- Next, find information: I have read the concentrations for the bottom row of beakers. Beaker 7 has 30% solute and 70% solvent. Beaker 8 has 40% solute and 60% solvent. Beaker 9 has 80% solute and 20% solvent. To solve the problem, I need to apply the principles of osmosis. I will now research the typical concentration of a cell to use as a baseline for comparison.
- Then, review the findings: I have gathered all the necessary data from the image. The worksheet presents 9 different solutions with varying solute and solvent percentages. To predict the effect on a cell placed in each solution, I must apply the principle of osmosis: water moves across a semi-permeable membrane from an area of lower solute concentration (higher water concentration) to an area of higher solute concentration (lower water concentration). For this type of problem, it is standard to assume a "typical" cell has a solute concentration of approximately 30%, meaning it is 70% water. I will now compare the solute concentration in each beaker to this 30% baseline to determine the direction of water movement and the resulting effect on the cell.
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Beaker 1 (80% solute): The solution is hypertonic (higher solute concentration than the cell). Water will move out of the cell, causing it to shrink (crenate).
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Beaker 2 (40% solute): The solution is hypertonic (higher solute concentration than the cell). Water will move out of the cell, causing it to shrink (crenate).
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Beaker 3 (70% solute): The solution is hypertonic (higher solute concentration than the cell). Water will move out of the cell, causing it to shrink (crenate).
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Beaker 4 (30% solute): The solution is isotonic (same solute concentration as the cell). There will be no net movement of water, so the cell will remain the same size.
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Beaker 5 (60% solute): The solution is hypertonic (higher solute concentration than the cell). Water will move out of the cell, causing it to shrink (crenate).
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Beaker 6 (80% solute): The solution is hypertonic (higher solute concentration than the cell). Water will move out of the cell, causing it to shrink (crenate).
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Beaker 7 (30% solute): The solution is isotonic (same solute concentration as the cell). There will be no net movement of water, so the cell will remain the same size.
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Beaker 8 (40% solute): The solution is hypertonic (higher solute concentration than the cell). Water will move out of the cell, causing it to shrink (crenate).
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Beaker 9 (80% solute): The solution is hypertonic (higher solute concentration than the cell). Water will move out of the cell, causing it to shrink (crenate).
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Final Answer:
- Beaker 1: Water moves out, cell shrinks.
- Beaker 2: Water moves out, cell shrinks.
- Beaker 3: Water moves out, cell shrinks.
- Beaker 4: No net movement, cell stays the same.
- Beaker 5: Water moves out, cell shrinks.
- Beaker 6: Water moves out, cell shrinks.
- Beaker 7: No net movement, cell stays the same.
- Beaker 8: Water moves out, cell shrinks.
- Beaker 9: Water moves out, cell shrinks.
Parent Tip: Review the logic above to help your child master the concept of osmosis worksheet biology.
