Practice worksheet for identifying and calculating angles formed by parallel lines cut by a transversal.
Worksheet titled "Parallel Lines Cut by a Transversal Practice" with four diagrams showing parallel lines intersected by transversals, angles labeled, and questions asking to find angle measures and determine the truth of statements about angle relationships.
WEBP
742×1050
43.1 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #800586
⭐
Show Answer Key & Explanations
Step-by-step solution for: Parallel Lines and Transversals Worksheets - Math Monks
▼
Show Answer Key & Explanations
Step-by-step solution for: Parallel Lines and Transversals Worksheets - Math Monks
Let's solve this step-by-step.
---
We'll use properties of parallel lines cut by a transversal, including:
- Corresponding angles are equal.
- Alternate interior angles are equal.
- Alternate exterior angles are equal.
- Consecutive (same-side) interior angles are supplementary (add to 180°).
- Vertical angles are equal.
- Linear pairs add up to 180°.
---
#### Problem 1)
Given:
- Lines AD and EH are parallel (assumed from diagram).
- Transversal CF cuts them.
- ∠BFC = 75°
We need to find:
- ∠HFC
- ∠HFG
##### Step 1: ∠HFC
∠BFC and ∠HFC are vertical angles (they are opposite each other at point F).
So,
> ∠HFC = ∠BFC = 75°
##### Step 2: ∠HFG
∠HFC and ∠HFG form a linear pair (they are adjacent and on a straight line), so they sum to 180°.
> ∠HFG = 180° – ∠HFC = 180° – 75° = 105°
✔ Answer:
- ∠HFC = 75°
- ∠HFG = 105°
---
#### Problem 2)
Given:
- Lines AD and EH are parallel.
- Transversal CG cuts them.
- ∠DBC = 38°
Wait — let’s clarify the notation.
Point B is on AD, and point F is on EH. The angle given is ∠DBC = 38°.
But D–B–C is not a straight line? Wait — actually, looking at the diagram:
- Line AD is horizontal.
- Line CG is the transversal going through B and F.
- ∠DBC is the angle at B between D–B and B–C.
But since AD is a straight line, and CB is going upward, ∠DBC is an angle formed at point B between line AD and transversal BC.
Wait — but we're told ∠DBC = 38°, which is likely the angle at B between DB and BC.
Now, since AD || EH, and transversal is CG, then:
- ∠DBC = 38° → this is an angle between the top line and the transversal.
We need:
- ∠HFC
- ∠DBC
Wait — ∠DBC is already given as 38°, so we just write that.
But let's double-check.
Actually, in the diagram:
- ∠DBC is the angle at B between D–B and B–C → this is interior angle on the right side.
- Since AD || EH, and transversal is CF, then ∠DBC and ∠HFC are corresponding angles?
Wait — let’s analyze.
From the diagram:
- ∠DBC is above the top line AD, on the right side of transversal.
- ∠HFC is below the bottom line EH, on the right side of transversal.
So they are on the same side of the transversal, one above, one below — that makes them corresponding angles only if they are in the same relative position.
Wait — actually, ∠DBC and ∠HFC are not corresponding because they are on different sides.
Let’s look carefully.
Actually, ∠DBC is formed by line AD and transversal BC, and ∠HFC is formed by line EH and transversal FG.
Since AD || EH, and transversal is CF, then:
- ∠DBC and ∠HFC are corresponding angles if they are in the same relative position.
But ∠DBC is above AD and to the right of the transversal.
- ∠HFC is below EH and to the right of the transversal.
So yes — both are on the right side of the transversal, and one above, one below → these are corresponding angles?
No — corresponding angles are in the same relative position — e.g., both upper-right or both lower-left.
But here, ∠DBC is upper-right, and ∠HFC is lower-right → they are not corresponding.
Wait — perhaps better to think about alternate interior or something else.
Alternatively, notice that ∠DBC and ∠BFE are alternate interior angles?
Wait — maybe it's easier to use vertical angles and linear pairs.
Let’s assume:
- ∠DBC = 38° (given)
- Then, since AD is a straight line, and ∠DBC is at B, then the angle adjacent to it (on the other side of the transversal) would be supplementary?
Wait — actually, ∠DBC is part of triangle or just an angle at B.
But looking at the figure: point B is where transversal CF intersects AD.
So ∠DBC is the angle between AD and CF at point B, on the right side.
So ∠DBC = 38° → this is the angle between AD and CF.
Then, since AD || EH, and CF is the transversal, then:
- ∠DBC and ∠HFC are corresponding angles? Let’s see:
- ∠DBC is on the top line, right side of transversal.
- ∠HFC is on the bottom line, right side of transversal.
Yes! So they are corresponding angles → therefore:
> ∠HFC = ∠DBC = 38°
And ∠DBC is given as 38°, so:
> ∠DBC = 38°
✔ Answer:
- ∠HFC = 38°
- ∠DBC = 38°
---
#### Problem 3)
Given:
- Lines AD and EH are parallel.
- Transversal BG cuts them.
- ∠ABF = 36° (at point B)
We need:
- ∠DBC
- ∠EFG
First, ∠ABF = 36° → this is the angle between AB and BF.
Since AD is a straight line, and ∠ABF = 36°, then the adjacent angle ∠FBD (which is ∠DBC) is:
> ∠DBC = 180° – 36° = 144°
Because AB and BD are a straight line (AD), so angles at B on a straight line sum to 180°.
So ∠DBC = 144°
Now, ∠EFG — this is the angle at F between E–F and F–G.
Since AD || EH, and transversal is BG, then:
- ∠ABF and ∠EFG are corresponding angles?
Let’s see:
- ∠ABF is at the top line, left side of transversal.
- ∠EFG is at the bottom line, left side of transversal.
Yes — both are on the left side of the transversal, and above and below respectively.
So they are corresponding angles → therefore:
> ∠EFG = ∠ABF = 36°
✔ Answer:
- ∠DBC = 144°
- ∠EFG = 36°
---
#### Problem 4)
Given:
- Lines AB and CD are parallel.
- Transversal GH cuts them.
- ∠GEB = 62° (angle at E between GE and EB)
We need:
- ∠AEH
- ∠DFG
First, ∠GEB = 62° → this is the angle between transversal GH and line AB at point E.
Since AB || CD, and GH is transversal.
Now, ∠AEH is the angle at E between AE and EH.
Note: AE is part of AB, and EH is part of GH.
So ∠AEH is adjacent to ∠GEB.
Since AB is a straight line, and GH crosses it at E, then:
- ∠AEH and ∠GEB are adjacent angles forming a linear pair.
So:
> ∠AEH = 180° – ∠GEB = 180° – 62° = 118°
Now, ∠DFG — this is at point F on line CD.
We want to find ∠DFG.
Note: ∠GEB = 62° → this is the angle between AB and GH.
Since AB || CD, then corresponding angles are equal.
∠GEB and ∠DFG are both on the right side of the transversal GH, and one is on top (AB), one on bottom (CD).
So they are corresponding angles → thus:
> ∠DFG = ∠GEB = 62°
✔ Answer:
- ∠AEH = 118°
- ∠DFG = 62°
---
We have two parallel lines cut by a transversal, with angles labeled 1 through 8.
Labeling convention:
- Top line: angles 1, 2, 3, 4 (clockwise)
- Bottom line: angles 5, 6, 7, 8 (clockwise)
Standard labeling:
- At top intersection: ∠1 (top-right), ∠2 (top-left), ∠3 (bottom-left), ∠4 (bottom-right)
- At bottom intersection: ∠5 (top-right), ∠6 (top-left), ∠7 (bottom-left), ∠8 (bottom-right)
Wait — actually, standard is:
- At top: ∠1 (top-right), ∠2 (top-left), ∠3 (bottom-left), ∠4 (bottom-right)
- At bottom: ∠5 (top-right), ∠6 (top-left), ∠7 (bottom-left), ∠8 (bottom-right)
But in the diagram, the labels are:
- Top: ∠1 (top-right), ∠2 (top-left), ∠3 (bottom-left), ∠4 (bottom-right)
- Bottom: ∠5 (top-right), ∠6 (top-left), ∠7 (bottom-left), ∠8 (bottom-right)
So:
| Angle | Position |
|-------|----------|
| ∠1 | Top-right |
| ∠2 | Top-left |
| ∠3 | Bottom-left |
| ∠4 | Bottom-right |
| ∠5 | Bottom-right (on lower line) |
| ∠6 | Bottom-left (on lower line) |
| ∠7 | Top-left (on lower line) |
| ∠8 | Top-right (on lower line) |
Wait — no — actually, when two lines cross, the four angles around a point are labeled clockwise.
So at the top intersection:
- ∠1: top-right
- ∠2: top-left
- ∠3: bottom-left
- ∠4: bottom-right
At the bottom intersection:
- ∠5: top-right
- ∠6: top-left
- ∠7: bottom-left
- ∠8: bottom-right
But the diagram shows:
- At top: ∠1, ∠2, ∠3, ∠4 (around the top intersection)
- At bottom: ∠5, ∠6, ∠7, ∠8 (around the bottom intersection)
So:
- ∠1 and ∠3 are vertical angles
- ∠2 and ∠4 are vertical angles
- ∠5 and ∠7 are vertical angles
- ∠6 and ∠8 are vertical angles
Also:
- ∠1 and ∠5 are corresponding
- ∠2 and ∠6 are corresponding
- ∠3 and ∠7 are corresponding
- ∠4 and ∠8 are corresponding
Alternate interior:
- ∠3 and ∠6 are alternate interior (both inside, on opposite sides)
- ∠4 and ∠5 are alternate interior
Alternate exterior:
- ∠1 and ∠8
- ∠2 and ∠7
Consecutive interior:
- ∠3 and ∠5
- ∠4 and ∠6
Now evaluate each statement:
---
1) ∠1 and ∠2 are vertically opposite angles.
- No. They are adjacent angles forming a linear pair.
- Vertically opposite would be ∠1 and ∠3, or ∠2 and ∠4.
→ False (F)
---
2) ∠1 and ∠5 are corresponding angles.
- Yes. Both are on the right side of the transversal, and above and below the parallel lines → corresponding angles.
→ True (T)
---
3) ∠2 and ∠5 are alternate exterior angles.
- ∠2 is top-left, ∠5 is bottom-right → not on the same side.
Alternate exterior angles: one on top, one on bottom, on opposite sides of transversal.
- ∠2 (top-left) and ∠8 (bottom-right) → are alternate exterior?
- ∠2 is left side, ∠8 is right side → no.
Wait: alternate exterior angles are:
- ∠2 and ∠7 (both on left side, one top, one bottom) → yes!
- ∠1 and ∠8 (both on right side, one top, one bottom) → yes!
So ∠2 and ∠5: ∠2 is top-left, ∠5 is bottom-right → they are on opposite sides of transversal, but ∠5 is on the right, while ∠2 is on the left.
So not alternate exterior.
Alternate exterior should be:
- ∠2 and ∠7 (both on left side, one top, one bottom)
- ∠1 and ∠8 (both on right side, one top, one bottom)
So ∠2 and ∠5 are not alternate exterior.
→ False (F)
---
4) ∠4 and ∠6 are alternate interior angles.
- ∠4 is bottom-right (top line), ∠6 is top-left (bottom line)
- Both are inside the parallel lines.
- ∠4 is on the right, ∠6 is on the left → opposite sides of transversal → yes, alternate interior.
Wait: alternate interior angles are:
- ∠3 and ∠6 (both inside, left side)
- ∠4 and ∠5 (both inside, right side)
So ∠4 and ∠6 are on opposite sides of transversal, but both are inside.
But ∠4 is on the right, ∠6 is on the left → so they are on opposite sides → yes, alternate interior.
Wait — let's check:
- Alternate interior: inside, opposite sides.
- ∠4: bottom-right → inside, right side
- ∠6: top-left → inside, left side
Yes → opposite sides, both inside → alternate interior
So yes, they are alternate interior angles.
→ True (T)
Wait — but standard pairs are:
- ∠3 and ∠6: both on left, inside, opposite sides → yes
- ∠4 and ∠5: both on right, inside, opposite sides → yes
But ∠4 and ∠6 are not on the same side — one on right, one on left → so they are not alternate interior.
Wait — alternate interior means on opposite sides of the transversal, and between the lines.
So:
- ∠3 and ∠6: both inside, one on left, one on right → yes → alternate interior
- ∠4 and ∠5: both inside, one on right, one on left → yes → alternate interior
But ∠4 and ∠6: ∠4 is on right, ∠6 is on left → but they are not opposite sides? Actually, they are on opposite sides.
But are they alternate interior?
Wait — ∠4 and ∠6 are not adjacent to the same transversal segment.
Let’s list:
- ∠4: bottom-right at top intersection → inside, right side
- ∠6: top-left at bottom intersection → inside, left side
So they are on opposite sides of the transversal, and both inside → yes, they are alternate interior angles.
But wait — no: alternate interior angles are pairs that are on opposite sides and between the lines.
So:
- ∠3 (bottom-left, top) and ∠6 (top-left, bottom) → both on left side? No.
Wait — confusion.
Standard definition:
- Alternate interior angles: between the two lines, on opposite sides of the transversal.
So:
- ∠3 and ∠6: ∠3 is on left side, ∠6 is on left side → same side → not alternate.
Wait — no:
At top intersection:
- ∠3: bottom-left → inside, left side
- ∠4: bottom-right → inside, right side
At bottom intersection:
- ∠5: top-right → inside, right side
- ∠6: top-left → inside, left side
So:
- ∠3 and ∠6: both on left side of transversal → same side → consecutive interior
- ∠4 and ∠5: both on right side → same side → consecutive interior
Alternate interior:
- ∠3 and ∠5: ∠3 is left, ∠5 is right → opposite sides, both inside → yes
- ∠4 and ∠6: ∠4 is right, ∠6 is left → opposite sides, both inside → yes
So yes, ∠4 and ∠6 are alternate interior angles.
Wait — no: ∠4 is at top, right; ∠6 is at bottom, left.
So they are on opposite sides of transversal, both inside → yes, alternate interior.
But typically, alternate interior angles are named as:
- ∠3 and ∠5
- ∠4 and ∠6
Yes — so ∠4 and ∠6 are alternate interior angles.
So statement 4: True (T)
Wait — but ∠4 and ∠6 are not adjacent — but that’s fine.
Yes, they are alternate interior.
→ True (T)
---
5) ∠3 and ∠6 are consecutive interior angles.
- Consecutive interior angles are same side, inside, and supplementary.
- ∠3: bottom-left at top → inside, left side
- ∠6: top-left at bottom → inside, left side
So both on left side of transversal, and inside → yes, they are consecutive interior angles.
→ True (T)
---
6) ∠3 is congruent to ∠8.
- ∠3: bottom-left at top → inside, left side
- ∠8: top-right at bottom → outside, right side
Are they congruent?
Check relationships:
- ∠3 and ∠8: are they corresponding? No.
- Alternate? ∠3 and ∠8: ∠3 is left, ∠8 is right → opposite sides.
- But ∠3 is inside, ∠8 is outside.
Wait — ∠3 and ∠8: are they alternate exterior? No.
But ∠3 and ∠8: are they vertically opposite? No.
But let’s see:
- ∠3 and ∠6 are vertical angles? No — ∠3 and ∠1 are vertical.
Wait — at top: ∠1 and ∠3 are vertical? No — ∠1 and ∠3 are not adjacent.
Wait — angles around a point:
At top intersection:
- ∠1 and ∠3 are opposite → vertical angles? No — ∠1 and ∠3 are not directly opposite.
Wait — actually:
- ∠1 and ∠3 are vertical angles? No — ∠1 and ∠3 are adjacent.
Wait — correct:
- ∠1 and ∠3 are not vertical — they are adjacent.
Vertical angles are:
- ∠1 and ∠3? No — ∠1 and ∠3 are not opposite.
Actually, in a crossing:
- ∠1 and ∠3 are not vertical.
Wait — the angles are labeled clockwise:
- ∠1 (top-right), ∠2 (top-left), ∠3 (bottom-left), ∠4 (bottom-right)
So:
- ∠1 and ∠3 are not opposite — they are diagonal? No — ∠1 and ∠3 are separated.
Actually, vertical angles are:
- ∠1 and ∠3 → no
- ∠1 and ∠3 are not opposite.
Wait — the correct vertical pairs are:
- ∠1 and ∠3 → no
- ∠1 and ∠3 are not adjacent.
Wait — in a straight line:
At the top intersection:
- ∠1 and ∠2 are adjacent
- ∠2 and ∠3 are adjacent
- ∠3 and ∠4 are adjacent
- ∠4 and ∠1 are adjacent
So vertical angles:
- ∠1 and ∠3 → no — they are not opposite
- Actually, ∠1 and ∠3 are not vertical.
Wait — the diagonally opposite angles are:
- ∠1 and ∠3 → no — ∠1 is top-right, ∠3 is bottom-left → yes, they are diagonally opposite → so vertical angles
Similarly, ∠2 and ∠4 are vertical.
So:
- ∠1 and ∠3 are vertical → equal
- ∠2 and ∠4 are vertical → equal
At bottom:
- ∠5 and ∠7 are vertical
- ∠6 and ∠8 are vertical
Now, back to statement 6: ∠3 ≅ ∠8
- ∠3 and ∠8: are they related?
- ∠3 is at top, bottom-left
- ∠8 is at bottom, top-right
They are not vertical, not corresponding, not alternate.
But let’s see: are they alternate exterior?
- ∠3: inside, left side
- ∠8: outside, right side → no
But ∠3 and ∠8: could they be alternate interior?
No — ∠3 is inside, ∠8 is outside.
Wait — ∠8 is at bottom, top-right → outside.
So ∠3 is inside, ∠8 is outside → not same type.
But are they congruent?
Only if they are corresponding or alternate.
But ∠3 and ∠8 are not corresponding.
Corresponding angles:
- ∠1 and ∠5
- ∠2 and ∠6
- ∠3 and ∠7
- ∠4 and ∠8
Ah! So ∠3 and ∠7 are corresponding → so ∠3 = ∠7
∠4 and ∠8 are corresponding → ∠4 = ∠8
So ∠3 and ∠8 are not corresponding.
But ∠3 and ∠8 are not equal unless specific.
But the question is: is ∠3 congruent to ∠8?
Only if they are corresponding or alternate or vertical.
But they are not.
So generally, no.
But let’s see: ∠3 and ∠8 are not related by any standard rule.
So unless the diagram implies otherwise, we assume general case.
So ∠3 and ∠8 are not necessarily congruent.
But are they?
Wait — ∠3 and ∠8: are they alternate exterior?
- ∠3: inside, left
- ∠8: outside, right → no
No.
But ∠3 and ∠8: are they alternate interior? No.
So no, they are not congruent.
But wait — ∠3 and ∠7 are corresponding → so ∠3 = ∠7
∠8 and ∠6 are vertical → ∠8 = ∠6
But ∠3 and ∠6: are they equal?
Only if the lines are parallel and angles are equal.
But in general, without more info, we can't say ∠3 = ∠8.
But the statement is asking whether ∠3 is congruent to ∠8.
In general, no.
But let’s check: ∠3 and ∠8 are not corresponding, not alternate, not vertical.
So not necessarily congruent.
But the statement says "is congruent" — meaning always?
So answer is False (F)
Wait — but let’s see: is there any relation?
Actually, ∠3 and ∠8: are they alternate exterior?
No.
But ∠3 and ∠8 are not related.
So unless the lines are parallel and angles are set, we cannot assume equality.
But in the context of parallel lines, corresponding angles are equal.
But ∠3 and ∠8 are not corresponding.
So False (F)
Wait — earlier I said ∠4 and ∠8 are corresponding → so ∠4 = ∠8
And ∠3 and ∠4 are supplementary (linear pair), so ∠3 + ∠4 = 180°
So ∠3 + ∠8 = 180° → not equal unless 90°.
So ∠3 ≠ ∠8 in general.
So False (F)
✔ Answer: F
---
---
1) ∠HFC = 75°, ∠HFG = 105°
2) ∠HFC = 38°, ∠DBC = 38°
3) ∠DBC = 144°, ∠EFG = 36°
4) ∠AEH = 118°, ∠DFG = 62°
---
1) ∠1 and ∠2 are vertically opposite angles. → F
2) ∠1 and ∠5 are corresponding angles. → T
3) ∠2 and ∠5 are alternate exterior angles. → F
4) ∠4 and ∠6 are alternate interior angles. → T
5) ∠3 and ∠6 are consecutive interior angles. → T
6) ∠3 is congruent to ∠8. → F
---
A)
1) ∠HFC = 75°, ∠HFG = 105°
2) ∠HFC = 38°, ∠DBC = 38°
3) ∠DBC = 144°, ∠EFG = 36°
4) ∠AEH = 118°, ∠DFG = 62°
B)
1) F
2) T
3) F
4) T
5) T
6) F
---
Part A: Find the measure of each of the specified angles
We'll use properties of parallel lines cut by a transversal, including:
- Corresponding angles are equal.
- Alternate interior angles are equal.
- Alternate exterior angles are equal.
- Consecutive (same-side) interior angles are supplementary (add to 180°).
- Vertical angles are equal.
- Linear pairs add up to 180°.
---
#### Problem 1)
Given:
- Lines AD and EH are parallel (assumed from diagram).
- Transversal CF cuts them.
- ∠BFC = 75°
We need to find:
- ∠HFC
- ∠HFG
##### Step 1: ∠HFC
∠BFC and ∠HFC are vertical angles (they are opposite each other at point F).
So,
> ∠HFC = ∠BFC = 75°
##### Step 2: ∠HFG
∠HFC and ∠HFG form a linear pair (they are adjacent and on a straight line), so they sum to 180°.
> ∠HFG = 180° – ∠HFC = 180° – 75° = 105°
✔ Answer:
- ∠HFC = 75°
- ∠HFG = 105°
---
#### Problem 2)
Given:
- Lines AD and EH are parallel.
- Transversal CG cuts them.
- ∠DBC = 38°
Wait — let’s clarify the notation.
Point B is on AD, and point F is on EH. The angle given is ∠DBC = 38°.
But D–B–C is not a straight line? Wait — actually, looking at the diagram:
- Line AD is horizontal.
- Line CG is the transversal going through B and F.
- ∠DBC is the angle at B between D–B and B–C.
But since AD is a straight line, and CB is going upward, ∠DBC is an angle formed at point B between line AD and transversal BC.
Wait — but we're told ∠DBC = 38°, which is likely the angle at B between DB and BC.
Now, since AD || EH, and transversal is CG, then:
- ∠DBC = 38° → this is an angle between the top line and the transversal.
We need:
- ∠HFC
- ∠DBC
Wait — ∠DBC is already given as 38°, so we just write that.
But let's double-check.
Actually, in the diagram:
- ∠DBC is the angle at B between D–B and B–C → this is interior angle on the right side.
- Since AD || EH, and transversal is CF, then ∠DBC and ∠HFC are corresponding angles?
Wait — let’s analyze.
From the diagram:
- ∠DBC is above the top line AD, on the right side of transversal.
- ∠HFC is below the bottom line EH, on the right side of transversal.
So they are on the same side of the transversal, one above, one below — that makes them corresponding angles only if they are in the same relative position.
Wait — actually, ∠DBC and ∠HFC are not corresponding because they are on different sides.
Let’s look carefully.
Actually, ∠DBC is formed by line AD and transversal BC, and ∠HFC is formed by line EH and transversal FG.
Since AD || EH, and transversal is CF, then:
- ∠DBC and ∠HFC are corresponding angles if they are in the same relative position.
But ∠DBC is above AD and to the right of the transversal.
- ∠HFC is below EH and to the right of the transversal.
So yes — both are on the right side of the transversal, and one above, one below → these are corresponding angles?
No — corresponding angles are in the same relative position — e.g., both upper-right or both lower-left.
But here, ∠DBC is upper-right, and ∠HFC is lower-right → they are not corresponding.
Wait — perhaps better to think about alternate interior or something else.
Alternatively, notice that ∠DBC and ∠BFE are alternate interior angles?
Wait — maybe it's easier to use vertical angles and linear pairs.
Let’s assume:
- ∠DBC = 38° (given)
- Then, since AD is a straight line, and ∠DBC is at B, then the angle adjacent to it (on the other side of the transversal) would be supplementary?
Wait — actually, ∠DBC is part of triangle or just an angle at B.
But looking at the figure: point B is where transversal CF intersects AD.
So ∠DBC is the angle between AD and CF at point B, on the right side.
So ∠DBC = 38° → this is the angle between AD and CF.
Then, since AD || EH, and CF is the transversal, then:
- ∠DBC and ∠HFC are corresponding angles? Let’s see:
- ∠DBC is on the top line, right side of transversal.
- ∠HFC is on the bottom line, right side of transversal.
Yes! So they are corresponding angles → therefore:
> ∠HFC = ∠DBC = 38°
And ∠DBC is given as 38°, so:
> ∠DBC = 38°
✔ Answer:
- ∠HFC = 38°
- ∠DBC = 38°
---
#### Problem 3)
Given:
- Lines AD and EH are parallel.
- Transversal BG cuts them.
- ∠ABF = 36° (at point B)
We need:
- ∠DBC
- ∠EFG
First, ∠ABF = 36° → this is the angle between AB and BF.
Since AD is a straight line, and ∠ABF = 36°, then the adjacent angle ∠FBD (which is ∠DBC) is:
> ∠DBC = 180° – 36° = 144°
Because AB and BD are a straight line (AD), so angles at B on a straight line sum to 180°.
So ∠DBC = 144°
Now, ∠EFG — this is the angle at F between E–F and F–G.
Since AD || EH, and transversal is BG, then:
- ∠ABF and ∠EFG are corresponding angles?
Let’s see:
- ∠ABF is at the top line, left side of transversal.
- ∠EFG is at the bottom line, left side of transversal.
Yes — both are on the left side of the transversal, and above and below respectively.
So they are corresponding angles → therefore:
> ∠EFG = ∠ABF = 36°
✔ Answer:
- ∠DBC = 144°
- ∠EFG = 36°
---
#### Problem 4)
Given:
- Lines AB and CD are parallel.
- Transversal GH cuts them.
- ∠GEB = 62° (angle at E between GE and EB)
We need:
- ∠AEH
- ∠DFG
First, ∠GEB = 62° → this is the angle between transversal GH and line AB at point E.
Since AB || CD, and GH is transversal.
Now, ∠AEH is the angle at E between AE and EH.
Note: AE is part of AB, and EH is part of GH.
So ∠AEH is adjacent to ∠GEB.
Since AB is a straight line, and GH crosses it at E, then:
- ∠AEH and ∠GEB are adjacent angles forming a linear pair.
So:
> ∠AEH = 180° – ∠GEB = 180° – 62° = 118°
Now, ∠DFG — this is at point F on line CD.
We want to find ∠DFG.
Note: ∠GEB = 62° → this is the angle between AB and GH.
Since AB || CD, then corresponding angles are equal.
∠GEB and ∠DFG are both on the right side of the transversal GH, and one is on top (AB), one on bottom (CD).
So they are corresponding angles → thus:
> ∠DFG = ∠GEB = 62°
✔ Answer:
- ∠AEH = 118°
- ∠DFG = 62°
---
Part B: True or False
We have two parallel lines cut by a transversal, with angles labeled 1 through 8.
Labeling convention:
- Top line: angles 1, 2, 3, 4 (clockwise)
- Bottom line: angles 5, 6, 7, 8 (clockwise)
Standard labeling:
- At top intersection: ∠1 (top-right), ∠2 (top-left), ∠3 (bottom-left), ∠4 (bottom-right)
- At bottom intersection: ∠5 (top-right), ∠6 (top-left), ∠7 (bottom-left), ∠8 (bottom-right)
Wait — actually, standard is:
- At top: ∠1 (top-right), ∠2 (top-left), ∠3 (bottom-left), ∠4 (bottom-right)
- At bottom: ∠5 (top-right), ∠6 (top-left), ∠7 (bottom-left), ∠8 (bottom-right)
But in the diagram, the labels are:
- Top: ∠1 (top-right), ∠2 (top-left), ∠3 (bottom-left), ∠4 (bottom-right)
- Bottom: ∠5 (top-right), ∠6 (top-left), ∠7 (bottom-left), ∠8 (bottom-right)
So:
| Angle | Position |
|-------|----------|
| ∠1 | Top-right |
| ∠2 | Top-left |
| ∠3 | Bottom-left |
| ∠4 | Bottom-right |
| ∠5 | Bottom-right (on lower line) |
| ∠6 | Bottom-left (on lower line) |
| ∠7 | Top-left (on lower line) |
| ∠8 | Top-right (on lower line) |
Wait — no — actually, when two lines cross, the four angles around a point are labeled clockwise.
So at the top intersection:
- ∠1: top-right
- ∠2: top-left
- ∠3: bottom-left
- ∠4: bottom-right
At the bottom intersection:
- ∠5: top-right
- ∠6: top-left
- ∠7: bottom-left
- ∠8: bottom-right
But the diagram shows:
- At top: ∠1, ∠2, ∠3, ∠4 (around the top intersection)
- At bottom: ∠5, ∠6, ∠7, ∠8 (around the bottom intersection)
So:
- ∠1 and ∠3 are vertical angles
- ∠2 and ∠4 are vertical angles
- ∠5 and ∠7 are vertical angles
- ∠6 and ∠8 are vertical angles
Also:
- ∠1 and ∠5 are corresponding
- ∠2 and ∠6 are corresponding
- ∠3 and ∠7 are corresponding
- ∠4 and ∠8 are corresponding
Alternate interior:
- ∠3 and ∠6 are alternate interior (both inside, on opposite sides)
- ∠4 and ∠5 are alternate interior
Alternate exterior:
- ∠1 and ∠8
- ∠2 and ∠7
Consecutive interior:
- ∠3 and ∠5
- ∠4 and ∠6
Now evaluate each statement:
---
1) ∠1 and ∠2 are vertically opposite angles.
- No. They are adjacent angles forming a linear pair.
- Vertically opposite would be ∠1 and ∠3, or ∠2 and ∠4.
→ False (F)
---
2) ∠1 and ∠5 are corresponding angles.
- Yes. Both are on the right side of the transversal, and above and below the parallel lines → corresponding angles.
→ True (T)
---
3) ∠2 and ∠5 are alternate exterior angles.
- ∠2 is top-left, ∠5 is bottom-right → not on the same side.
Alternate exterior angles: one on top, one on bottom, on opposite sides of transversal.
- ∠2 (top-left) and ∠8 (bottom-right) → are alternate exterior?
- ∠2 is left side, ∠8 is right side → no.
Wait: alternate exterior angles are:
- ∠2 and ∠7 (both on left side, one top, one bottom) → yes!
- ∠1 and ∠8 (both on right side, one top, one bottom) → yes!
So ∠2 and ∠5: ∠2 is top-left, ∠5 is bottom-right → they are on opposite sides of transversal, but ∠5 is on the right, while ∠2 is on the left.
So not alternate exterior.
Alternate exterior should be:
- ∠2 and ∠7 (both on left side, one top, one bottom)
- ∠1 and ∠8 (both on right side, one top, one bottom)
So ∠2 and ∠5 are not alternate exterior.
→ False (F)
---
4) ∠4 and ∠6 are alternate interior angles.
- ∠4 is bottom-right (top line), ∠6 is top-left (bottom line)
- Both are inside the parallel lines.
- ∠4 is on the right, ∠6 is on the left → opposite sides of transversal → yes, alternate interior.
Wait: alternate interior angles are:
- ∠3 and ∠6 (both inside, left side)
- ∠4 and ∠5 (both inside, right side)
So ∠4 and ∠6 are on opposite sides of transversal, but both are inside.
But ∠4 is on the right, ∠6 is on the left → so they are on opposite sides → yes, alternate interior.
Wait — let's check:
- Alternate interior: inside, opposite sides.
- ∠4: bottom-right → inside, right side
- ∠6: top-left → inside, left side
Yes → opposite sides, both inside → alternate interior
So yes, they are alternate interior angles.
→ True (T)
Wait — but standard pairs are:
- ∠3 and ∠6: both on left, inside, opposite sides → yes
- ∠4 and ∠5: both on right, inside, opposite sides → yes
But ∠4 and ∠6 are not on the same side — one on right, one on left → so they are not alternate interior.
Wait — alternate interior means on opposite sides of the transversal, and between the lines.
So:
- ∠3 and ∠6: both inside, one on left, one on right → yes → alternate interior
- ∠4 and ∠5: both inside, one on right, one on left → yes → alternate interior
But ∠4 and ∠6: ∠4 is on right, ∠6 is on left → but they are not opposite sides? Actually, they are on opposite sides.
But are they alternate interior?
Wait — ∠4 and ∠6 are not adjacent to the same transversal segment.
Let’s list:
- ∠4: bottom-right at top intersection → inside, right side
- ∠6: top-left at bottom intersection → inside, left side
So they are on opposite sides of the transversal, and both inside → yes, they are alternate interior angles.
But wait — no: alternate interior angles are pairs that are on opposite sides and between the lines.
So:
- ∠3 (bottom-left, top) and ∠6 (top-left, bottom) → both on left side? No.
Wait — confusion.
Standard definition:
- Alternate interior angles: between the two lines, on opposite sides of the transversal.
So:
- ∠3 and ∠6: ∠3 is on left side, ∠6 is on left side → same side → not alternate.
Wait — no:
At top intersection:
- ∠3: bottom-left → inside, left side
- ∠4: bottom-right → inside, right side
At bottom intersection:
- ∠5: top-right → inside, right side
- ∠6: top-left → inside, left side
So:
- ∠3 and ∠6: both on left side of transversal → same side → consecutive interior
- ∠4 and ∠5: both on right side → same side → consecutive interior
Alternate interior:
- ∠3 and ∠5: ∠3 is left, ∠5 is right → opposite sides, both inside → yes
- ∠4 and ∠6: ∠4 is right, ∠6 is left → opposite sides, both inside → yes
So yes, ∠4 and ∠6 are alternate interior angles.
Wait — no: ∠4 is at top, right; ∠6 is at bottom, left.
So they are on opposite sides of transversal, both inside → yes, alternate interior.
But typically, alternate interior angles are named as:
- ∠3 and ∠5
- ∠4 and ∠6
Yes — so ∠4 and ∠6 are alternate interior angles.
So statement 4: True (T)
Wait — but ∠4 and ∠6 are not adjacent — but that’s fine.
Yes, they are alternate interior.
→ True (T)
---
5) ∠3 and ∠6 are consecutive interior angles.
- Consecutive interior angles are same side, inside, and supplementary.
- ∠3: bottom-left at top → inside, left side
- ∠6: top-left at bottom → inside, left side
So both on left side of transversal, and inside → yes, they are consecutive interior angles.
→ True (T)
---
6) ∠3 is congruent to ∠8.
- ∠3: bottom-left at top → inside, left side
- ∠8: top-right at bottom → outside, right side
Are they congruent?
Check relationships:
- ∠3 and ∠8: are they corresponding? No.
- Alternate? ∠3 and ∠8: ∠3 is left, ∠8 is right → opposite sides.
- But ∠3 is inside, ∠8 is outside.
Wait — ∠3 and ∠8: are they alternate exterior? No.
But ∠3 and ∠8: are they vertically opposite? No.
But let’s see:
- ∠3 and ∠6 are vertical angles? No — ∠3 and ∠1 are vertical.
Wait — at top: ∠1 and ∠3 are vertical? No — ∠1 and ∠3 are not adjacent.
Wait — angles around a point:
At top intersection:
- ∠1 and ∠3 are opposite → vertical angles? No — ∠1 and ∠3 are not directly opposite.
Wait — actually:
- ∠1 and ∠3 are vertical angles? No — ∠1 and ∠3 are adjacent.
Wait — correct:
- ∠1 and ∠3 are not vertical — they are adjacent.
Vertical angles are:
- ∠1 and ∠3? No — ∠1 and ∠3 are not opposite.
Actually, in a crossing:
- ∠1 and ∠3 are not vertical.
Wait — the angles are labeled clockwise:
- ∠1 (top-right), ∠2 (top-left), ∠3 (bottom-left), ∠4 (bottom-right)
So:
- ∠1 and ∠3 are not opposite — they are diagonal? No — ∠1 and ∠3 are separated.
Actually, vertical angles are:
- ∠1 and ∠3 → no
- ∠1 and ∠3 are not opposite.
Wait — the correct vertical pairs are:
- ∠1 and ∠3 → no
- ∠1 and ∠3 are not adjacent.
Wait — in a straight line:
At the top intersection:
- ∠1 and ∠2 are adjacent
- ∠2 and ∠3 are adjacent
- ∠3 and ∠4 are adjacent
- ∠4 and ∠1 are adjacent
So vertical angles:
- ∠1 and ∠3 → no — they are not opposite
- Actually, ∠1 and ∠3 are not vertical.
Wait — the diagonally opposite angles are:
- ∠1 and ∠3 → no — ∠1 is top-right, ∠3 is bottom-left → yes, they are diagonally opposite → so vertical angles
Similarly, ∠2 and ∠4 are vertical.
So:
- ∠1 and ∠3 are vertical → equal
- ∠2 and ∠4 are vertical → equal
At bottom:
- ∠5 and ∠7 are vertical
- ∠6 and ∠8 are vertical
Now, back to statement 6: ∠3 ≅ ∠8
- ∠3 and ∠8: are they related?
- ∠3 is at top, bottom-left
- ∠8 is at bottom, top-right
They are not vertical, not corresponding, not alternate.
But let’s see: are they alternate exterior?
- ∠3: inside, left side
- ∠8: outside, right side → no
But ∠3 and ∠8: could they be alternate interior?
No — ∠3 is inside, ∠8 is outside.
Wait — ∠8 is at bottom, top-right → outside.
So ∠3 is inside, ∠8 is outside → not same type.
But are they congruent?
Only if they are corresponding or alternate.
But ∠3 and ∠8 are not corresponding.
Corresponding angles:
- ∠1 and ∠5
- ∠2 and ∠6
- ∠3 and ∠7
- ∠4 and ∠8
Ah! So ∠3 and ∠7 are corresponding → so ∠3 = ∠7
∠4 and ∠8 are corresponding → ∠4 = ∠8
So ∠3 and ∠8 are not corresponding.
But ∠3 and ∠8 are not equal unless specific.
But the question is: is ∠3 congruent to ∠8?
Only if they are corresponding or alternate or vertical.
But they are not.
So generally, no.
But let’s see: ∠3 and ∠8 are not related by any standard rule.
So unless the diagram implies otherwise, we assume general case.
So ∠3 and ∠8 are not necessarily congruent.
But are they?
Wait — ∠3 and ∠8: are they alternate exterior?
- ∠3: inside, left
- ∠8: outside, right → no
No.
But ∠3 and ∠8: are they alternate interior? No.
So no, they are not congruent.
But wait — ∠3 and ∠7 are corresponding → so ∠3 = ∠7
∠8 and ∠6 are vertical → ∠8 = ∠6
But ∠3 and ∠6: are they equal?
Only if the lines are parallel and angles are equal.
But in general, without more info, we can't say ∠3 = ∠8.
But the statement is asking whether ∠3 is congruent to ∠8.
In general, no.
But let’s check: ∠3 and ∠8 are not corresponding, not alternate, not vertical.
So not necessarily congruent.
But the statement says "is congruent" — meaning always?
So answer is False (F)
Wait — but let’s see: is there any relation?
Actually, ∠3 and ∠8: are they alternate exterior?
No.
But ∠3 and ∠8 are not related.
So unless the lines are parallel and angles are set, we cannot assume equality.
But in the context of parallel lines, corresponding angles are equal.
But ∠3 and ∠8 are not corresponding.
So False (F)
Wait — earlier I said ∠4 and ∠8 are corresponding → so ∠4 = ∠8
And ∠3 and ∠4 are supplementary (linear pair), so ∠3 + ∠4 = 180°
So ∠3 + ∠8 = 180° → not equal unless 90°.
So ∠3 ≠ ∠8 in general.
So False (F)
✔ Answer: F
---
✔ Final Answers
---
Part A
1) ∠HFC = 75°, ∠HFG = 105°
2) ∠HFC = 38°, ∠DBC = 38°
3) ∠DBC = 144°, ∠EFG = 36°
4) ∠AEH = 118°, ∠DFG = 62°
---
Part B
1) ∠1 and ∠2 are vertically opposite angles. → F
2) ∠1 and ∠5 are corresponding angles. → T
3) ∠2 and ∠5 are alternate exterior angles. → F
4) ∠4 and ∠6 are alternate interior angles. → T
5) ∠3 and ∠6 are consecutive interior angles. → T
6) ∠3 is congruent to ∠8. → F
---
✔ Boxed Final Answer:
A)
1) ∠HFC = 75°, ∠HFG = 105°
2) ∠HFC = 38°, ∠DBC = 38°
3) ∠DBC = 144°, ∠EFG = 36°
4) ∠AEH = 118°, ∠DFG = 62°
B)
1) F
2) T
3) F
4) T
5) T
6) F
Parent Tip: Review the logic above to help your child master the concept of parallel lines transversal worksheet.