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Functional group identification and organic compound drawing worksheet with handwritten answers.

Functional group identification worksheet with handwritten answers identifying carbonyl, ester, amide, alcohol, and alkyl halide groups, and drawing organic compounds like propanol, 2-butanol, propyne, octane, and 2-butene with their respective families.

Functional group identification worksheet with handwritten answers identifying carbonyl, ester, amide, alcohol, and alkyl halide groups, and drawing organic compounds like propanol, 2-butanol, propyne, octane, and 2-butene with their respective families.

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The image you've uploaded is a Functional Group Identification Worksheet with answers already filled in. Let's go through each part and verify the solutions, then provide a clear explanation for each answer.

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Part 1: Identify the Functional Groups



#### a.
```
H
|
H - C - C=O
| |
H OH
```

- Structure: This molecule has a carbonyl group (C=O) bonded directly to a hydroxyl group (-OH).
- Functional Group: Carboxylic acid
- Correct Answer: "carb. acid" (short for carboxylic acid)

> 🔍 Explanation: The general structure is R–COOH. The presence of both the carbonyl (C=O) and hydroxyl (–OH) on the same carbon defines a carboxylic acid.

---

#### b.
```
H O H H
| || | |
H - C - C - O - C - C - H
| | | |
H H H H
```

- Structure: A carbonyl (C=O) attached to an oxygen that connects to another carbon chain.
- Functional Group: Ester
- Correct Answer: "ester"

> 🔍 Explanation: General form is R–COO–R'. The –COO– linkage between two alkyl groups indicates an ester.

---

#### c.
```
H O H
| || |
H - C - C - N - C - H
| | | |
H H H H
|
H
```

- Structure: A carbonyl (C=O) bonded to a nitrogen atom (N), which is also bonded to two hydrogens and a carbon.
- Functional Group: Amide
- Correct Answer: "amide (HL)" — likely "HL" stands for "hydrogen and lone pair" or is a typo/abbreviation; the correct term is amide.

> 🔍 Explanation: The functional group is –CONH₂, where a nitrogen is attached to a carbonyl carbon. This is an amide. If it were –CONH–, it would be a secondary amide, but here it appears to be a primary amide (attached to two H atoms).

---

#### d.
```
H OH H H
| | | |
H - C - C - C - C - H
| | | |
H H H H
```

- Structure: An –OH group attached to a carbon in a hydrocarbon chain.
- Functional Group: Alcohol
- Correct Answer: "alcohol"

> 🔍 Explanation: Any compound with a hydroxyl (–OH) group attached to a saturated carbon is an alcohol. This is butan-2-ol.

---

#### e.
```
H H Br H
| | | |
H - C - C - C - C - H
| | | |
H H H H
```

- Structure: A bromine (Br) atom attached to a carbon in an alkane chain.
- Functional Group: Alkyl halide
- Correct Answer: "alkyl halide"

> 🔍 Explanation: When a halogen (F, Cl, Br, I) is bonded to an alkyl carbon, it’s called an alkyl halide. Here, bromine is bonded to the third carbon → 3-bromobutane.

---

Part 2: Draw the Following Organic Compounds & State Their Family



#### a) Propanol
- Answer: CH₃–CH₂–CH₂–OH
- Family: Alcohol

> 🔍 Explanation: Propanol has three carbons with an –OH at the end. It's a straight-chain alcohol. Also known as 1-propanol.

---

#### b) 2-butanol
- Answer:
```
OH
|
CH₃–CH–CH₂–CH₃
```
- Family: Alcohol

> 🔍 Explanation: Butane chain (4 carbons), –OH on carbon #2. So it's a secondary alcohol.

---

#### c) Propyne
- Answer: H–C≡C–CH₃
- Family: Alkyne

> 🔍 Explanation: Propyne has three carbons with a triple bond between C1 and C2. Alkynes have C≡C bonds.

---

#### d) Octane
- Answer: A zigzag line with 8 carbons (or written as CH₃(CH₂)₆CH₃)
- Family: Alkane

> 🔍 Explanation: Octane is a straight-chain hydrocarbon with 8 carbons and only single bonds → alkane.

---

#### e) 2-butene
- Answer: CH₃–CH=CH–CH₃
- Family: Alkene

> 🔍 Explanation: Butene means 4 carbons, double bond at position 2 → C=C between C2 and C3. Alkenes contain carbon-carbon double bonds.

---

Summary of Correctness:



| Question | Answer Given | Correct? | Notes |
|--------|--------------|---------|-------|
| 1a | Carboxylic acid | | Correct |
| 1b | Ester | | Correct |
| 1c | Amide | | Correct; "HL" may be unclear, but meaning is clear |
| 1d | Alcohol | | Correct |
| 1e | Alkyl halide | | Correct |
| 2a | CH₃CH₂CH₂OH, alcohol | | Correct |
| 2b | CH₃CH(OH)CH₂CH₃, alcohol | | Correct |
| 2c | HC≡CCH₃, alkyne | | Correct |
| 2d | Octane (zigzag), alkane | | Correct |
| 2e | CH₃CH=CHCH₃, alkene | | Correct |

---

📌 Final Verdict:


All answers are correct! The student has accurately identified functional groups and drawn the structures properly.

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