Problem Analysis:
The task involves identifying functional groups in organic molecules and drawing an organic compound based on its name. Let's break it down step by step.
---
####
Part 1: Identify the Functional Groups
1.
Molecule (a):
- The molecule has a `C=O` group (carbonyl) bonded to an `OH` group.
- This is the
carboxylic acid functional group.
-
Correct Answer: Carboxylic acid
2.
Molecule (b):
- The molecule has a `C=O` group (carbonyl) bonded to an `O-R` group (where `R` is an alkyl group).
- This is the
ester functional group.
-
Correct Answer: Ester
3.
Molecule (c):
- The molecule has a `C=O` group (carbonyl) bonded to an `NH2` group.
- This is the
amide functional group.
-
Correct Answer: Amide
4.
Molecule (d):
- The molecule has an `OH` group bonded to a carbon atom.
- This is the
alcohol functional group.
-
Correct Answer: Alcohol
5.
Molecule (e):
- The molecule has a halogen (`Br`) atom directly bonded to a carbon atom.
- This is the
alkyl halide functional group.
-
Correct Answer: Alkyl halide
---
####
Part 2: Draw the Following Organic Compounds
1.
Compound (a): Propanol
- Propanol is an alcohol with a three-carbon chain (`propane`) and an `-OH` group.
- The structure of propanol can be written as:
```
CH3-CH2-CH2-OH
```
- Alternatively, it can be drawn using a condensed formula or a line-angle structure:
```
CH3CH2CH2OH
```
-
Correct Answer: The student correctly identified it as an alcohol and drew the structure as `OH`.
---
Final Answers:
1.
Functional Group Identification:
- (a) Carboxylic acid
- (b) Ester
- (c) Amide
- (d) Alcohol
- (e) Alkyl halide
2.
Drawing Propanol:
- Structure: `CH3CH2CH2OH`
---
Boxed Final Answer:
\[
\boxed{
\text{1. (a) Carboxylic acid, (b) Ester, (c) Amide, (d) Alcohol, (e) Alkyl halide}
}
\]
\[
\boxed{
\text{2. Propanol: } \text{CH3CH2CH2OH}
}
\]
Parent Tip: Review the logic above to help your child master the concept of organic chemistry functional groups worksheet.