Year 6 Order Fractions Worksheet/Worksheet - KS2 Maths - Free Printable

Let's solve each problem step by step. The goal is to order the fractions from least to greatest.

We'll use a common method: convert fractions to decimals or find a common denominator to compare them easily. Here, we’ll convert to decimals for simplicity.

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1) $\frac{1}{2}, \frac{1}{10}, \frac{1}{8}$

Convert to decimals:
- $\frac{1}{2} = 0.5$
- $\frac{1}{10} = 0.1$
- $\frac{1}{8} = 0.125$

Now order from least to greatest:
- $0.1 < 0.125 < 0.5$

So:
$\frac{1}{10}, \frac{1}{8}, \frac{1}{2}$

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2) $\frac{2}{5}, \frac{3}{4}, \frac{1}{3}$

Convert to decimals:
- $\frac{2}{5} = 0.4$
- $\frac{3}{4} = 0.75$
- $\frac{1}{3} \approx 0.333$

Order:
- $0.333 < 0.4 < 0.75$

So:
$\frac{1}{3}, \frac{2}{5}, \frac{3}{4}$

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3) $\frac{1}{10}, \frac{4}{5}, \frac{3}{8}$

Convert to decimals:
- $\frac{1}{10} = 0.1$
- $\frac{4}{5} = 0.8$
- $\frac{3}{8} = 0.375$

Order:
- $0.1 < 0.375 < 0.8$

So:
$\frac{1}{10}, \frac{3}{8}, \frac{4}{5}$

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4) $\frac{1}{5}, \frac{7}{8}, \frac{1}{3}$

Convert to decimals:
- $\frac{1}{5} = 0.2$
- $\frac{7}{8} = 0.875$
- $\frac{1}{3} \approx 0.333$

Order:
- $0.2 < 0.333 < 0.875$

So:
$\frac{1}{5}, \frac{1}{3}, \frac{7}{8}$

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5) $\frac{3}{8}, \frac{1}{4}, \frac{2}{3}$

Convert to decimals:
- $\frac{3}{8} = 0.375$
- $\frac{1}{4} = 0.25$
- $\frac{2}{3} \approx 0.666$

Order:
- $0.25 < 0.375 < 0.666$

So:
$\frac{1}{4}, \frac{3}{8}, \frac{2}{3}$

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6) $\frac{3}{10}, \frac{1}{3}, \frac{1}{5}$

Convert to decimals:
- $\frac{3}{10} = 0.3$
- $\frac{1}{3} \approx 0.333$
- $\frac{1}{5} = 0.2$

Order:
- $0.2 < 0.3 < 0.333$

So:
$\frac{1}{5}, \frac{3}{10}, \frac{1}{3}$

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✔ Final Answers:

1) $\frac{1}{10}, \frac{1}{8}, \frac{1}{2}$
2) $\frac{1}{3}, \frac{2}{5}, \frac{3}{4}$
3) $\frac{1}{10}, \frac{3}{8}, \frac{4}{5}$
4) $\frac{1}{5}, \frac{1}{3}, \frac{7}{8}$
5) $\frac{1}{4}, \frac{3}{8}, \frac{2}{3}$
6) $\frac{1}{5}, \frac{3}{10}, \frac{1}{3}$

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💡 Tip: When comparing fractions, converting to decimals is often faster and less error-prone than finding common denominators — especially when dealing with different denominators. But if you prefer using common denominators, that works too!

Let me know if you'd like to see the same problems solved using common denominators!