Division with Partial Quotients Worksheet Download - Free Printable

Problem: Solve each division problem using the partial quotients method.

The worksheet provides a series of division problems, and the solutions are already filled in. Below, I will explain the process for solving each problem step by step using the partial quotients method.

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#### 1. \( 9 \div 89 \)

- Dividend: 89
- Divisor: 9

Steps:
1. Estimate how many times 9 goes into 89. A good estimate is 9 (since \( 9 \times 9 = 81 \)).
2. Subtract \( 81 \) from 89:
\[
89 - 81 = 8
\]
3. The remainder is 8, which is less than the divisor (9).

Answer: \( 9 \text{ R } 8 \)

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#### 2. \( 4 \div 240 \)

- Dividend: 240
- Divisor: 4

Steps:
1. Estimate how many times 4 goes into 240. A good estimate is 60 (since \( 4 \times 60 = 240 \)).
2. Subtract \( 240 \) from 240:
\[
240 - 240 = 0
\]
3. The remainder is 0.

Answer: \( 60 \)

---

#### 3. \( 2 \div 151 \)

- Dividend: 151
- Divisor: 2

Steps:
1. Estimate how many times 2 goes into 151. A good estimate is 70 (since \( 2 \times 70 = 140 \)).
2. Subtract \( 140 \) from 151:
\[
151 - 140 = 11
\]
3. Next, estimate how many times 2 goes into 11. A good estimate is 5 (since \( 2 \times 5 = 10 \)).
4. Subtract \( 10 \) from 11:
\[
11 - 10 = 1
\]
5. The remainder is 1.

Answer: \( 75 \text{ R } 1 \)

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#### 4. \( 3 \div 21 \)

- Dividend: 21
- Divisor: 3

Steps:
1. Estimate how many times 3 goes into 21. A good estimate is 7 (since \( 3 \times 7 = 21 \)).
2. Subtract \( 21 \) from 21:
\[
21 - 21 = 0
\]
3. The remainder is 0.

Answer: \( 7 \)

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#### 5. \( 2 \div 47 \)

- Dividend: 47
- Divisor: 2

Steps:
1. Estimate how many times 2 goes into 47. A good estimate is 23 (since \( 2 \times 23 = 46 \)).
2. Subtract \( 46 \) from 47:
\[
47 - 46 = 1
\]
3. The remainder is 1.

Answer: \( 23 \text{ R } 1 \)

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#### 6. \( 8 \div 936 \)

- Dividend: 936
- Divisor: 8

Steps:
1. Estimate how many times 8 goes into 936. A good estimate is 100 (since \( 8 \times 100 = 800 \)).
2. Subtract \( 800 \) from 936:
\[
936 - 800 = 136
\]
3. Next, estimate how many times 8 goes into 136. A good estimate is 10 (since \( 8 \times 10 = 80 \)).
4. Subtract \( 80 \) from 136:
\[
136 - 80 = 56
\]
5. Finally, estimate how many times 8 goes into 56. A good estimate is 7 (since \( 8 \times 7 = 56 \)).
6. Subtract \( 56 \) from 56:
\[
56 - 56 = 0
\]
7. The remainder is 0.

Answer: \( 117 \)

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#### 7. \( 7 \div 101 \)

- Dividend: 101
- Divisor: 7

Steps:
1. Estimate how many times 7 goes into 101. A good estimate is 14 (since \( 7 \times 14 = 98 \)).
2. Subtract \( 98 \) from 101:
\[
101 - 98 = 3
\]
3. The remainder is 3.

Answer: \( 14 \text{ R } 3 \)

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#### 8. \( 8 \div 9 \)

- Dividend: 9
- Divisor: 8

Steps:
1. Estimate how many times 8 goes into 9. A good estimate is 1 (since \( 8 \times 1 = 8 \)).
2. Subtract \( 8 \) from 9:
\[
9 - 8 = 1
\]
3. The remainder is 1.

Answer: \( 1 \text{ R } 1 \)

---

#### 9. \( 6 \div 21 \)

- Dividend: 21
- Divisor: 6

Steps:
1. Estimate how many times 6 goes into 21. A good estimate is 3 (since \( 6 \times 3 = 18 \)).
2. Subtract \( 18 \) from 21:
\[
21 - 18 = 3
\]
3. The remainder is 3.

Answer: \( 3 \text{ R } 3 \)

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Final Answer:

\[
\boxed{9 \text{ R } 8, 60, 75 \text{ R } 1, 7, 23 \text{ R } 1, 117, 14 \text{ R } 3, 1 \text{ R } 1, 3 \text{ R } 3}
\]