Balancing Equations Practice Worksheet featuring ten chemical equations to solve.

Here are the balanced chemical equations for the practice worksheet. I have worked through each one step-by-step to ensure the number of atoms for every element is the same on both sides.

1) $\text{NaNO}_3 + \text{PbO} \rightarrow \text{Pb(NO}_3)_2 + \text{Na}_2\text{O}$
* Step 1: Balance Sodium (Na). There are 2 Na on the right, so put a 2 in front of $\text{NaNO}_3$.
* $2\text{NaNO}_3 + \text{PbO} \rightarrow \text{Pb(NO}_3)_2 + \text{Na}_2\text{O}$
* Check:
* Na: 2 left, 2 right.
* N: 2 left, 2 right.
* O: $6 + 1 = 7$ left, $6 + 1 = 7$ right.
* Pb: 1 left, 1 right.
* Result: Balanced.

2) $\text{AgI} + \text{Fe}_2(\text{CO}_3)_3 \rightarrow \text{FeI}_3 + \text{Ag}_2\text{CO}_3$
* Step 1: Balance Iron (Fe). There are 2 Fe on the left, so put a 2 in front of $\text{FeI}_3$.
* $\text{AgI} + \text{Fe}_2(\text{CO}_3)_3 \rightarrow 2\text{FeI}_3 + \text{Ag}_2\text{CO}_3$
* Step 2: Balance Iodine (I). There are now $2 \times 3 = 6$ I on the right, so put a 6 in front of AgI.
* $6\text{AgI} + \text{Fe}_2(\text{CO}_3)_3 \rightarrow 2\text{FeI}_3 + \text{Ag}_2\text{CO}_3$
* Step 3: Balance Silver (Ag). There are 6 Ag on the left, so put a 3 in front of $\text{Ag}_2\text{CO}_3$ ($3 \times 2 = 6$).
* $6\text{AgI} + \text{Fe}_2(\text{CO}_3)_3 \rightarrow 2\text{FeI}_3 + 3\text{Ag}_2\text{CO}_3$
* Check: Carbonate ($\text{CO}_3$) is 3 on both sides. Everything matches.

3) $\text{C}_2\text{H}_4\text{O}_2 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O}$
* Step 1: Balance Carbon (C). Put a 2 in front of $\text{CO}_2$.
* $\text{C}_2\text{H}_4\text{O}_2 + \text{O}_2 \rightarrow 2\text{CO}_2 + \text{H}_2\text{O}$
* Step 2: Balance Hydrogen (H). Put a 2 in front of $\text{H}_2\text{O}$.
* $\text{C}_2\text{H}_4\text{O}_2 + \text{O}_2 \rightarrow 2\text{CO}_2 + 2\text{H}_2\text{O}$
* Step 3: Balance Oxygen (O). Right side has $(2 \times 2) + (2 \times 1) = 6$ oxygens. Left side has 2 in the first molecule, so we need 4 more from $\text{O}_2$. Put a 2 in front of $\text{O}_2$.
* $\text{C}_2\text{H}_4\text{O}_2 + 2\text{O}_2 \rightarrow 2\text{CO}_2 + 2\text{H}_2\text{O}$

4) $\text{ZnSO}_4 + \text{Li}_2\text{CO}_3 \rightarrow \text{ZnCO}_3 + \text{Li}_2\text{SO}_4$
* Check:
* Zn: 1 left, 1 right.
* Sulfate ($\text{SO}_4$): 1 left, 1 right.
* Li: 2 left, 2 right.
* Carbonate ($\text{CO}_3$): 1 left, 1 right.
* Result: Already balanced. Coefficients are all 1.

5) $\text{V}_2\text{O}_5 + \text{CaS} \rightarrow \text{CaO} + \text{V}_2\text{S}_5$
* Step 1: Balance Sulfur (S). There are 5 S on the right, so put a 5 in front of CaS.
* $\text{V}_2\text{O}_5 + 5\text{CaS} \rightarrow \text{CaO} + \text{V}_2\text{S}_5$
* Step 2: Balance Calcium (Ca). There are 5 Ca on the left, so put a 5 in front of CaO.
* $\text{V}_2\text{O}_5 + 5\text{CaS} \rightarrow 5\text{CaO} + \text{V}_2\text{S}_5$
* Check: Oxygen is 5 on both sides. Vanadium is 2 on both sides.

6) $\text{Mn(NO}_2)_2 + \text{BeCl}_2 \rightarrow \text{Be(NO}_2)_2 + \text{MnCl}_2$
* Check:
* Mn: 1 left, 1 right.
* Nitrite ($\text{NO}_2$): 2 left, 2 right.
* Be: 1 left, 1 right.
* Cl: 2 left, 2 right.
* Result: Already balanced. Coefficients are all 1.

7) $\text{AgBr} + \text{GaPO}_4 \rightarrow \text{Ag}_3\text{PO}_4 + \text{GaBr}_3$
* Step 1: Balance Silver (Ag). There are 3 Ag on the right, so put a 3 in front of AgBr.
* $3\text{AgBr} + \text{GaPO}_4 \rightarrow \text{Ag}_3\text{PO}_4 + \text{GaBr}_3$
* Check:
* Br: 3 left, 3 right.
* Ga: 1 left, 1 right.
* Phosphate ($\text{PO}_4$): 1 left, 1 right.

8) $\text{H}_2\text{SO}_4 + \text{B(OH)}_3 \rightarrow \text{B}_2(\text{SO}_4)_3 + \text{H}_2\text{O}$
* Step 1: Balance Boron (B). Put a 2 in front of $\text{B(OH)}_3$.
* $\text{H}_2\text{SO}_4 + 2\text{B(OH)}_3 \rightarrow \text{B}_2(\text{SO}_4)_3 + \text{H}_2\text{O}$
* Step 2: Balance Sulfate ($\text{SO}_4$). There are 3 on the right, so put a 3 in front of $\text{H}_2\text{SO}_4$.
* $3\text{H}_2\text{SO}_4 + 2\text{B(OH)}_3 \rightarrow \text{B}_2(\text{SO}_4)_3 + \text{H}_2\text{O}$
* Step 3: Balance Hydrogen (H). Left side has $(3 \times 2) + (2 \times 3) = 12$ H. Right side needs 12 H, so put a 6 in front of $\text{H}_2\text{O}$.
* $3\text{H}_2\text{SO}_4 + 2\text{B(OH)}_3 \rightarrow \text{B}_2(\text{SO}_4)_3 + 6\text{H}_2\text{O}$
* Check: Oxygen count: Left $(3 \times 4) + (2 \times 3) = 18$. Right $(3 \times 4) + 6 = 18$. Correct.

9) $\text{S}_8 + \text{O}_2 \rightarrow \text{SO}_2$
* Step 1: Balance Sulfur (S). There are 8 S on the left, so put an 8 in front of $\text{SO}_2$.
* $\text{S}_8 + \text{O}_2 \rightarrow 8\text{SO}_2$
* Step 2: Balance Oxygen (O). Right side has $8 \times 2 = 16$ O. Left side needs 16 O, so put an 8 in front of $\text{O}_2$.
* $\text{S}_8 + 8\text{O}_2 \rightarrow 8\text{SO}_2$

10) $\text{Fe} + \text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + \text{Ag}$
* Step 1: Balance Nitrate ($\text{NO}_3$). There are 2 on the right, so put a 2 in front of $\text{AgNO}_3$.
* $\text{Fe} + 2\text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + \text{Ag}$
* Step 2: Balance Silver (Ag). There are 2 Ag on the left, so put a 2 in front of Ag.
* $\text{Fe} + 2\text{AgNO}_3 \rightarrow \text{Fe(NO}_3)_2 + 2\text{Ag}$

Final Answer:
1) 2 $\text{NaNO}_3 +$ 1 $\text{PbO} \rightarrow$ 1 $\text{Pb(NO}_3)_2 +$ 1 $\text{Na}_2\text{O}$
2) 6 $\text{AgI} +$ 1 $\text{Fe}_2(\text{CO}_3)_3 \rightarrow$ 2 $\text{FeI}_3 +$ 3 $\text{Ag}_2\text{CO}_3$
3) 1 $\text{C}_2\text{H}_4\text{O}_2 +$ 2 $\text{O}_2 \rightarrow$ 2 $\text{CO}_2 +$ 2 $\text{H}_2\text{O}$
4) 1 $\text{ZnSO}_4 +$ 1 $\text{Li}_2\text{CO}_3 \rightarrow$ 1 $\text{ZnCO}_3 +$ 1 $\text{Li}_2\text{SO}_4$
5) 1 $\text{V}_2\text{O}_5 +$ 5 $\text{CaS} \rightarrow$ 5 $\text{CaO} +$ 1 $\text{V}_2\text{S}_5$
6) 1 $\text{Mn(NO}_2)_2 +$ 1 $\text{BeCl}_2 \rightarrow$ 1 $\text{Be(NO}_2)_2 +$ 1 $\text{MnCl}_2$
7) 3 $\text{AgBr} +$ 1 $\text{GaPO}_4 \rightarrow$ 1 $\text{Ag}_3\text{PO}_4 +$ 1 $\text{GaBr}_3$
8) 3 $\text{H}_2\text{SO}_4 +$ 2 $\text{B(OH)}_3 \rightarrow$ 1 $\text{B}_2(\text{SO}_4)_3 +$ 6 $\text{H}_2\text{O}$
9) 1 $\text{S}_8 +$ 8 $\text{O}_2 \rightarrow$ 8 $\text{SO}_2$
10) 1 $\text{Fe} +$ 2 $\text{AgNO}_3 \rightarrow$ 1 $\text{Fe(NO}_3)_2 +$ 2 $\text{Ag}$