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Grade 5 Order of Operations Worksheet focusing on PEMDAS with nested parentheses.

PEMDAS with nested parenthesis worksheet for Grade 5, featuring math problems involving order of operations with exponents and parentheses.

PEMDAS with nested parenthesis worksheet for Grade 5, featuring math problems involving order of operations with exponents and parentheses.

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Show Answer Key & Explanations Step-by-step solution for: Grade 5 PEMDAS Worksheets | Worsheets library | Worsheets library
Explanation:
We are solving 10 problems involving the order of operations, especially with nested parentheses. Remember PEMDAS:
Parentheses → Exponents → Multiplication & Division (left to right) → Addition & Subtraction (left to right).

Let’s solve each one step by step.

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1) $ 6^2 - (32 - 29)^2 $

- Inside parentheses: $32 - 29 = 3$
- Exponents: $6^2 = 36$, and $3^2 = 9$
- Then: $36 - 9 = 27$

Answer: 27

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2) $ [(21 - 17) \times (14 - 9)]^2 $

- Inner parentheses: $21 - 17 = 4$, $14 - 9 = 5$
- Multiply: $4 \times 5 = 20$
- Square: $20^2 = 400$

Answer: 400

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3) $ 11^2 - 3 \times 8 - 5^2 - 19 $

- Exponents first: $11^2 = 121$, $5^2 = 25$
- Multiplication: $3 \times 8 = 24$
- Now: $121 - 24 - 25 - 19$
- Left to right:
- $121 - 24 = 97$
- $97 - 25 = 72$
- $72 - 19 = 53$

Answer: 53

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4) $ 11^2 - \{3 \times [8 - (5^2 - 19)]\} $

- Innermost: $5^2 = 25$, so $25 - 19 = 6$
- Next: $8 - 6 = 2$
- Then: $3 \times 2 = 6$
- $11^2 = 121$
- Finally: $121 - 6 = 115$

Answer: 115

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5) $ 11^2 - [3 \times (8 - 5)^2] - 19 $

- Inside parentheses: $8 - 5 = 3$
- Square it: $3^2 = 9$
- Multiply: $3 \times 9 = 27$
- $11^2 = 121$
- So: $121 - 27 - 19$
- $121 - 27 = 94$
- $94 - 19 = 75$

Answer: 75

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6) $ 12 \times (3 + 11 + 6) - 2^3 $

- Parentheses: $3 + 11 + 6 = 20$
- Multiply: $12 \times 20 = 240$
- Exponent: $2^3 = 8$
- Subtract: $240 - 8 = 232$

Answer: 232

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7) $ 4^2 + 2^2 \times [40 + (31 - 29)^2] $

- Innermost: $31 - 29 = 2$, then $2^2 = 4$
- Inside brackets: $40 + 4 = 44$
- Exponents: $4^2 = 16$, $2^2 = 4$
- Multiply: $4 \times 44 = 176$
- Add: $16 + 176 = 192$

Answer: 192

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8) $ 1^3 \times \{9 + [(9 - 21 + 7) - (2^2 - 5)]\} $

- First, $1^3 = 1$, so we can ignore multiplying by 1 until the end.
- Inside innermost:
- $9 - 21 + 7 = (9 + 7) - 21 = 16 - 21 = -5$
- $2^2 = 4$, so $4 - 5 = -1$
- Now: $(-5) - (-1) = -5 + 1 = -4$
- Then: $9 + (-4) = 5$
- Finally: $1 \times 5 = 5$

Answer: 5

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9) $ 10^2 \times 9 - (4^2 - 4 \times 10) $

- $10^2 = 100$, so $100 \times 9 = 900$
- Inside parentheses:
- $4^2 = 16$
- $4 \times 10 = 40$
- So: $16 - 40 = -24$
- Now: $900 - (-24) = 900 + 24 = 924$

Answer: 924

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10) $ 4^2 + 3^2 - [2 \times (11 + 9 - 13)] $

- Exponents: $4^2 = 16$, $3^2 = 9$ → sum so far: $16 + 9 = 25$
- Inside parentheses: $11 + 9 = 20$, $20 - 13 = 7$
- Multiply: $2 \times 7 = 14$
- Subtract: $25 - 14 = 11$

Answer: 11

Now double-check all answers quickly:

1) 27
2) 400
3) 53
4) 115
5) 75
6) 232
7) 192
8) 5
9) 924
10) 11

All look correct.

Final Answer:
27, 400, 53, 115, 75, 232, 192, 5, 924, 11
Parent Tip: Review the logic above to help your child master the concept of pemdas worksheet for 5th graders.
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