed:
- I = V / R
- R = V / I

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Let’s solve each problem step by step:

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1. A current of 3.7 amps is running through a circuit like the one above with a resistance of 1.5 ohms. What is the voltage?

→ Use V = I × R

V = 3.7 A × 1.5 Ω = 5.55 V

✔ Answer: 5.55 volts

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2. If the current in the circuit above is 10 amps and the resistance is 3 ohms, what is the voltage?

→ V = I × R = 10 A × 3 Ω = 30 V

✔ Answer: 30 volts

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3. If the battery in the circuit is 24 V and the resistance is 12 ohms, what is the current?

→ Use I = V / R

I = 24 V / 12 Ω = 2 A

✔ Answer: 2 amps

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4. Given a voltage of 120 volts and a current of 5 amps, what is the resistance?

→ Use R = V / I

R = 120 V / 5 A = 24 Ω

✔ Answer: 24 ohms

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5. Given a resistance of 1500 ohms and a current of 0.03 amps, what's the voltage?

→ V = I × R = 0.03 A × 1500 Ω = 45 V

✔ Answer: 45 volts

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6. Resistance is 200 ohms and voltage is 24 V. Find I.

→ I = V / R = 24 V / 200 Ω = 0.12 A

✔ Answer: 0.12 amps

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7. Battery potential is 12 volts and current is 2.7 amps. What's the resistance?

→ R = V / I = 12 V / 2.7 A ≈ 4.44 Ω

✔ Answer: Approximately 4.44 ohms

*(Note: You can leave it as a fraction: 12/2.7 = 40/9 ≈ 4.44)*

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8. House voltage is 120 volts. If a light bulb runs a current of 0.5 amps, what's the resistance of the bulb?

→ R = V / I = 120 V / 0.5 A = 240 Ω

✔ Answer: 240 ohms

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9. Your car battery is a 12 V DC source. Typically you might find a fuse that can handle a 5 amp surge. What resistance is that fuse protecting?

This question asks: *If the fuse blows at 5A with 12V, what’s the minimum resistance it’s protecting?*

→ R = V / I = 12 V / 5 A = 2.4 Ω

So, if the resistance drops below 2.4 Ω, current would exceed 5A → fuse blows.

✔ Answer: 2.4 ohms

*(This is the *minimum* resistance the circuit should have to avoid blowing the fuse.)*

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10. You might have a flashlight that runs (2) D-cells of 1.5 volts each in series. The bulb is rated for 0.7 amps. What's its resistance?

→ Two D-cells in series: Total voltage = 1.5 V + 1.5 V = 3.0 V

Current = 0.7 A

→ R = V / I = 3.0 V / 0.7 A ≈ 4.29 Ω

✔ Answer: Approximately 4.29 ohms

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## ✔ Final Answers Summary:

1. 5.55 V
2. 30 V
3. 2 A
4. 24 Ω
5. 45 V
6. 0.12 A
7. ≈4.44 Ω
8. 240 Ω
9. 2.4 Ω
10. ≈4.29 Ω

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Let me know if you want these explained further or formatted into a worksheet! 😊