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Practice problems for order of operations, featuring expressions with addition, subtraction, multiplication, division, and parentheses.

A worksheet titled "ORDER OF OPERATIONS PRACTICE" with six math problems involving parentheses, brackets, and mixed operations.

A worksheet titled "ORDER OF OPERATIONS PRACTICE" with six math problems involving parentheses, brackets, and mixed operations.

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Show Answer Key & Explanations Step-by-step solution for: Order of Operations Practice Worksheet | Math = Love
Let's solve each expression step by step using the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right).

---

Problem 1:


Expression:
$$
3 + [(9 \div 3) \cdot 2] + [(2 \cdot 6) \div 3]
$$

Step-by-step:

1. Evaluate inside parentheses:
- $9 \div 3 = 3$
- $2 \cdot 6 = 12$

2. Now substitute:
$$
3 + [3 \cdot 2] + [12 \div 3]
$$

3. Perform multiplication and division:
- $3 \cdot 2 = 6$
- $12 \div 3 = 4$

4. Now:
$$
3 + 6 + 4 = 13
$$

Answer: 13

---

Problem 2:


Expression:
$$
[(3 + 9) \div (3 \cdot 2)] + [(2 \cdot 6) \div 3]
$$

Step-by-step:

1. Inside parentheses:
- $3 + 9 = 12$
- $3 \cdot 2 = 6$
- $2 \cdot 6 = 12$

2. Substitute:
$$
[12 \div 6] + [12 \div 3]
$$

3. Perform divisions:
- $12 \div 6 = 2$
- $12 \div 3 = 4$

4. Add:
$$
2 + 4 = 6
$$

Answer: 6

---

Problem 3:


Expression:
$$
(3 + 9) \div [(3 \cdot 2 + 2 \cdot 6) \div 3]
$$

Step-by-step:

1. Numerator: $3 + 9 = 12$

2. Denominator: $(3 \cdot 2 + 2 \cdot 6) \div 3$

- First, do multiplications:
- $3 \cdot 2 = 6$
- $2 \cdot 6 = 12$
- Then addition: $6 + 12 = 18$
- Then divide: $18 \div 3 = 6$

3. So now:
$$
12 \div 6 = 2
$$

Answer: 2

---

Problem 4:


Expression:
$$
(3 + 9 \div 3 \cdot 2) + (2 \cdot 6 \div 3)
$$

Important: No parentheses around $9 \div 3 \cdot 2$, so follow left-to-right for same precedence (division and multiplication).

Step-by-step:

1. First part: $3 + 9 \div 3 \cdot 2$

- $9 \div 3 = 3$
- $3 \cdot 2 = 6$
- $3 + 6 = 9$

2. Second part: $2 \cdot 6 \div 3$

- $2 \cdot 6 = 12$
- $12 \div 3 = 4$

3. Add both parts:
$$
9 + 4 = 13
$$

Answer: 13

---

Problem 5:


Expression:
$$
[(3 + 9) \div 3 \cdot 2 + 2] \cdot (6 \div 3)
$$

Step-by-step:

1. Start with innermost:
- $3 + 9 = 12$

2. So expression becomes:
$$
[12 \div 3 \cdot 2 + 2] \cdot (6 \div 3)
$$

3. Work inside the first bracket:
- $12 \div 3 = 4$
- $4 \cdot 2 = 8$
- $8 + 2 = 10$

4. Second part: $6 \div 3 = 2$

5. Now:
$$
10 \cdot 2 = 20
$$

Answer: 20

---

Problem 6:


Expression:
$$
[(3 + 9 \div 3) \cdot 2] + (2 \cdot 6 \div 3)
$$

Step-by-step:

1. Inside first bracket: $3 + 9 \div 3$

- $9 \div 3 = 3$
- $3 + 3 = 6$

2. Multiply by 2: $6 \cdot 2 = 12$

3. Second part: $2 \cdot 6 \div 3$

- $2 \cdot 6 = 12$
- $12 \div 3 = 4$

4. Add:
$$
12 + 4 = 16
$$

Answer: 16

---

Final Answers:



| Expression | Answer |
|----------|--------|
| $3 + [(9 \div 3) \cdot 2] + [(2 \cdot 6) \div 3]$ | 13 |
| $[(3 + 9) \div (3 \cdot 2)] + [(2 \cdot 6) \div 3]$ | 6 |
| $(3 + 9) \div [(3 \cdot 2 + 2 \cdot 6) \div 3]$ | 2 |
| $(3 + 9 \div 3 \cdot 2) + (2 \cdot 6 \div 3)$ | 13 |
| $[(3 + 9) \div 3 \cdot 2 + 2] \cdot (6 \div 3)$ | 20 |
| $[(3 + 9 \div 3) \cdot 2] + (2 \cdot 6 \div 3)$ | 16 |

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