Area & Perimeter word problems for Grade 4 - Free Printable
Educational worksheet: Area & Perimeter word problems for Grade 4. Download and print for classroom or home learning activities.
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Step-by-step solution for: Area & Perimeter word problems for Grade 4
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Show Answer Key & Explanations
Step-by-step solution for: Area & Perimeter word problems for Grade 4
Let's solve each problem step by step.
---
A rectangle's perimeter is 34 meters. The rectangle is 15 meters long. What is its width?
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Perimeter \( P = 34 \) meters
- Length = 15 meters
Substitute the known values into the formula:
\[
34 = 2 \times (15 + \text{width})
\]
Divide both sides by 2:
\[
17 = 15 + \text{width}
\]
Subtract 15 from both sides:
\[
\text{width} = 2 \text{ meters}
\]
Answer:
\[
\boxed{2}
\]
---
The park is 50 meters long and 15 meters wide. Find its perimeter.
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length = 50 meters
- Width = 15 meters
Substitute the known values into the formula:
\[
P = 2 \times (50 + 15)
\]
Simplify inside the parentheses:
\[
P = 2 \times 65
\]
Multiply:
\[
P = 130 \text{ meters}
\]
Answer:
\[
\boxed{130}
\]
---
A rectangular piece of cake is 15 centimeters long and 6 centimeters wide. What is its perimeter?
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length = 15 cm
- Width = 6 cm
Substitute the known values into the formula:
\[
P = 2 \times (15 + 6)
\]
Simplify inside the parentheses:
\[
P = 2 \times 21
\]
Multiply:
\[
P = 42 \text{ cm}
\]
Answer:
\[
\boxed{42}
\]
---
A mobile phone is 5 cm wide and 10 cm long. What is its perimeter?
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length = 10 cm
- Width = 5 cm
Substitute the known values into the formula:
\[
P = 2 \times (10 + 5)
\]
Simplify inside the parentheses:
\[
P = 2 \times 15
\]
Multiply:
\[
P = 30 \text{ cm}
\]
Answer:
\[
\boxed{30}
\]
---
A square has sides that are 6 feet long. What is the area of the square?
#### Solution:
The formula for the area of a square is:
\[
A = \text{side}^2
\]
Given:
- Side = 6 feet
Substitute the known value into the formula:
\[
A = 6^2
\]
Calculate:
\[
A = 36 \text{ square feet}
\]
Answer:
\[
\boxed{36}
\]
---
A rectangular table is 18 centimeters long and 4 centimeters wide. What is its perimeter?
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length = 18 cm
- Width = 4 cm
Substitute the known values into the formula:
\[
P = 2 \times (18 + 4)
\]
Simplify inside the parentheses:
\[
P = 2 \times 22
\]
Multiply:
\[
P = 44 \text{ cm}
\]
Answer:
\[
\boxed{44}
\]
---
1. \(\boxed{2}\)
2. \(\boxed{130}\)
3. \(\boxed{42}\)
4. \(\boxed{30}\)
5. \(\boxed{36}\)
6. \(\boxed{44}\)
---
Problem 1:
A rectangle's perimeter is 34 meters. The rectangle is 15 meters long. What is its width?
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Perimeter \( P = 34 \) meters
- Length = 15 meters
Substitute the known values into the formula:
\[
34 = 2 \times (15 + \text{width})
\]
Divide both sides by 2:
\[
17 = 15 + \text{width}
\]
Subtract 15 from both sides:
\[
\text{width} = 2 \text{ meters}
\]
Answer:
\[
\boxed{2}
\]
---
Problem 2:
The park is 50 meters long and 15 meters wide. Find its perimeter.
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length = 50 meters
- Width = 15 meters
Substitute the known values into the formula:
\[
P = 2 \times (50 + 15)
\]
Simplify inside the parentheses:
\[
P = 2 \times 65
\]
Multiply:
\[
P = 130 \text{ meters}
\]
Answer:
\[
\boxed{130}
\]
---
Problem 3:
A rectangular piece of cake is 15 centimeters long and 6 centimeters wide. What is its perimeter?
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length = 15 cm
- Width = 6 cm
Substitute the known values into the formula:
\[
P = 2 \times (15 + 6)
\]
Simplify inside the parentheses:
\[
P = 2 \times 21
\]
Multiply:
\[
P = 42 \text{ cm}
\]
Answer:
\[
\boxed{42}
\]
---
Problem 4:
A mobile phone is 5 cm wide and 10 cm long. What is its perimeter?
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length = 10 cm
- Width = 5 cm
Substitute the known values into the formula:
\[
P = 2 \times (10 + 5)
\]
Simplify inside the parentheses:
\[
P = 2 \times 15
\]
Multiply:
\[
P = 30 \text{ cm}
\]
Answer:
\[
\boxed{30}
\]
---
Problem 5:
A square has sides that are 6 feet long. What is the area of the square?
#### Solution:
The formula for the area of a square is:
\[
A = \text{side}^2
\]
Given:
- Side = 6 feet
Substitute the known value into the formula:
\[
A = 6^2
\]
Calculate:
\[
A = 36 \text{ square feet}
\]
Answer:
\[
\boxed{36}
\]
---
Problem 6:
A rectangular table is 18 centimeters long and 4 centimeters wide. What is its perimeter?
#### Solution:
The formula for the perimeter of a rectangle is:
\[
P = 2 \times (\text{length} + \text{width})
\]
Given:
- Length = 18 cm
- Width = 4 cm
Substitute the known values into the formula:
\[
P = 2 \times (18 + 4)
\]
Simplify inside the parentheses:
\[
P = 2 \times 22
\]
Multiply:
\[
P = 44 \text{ cm}
\]
Answer:
\[
\boxed{44}
\]
---
Final Answers:
1. \(\boxed{2}\)
2. \(\boxed{130}\)
3. \(\boxed{42}\)
4. \(\boxed{30}\)
5. \(\boxed{36}\)
6. \(\boxed{44}\)
Parent Tip: Review the logic above to help your child master the concept of perimeter worksheet for grade 4.