To solve the problem, we need to count the beads on each abacus and determine their place values. Then, we will compare the values using the symbols `<`, `>`, or `=`.
Step-by-Step Solution:
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Understanding the Abacus:
- Each vertical rod represents a place value (units, tens, hundreds, etc.).
- Beads above the horizontal bar are worth 5 units each.
- Beads below the horizontal bar are worth 1 unit each.
####
Counting Beads and Determining Place Values:
We will analyze each pair of abacuses row by row.
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Row 1:
1.
Left Abacus:
- Units place: 3 beads below the bar → 3
- Tens place: 2 beads below the bar → 20
- Total: \( 20 + 3 = 23 \)
2.
Right Abacus:
- Units place: 4 beads below the bar → 4
- Tens place: 2 beads below the bar → 20
- Total: \( 20 + 4 = 24 \)
3.
Comparison:
- \( 23 < 24 \)
---
Row 2:
1.
Left Abacus:
- Units place: 5 beads above the bar → 5
- Tens place: 1 bead above the bar → 50
- Total: \( 50 + 5 = 55 \)
2.
Right Abacus:
- Units place: 3 beads below the bar → 3
- Tens place: 3 beads below the bar → 30
- Total: \( 30 + 3 = 33 \)
3.
Comparison:
- \( 55 > 33 \)
---
Row 3:
1.
Left Abacus:
- Units place: 2 beads below the bar → 2
- Tens place: 1 bead above the bar and 3 beads below the bar → 50 + 30 = 80
- Total: \( 80 + 2 = 82 \)
2.
Right Abacus:
- Units place: 4 beads below the bar → 4
- Tens place: 1 bead above the bar and 2 beads below the bar → 50 + 20 = 70
- Total: \( 70 + 4 = 74 \)
3.
Comparison:
- \( 82 > 74 \)
---
Row 4:
1.
Left Abacus:
- Units place: 1 bead above the bar and 3 beads below the bar → 5 + 3 = 8
- Tens place: 1 bead above the bar → 50
- Total: \( 50 + 8 = 58 \)
2.
Right Abacus:
- Units place: 6 beads below the bar → 6
- Tens place: 2 beads above the bar → 100
- Total: \( 100 + 6 = 106 \)
3.
Comparison:
- \( 58 < 106 \)
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Final Answer:
The comparisons for each row are:
1. \( 23 < 24 \)
2. \( 55 > 33 \)
3. \( 82 > 74 \)
4. \( 58 < 106 \)
Thus, the final answer is:
\[
\boxed{<, >, >, <}
\]
Parent Tip: Review the logic above to help your child master the concept of place value worksheet abacus.
