Order of Operations Practice Worksheet | Math = Love - Free Printable
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Step-by-step solution for: Order of Operations Practice Worksheet | Math = Love
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Show Answer Key & Explanations
Step-by-step solution for: Order of Operations Practice Worksheet | Math = Love
Let’s solve each problem one by one, following the order of operations:
> PEMDAS:
> Parentheses → Exponents → Multiplication & Division (left to right) → Addition & Subtraction (left to right)
We’ll go row by row, left to right.
---
Problem 1: Left column, top row
`3 + [(9 ÷ 3) · 2] + [(2 · 6) ÷ 3]`
Step 1: Solve inside innermost parentheses first.
- `(9 ÷ 3)` = 3
- `(2 · 6)` = 12
Now plug back in:
`3 + [3 · 2] + [12 ÷ 3]`
Step 2: Do multiplication and division inside brackets.
- `3 · 2` = 6
- `12 ÷ 3` = 4
Now:
`3 + 6 + 4`
Step 3: Add left to right.
`3 + 6 = 9`, then `9 + 4 = 13`
✔ Answer: 13
---
Problem 2: Right column, top row
`[(3 + 9) ÷ (3 · 2)] + [(2 · 6) ÷ 3]`
Step 1: Inner parentheses:
- `(3 + 9)` = 12
- `(3 · 2)` = 6
- `(2 · 6)` = 12
Plug in:
`[12 ÷ 6] + [12 ÷ 3]`
Step 2: Divide:
- `12 ÷ 6` = 2
- `12 ÷ 3` = 4
Add: `2 + 4 = 6`
✔ Answer: 6
---
Problem 3: Left column, second row
`(3 + 9) ÷ [(3 · 2 + 2 · 6) ÷ 3]`
Step 1: Numerator: `(3 + 9)` = 12
Denominator: Inside big bracket: `(3 · 2 + 2 · 6) ÷ 3`
First, do multiplications inside:
- `3 · 2` = 6
- `2 · 6` = 12
So: `(6 + 12) ÷ 3` = `18 ÷ 3` = 6
Now whole expression: `12 ÷ 6 = 2`
✔ Answer: 2
---
Problem 4: Right column, second row
`(3 + 9 ÷ 3 · 2) + (2 · 6 ÷ 3)`
Important: In `9 ÷ 3 · 2`, do left to right!
First part: `(3 + 9 ÷ 3 · 2)`
- `9 ÷ 3` = 3
- `3 · 2` = 6
- So: `3 + 6 = 9`
Second part: `(2 · 6 ÷ 3)`
- `2 · 6` = 12
- `12 ÷ 3` = 4
Total: `9 + 4 = 13`
✔ Answer: 13
---
Problem 5: Left column, third row
`[(3 + 9) ÷ 3 · 2 + 2] · (6 ÷ 3)`
Step 1: `(3 + 9)` = 12
Then: `[12 ÷ 3 · 2 + 2] · (6 ÷ 3)`
Inside bracket: Left to right for ÷ and ·
- `12 ÷ 3` = 4
- `4 · 2` = 8
- `8 + 2` = 10
Other part: `(6 ÷ 3)` = 2
Multiply: `10 · 2 = 20`
✔ Answer: 20
---
Problem 6: Right column, third row
`[(3 + 9 ÷ 3) · 2] + (2 · 6 ÷ 3)`
First: Inside first bracket: `(3 + 9 ÷ 3)`
- `9 ÷ 3` = 3
- `3 + 3` = 6
- Then `6 · 2` = 12
Second part: `(2 · 6 ÷ 3)`
- `2 · 6` = 12
- `12 ÷ 3` = 4
Total: `12 + 4 = 16`
✔ Answer: 16
---
Problem 7: Left column, fourth row
`[(3 + 9 ÷ (3 · 2) + 2] · 6 ÷ 3`
Wait — let me check original: It says:
`[(3 + 9 ÷ (3 · 2) + 2] · 6 ÷ 3`
Actually, looking again — it should be:
`[(3 + 9 ÷ (3 · 2) + 2)] · 6 ÷ 3`
Assume that’s what was meant.
Step 1: Innermost: `(3 · 2)` = 6
Then: `9 ÷ 6` = 1.5? Wait — but maybe we’re supposed to keep fractions or decimals? Let’s see.
But actually, let’s re-read carefully. Original is:
`[(3 + 9 ÷ (3 · 2) + 2] · 6 ÷ 3`
I think there might be a typo — probably meant:
`[(3 + 9 ÷ (3 · 2) + 2)] · 6 ÷ 3`
Proceeding:
- `(3 · 2)` = 6
- `9 ÷ 6` = 1.5
- Now: `3 + 1.5 + 2` = 6.5
- Then: `6.5 · 6` = 39
- Then: `39 ÷ 3` = 13
But wait — this gives decimal. Maybe I misread.
Looking back at image description — perhaps it's:
`[(3 + 9 ÷ (3 · 2) + 2)] · 6 ÷ 3`
Yes. But 9÷6=1.5 — okay, unless they expect fraction.
Alternatively — maybe it’s `(3 + 9) ÷ (3·2) + 2`? No, brackets are as written.
Wait — let me double-check the original problem from your list:
You wrote:
`[(3 + 9 ÷ (3 · 2) + 2] · 6 ÷ 3`
There’s an extra opening bracket? Probably typo. Likely:
`[(3 + 9 ÷ (3 · 2) + 2)] · 6 ÷ 3`
So:
Inner: `3·2=6`
Then: `9÷6 = 3/2 = 1.5`
Then: `3 + 1.5 + 2 = 6.5`
Then: `6.5 × 6 = 39`
Then: `39 ÷ 3 = 13`
✔ Answer: 13
*(Note: If fractional answer expected, 13 is still correct since 39/3=13)*
---
Problem 8: Right column, fourth row
`3 + (9 ÷ 3) · (2 + 2 · 6 ÷ 3)`
Break it down.
First: `(9 ÷ 3)` = 3
Second: Inside other parentheses: `(2 + 2 · 6 ÷ 3)`
Do multiplication/division left to right:
- `2 · 6` = 12
- `12 ÷ 3` = 4
- Then: `2 + 4` = 6
Now: `3 + 3 · 6`
Multiplication before addition: `3 · 6 = 18`
Then: `3 + 18 = 21`
✔ Answer: 21
---
Problem 9: Left column, bottom row
`3 + {[(9 ÷ 3) · (2 + 2)] · (6 ÷ 3)}`
Start innermost:
- `(9 ÷ 3)` = 3
- `(2 + 2)` = 4
- `(6 ÷ 3)` = 2
Now: `{[3 · 4] · 2}`
→ `[12] · 2` = 24
Then: `3 + 24 = 27`
✔ Answer: 27
---
Problem 10: Right column, bottom row
`[(3 + 9) ÷ 3] · 2 + [(2 · 6) ÷ 3]`
Step 1: `(3 + 9)` = 12 → `12 ÷ 3` = 4 → `4 · 2` = 8
Step 2: `(2 · 6)` = 12 → `12 ÷ 3` = 4
Add: `8 + 4 = 12`
✔ Answer: 12
---
Final Answers Summary:
Left Column:
1. 13
2. 2
3. 20
4. 13
5. 27
Right Column:
1. 6
2. 13
3. 16
4. 21
5. 12
──────────────────────────────────────
Final Answer:
Left Column (top to bottom): 13, 2, 20, 13, 27
Right Column (top to bottom): 6, 13, 16, 21, 12
> PEMDAS:
> Parentheses → Exponents → Multiplication & Division (left to right) → Addition & Subtraction (left to right)
We’ll go row by row, left to right.
---
Problem 1: Left column, top row
`3 + [(9 ÷ 3) · 2] + [(2 · 6) ÷ 3]`
Step 1: Solve inside innermost parentheses first.
- `(9 ÷ 3)` = 3
- `(2 · 6)` = 12
Now plug back in:
`3 + [3 · 2] + [12 ÷ 3]`
Step 2: Do multiplication and division inside brackets.
- `3 · 2` = 6
- `12 ÷ 3` = 4
Now:
`3 + 6 + 4`
Step 3: Add left to right.
`3 + 6 = 9`, then `9 + 4 = 13`
✔ Answer: 13
---
Problem 2: Right column, top row
`[(3 + 9) ÷ (3 · 2)] + [(2 · 6) ÷ 3]`
Step 1: Inner parentheses:
- `(3 + 9)` = 12
- `(3 · 2)` = 6
- `(2 · 6)` = 12
Plug in:
`[12 ÷ 6] + [12 ÷ 3]`
Step 2: Divide:
- `12 ÷ 6` = 2
- `12 ÷ 3` = 4
Add: `2 + 4 = 6`
✔ Answer: 6
---
Problem 3: Left column, second row
`(3 + 9) ÷ [(3 · 2 + 2 · 6) ÷ 3]`
Step 1: Numerator: `(3 + 9)` = 12
Denominator: Inside big bracket: `(3 · 2 + 2 · 6) ÷ 3`
First, do multiplications inside:
- `3 · 2` = 6
- `2 · 6` = 12
So: `(6 + 12) ÷ 3` = `18 ÷ 3` = 6
Now whole expression: `12 ÷ 6 = 2`
✔ Answer: 2
---
Problem 4: Right column, second row
`(3 + 9 ÷ 3 · 2) + (2 · 6 ÷ 3)`
Important: In `9 ÷ 3 · 2`, do left to right!
First part: `(3 + 9 ÷ 3 · 2)`
- `9 ÷ 3` = 3
- `3 · 2` = 6
- So: `3 + 6 = 9`
Second part: `(2 · 6 ÷ 3)`
- `2 · 6` = 12
- `12 ÷ 3` = 4
Total: `9 + 4 = 13`
✔ Answer: 13
---
Problem 5: Left column, third row
`[(3 + 9) ÷ 3 · 2 + 2] · (6 ÷ 3)`
Step 1: `(3 + 9)` = 12
Then: `[12 ÷ 3 · 2 + 2] · (6 ÷ 3)`
Inside bracket: Left to right for ÷ and ·
- `12 ÷ 3` = 4
- `4 · 2` = 8
- `8 + 2` = 10
Other part: `(6 ÷ 3)` = 2
Multiply: `10 · 2 = 20`
✔ Answer: 20
---
Problem 6: Right column, third row
`[(3 + 9 ÷ 3) · 2] + (2 · 6 ÷ 3)`
First: Inside first bracket: `(3 + 9 ÷ 3)`
- `9 ÷ 3` = 3
- `3 + 3` = 6
- Then `6 · 2` = 12
Second part: `(2 · 6 ÷ 3)`
- `2 · 6` = 12
- `12 ÷ 3` = 4
Total: `12 + 4 = 16`
✔ Answer: 16
---
Problem 7: Left column, fourth row
`[(3 + 9 ÷ (3 · 2) + 2] · 6 ÷ 3`
Wait — let me check original: It says:
`[(3 + 9 ÷ (3 · 2) + 2] · 6 ÷ 3`
Actually, looking again — it should be:
`[(3 + 9 ÷ (3 · 2) + 2)] · 6 ÷ 3`
Assume that’s what was meant.
Step 1: Innermost: `(3 · 2)` = 6
Then: `9 ÷ 6` = 1.5? Wait — but maybe we’re supposed to keep fractions or decimals? Let’s see.
But actually, let’s re-read carefully. Original is:
`[(3 + 9 ÷ (3 · 2) + 2] · 6 ÷ 3`
I think there might be a typo — probably meant:
`[(3 + 9 ÷ (3 · 2) + 2)] · 6 ÷ 3`
Proceeding:
- `(3 · 2)` = 6
- `9 ÷ 6` = 1.5
- Now: `3 + 1.5 + 2` = 6.5
- Then: `6.5 · 6` = 39
- Then: `39 ÷ 3` = 13
But wait — this gives decimal. Maybe I misread.
Looking back at image description — perhaps it's:
`[(3 + 9 ÷ (3 · 2) + 2)] · 6 ÷ 3`
Yes. But 9÷6=1.5 — okay, unless they expect fraction.
Alternatively — maybe it’s `(3 + 9) ÷ (3·2) + 2`? No, brackets are as written.
Wait — let me double-check the original problem from your list:
You wrote:
`[(3 + 9 ÷ (3 · 2) + 2] · 6 ÷ 3`
There’s an extra opening bracket? Probably typo. Likely:
`[(3 + 9 ÷ (3 · 2) + 2)] · 6 ÷ 3`
So:
Inner: `3·2=6`
Then: `9÷6 = 3/2 = 1.5`
Then: `3 + 1.5 + 2 = 6.5`
Then: `6.5 × 6 = 39`
Then: `39 ÷ 3 = 13`
✔ Answer: 13
*(Note: If fractional answer expected, 13 is still correct since 39/3=13)*
---
Problem 8: Right column, fourth row
`3 + (9 ÷ 3) · (2 + 2 · 6 ÷ 3)`
Break it down.
First: `(9 ÷ 3)` = 3
Second: Inside other parentheses: `(2 + 2 · 6 ÷ 3)`
Do multiplication/division left to right:
- `2 · 6` = 12
- `12 ÷ 3` = 4
- Then: `2 + 4` = 6
Now: `3 + 3 · 6`
Multiplication before addition: `3 · 6 = 18`
Then: `3 + 18 = 21`
✔ Answer: 21
---
Problem 9: Left column, bottom row
`3 + {[(9 ÷ 3) · (2 + 2)] · (6 ÷ 3)}`
Start innermost:
- `(9 ÷ 3)` = 3
- `(2 + 2)` = 4
- `(6 ÷ 3)` = 2
Now: `{[3 · 4] · 2}`
→ `[12] · 2` = 24
Then: `3 + 24 = 27`
✔ Answer: 27
---
Problem 10: Right column, bottom row
`[(3 + 9) ÷ 3] · 2 + [(2 · 6) ÷ 3]`
Step 1: `(3 + 9)` = 12 → `12 ÷ 3` = 4 → `4 · 2` = 8
Step 2: `(2 · 6)` = 12 → `12 ÷ 3` = 4
Add: `8 + 4 = 12`
✔ Answer: 12
---
Final Answers Summary:
Left Column:
1. 13
2. 2
3. 20
4. 13
5. 27
Right Column:
1. 6
2. 13
3. 16
4. 21
5. 12
──────────────────────────────────────
Final Answer:
Left Column (top to bottom): 13, 2, 20, 13, 27
Right Column (top to bottom): 6, 13, 16, 21, 12
Parent Tip: Review the logic above to help your child master the concept of order of operations worksheet and answers.