Printable Boggle {{Freebie}} - Free Printable

Explanation:
We are given two 4×4 letter grids. The goal is to find words that can be formed by connecting adjacent letters (horizontally, vertically, or diagonally), like in the game Boggle.

Let’s examine the first grid:

```
p l a m
n e r y
t v w i
e g h b
```

We look for real English words of 3+ letters. Let’s scan systematically:

- Starting at p: p-l-a = “pla” (not a word), p-l-n = “pln” (no), p-l-e = “ple” → “ple” isn’t a word, but “plan” is!
p → l → a → n? Wait: p(0,0), l(0,1), a(0,2), n(1,0) — not adjacent (a to n is diagonal down-left from (0,2) to (1,0)? That’s 2 columns left and 1 down — not adjacent. Adjacent means sharing a side or corner: max 1 step in row and column.

So valid moves: from any cell, you can go to any of the 8 surrounding cells (if they exist).

Let’s list possible words:

Grid 1:
Row 0: p l a m
Row 1: n e r y
Row 2: t v w i
Row 3: e g h b

Try “man”: m(0,3) → a(0,2) → n(1,0)? No — a to n is not adjacent (a is (0,2), n is (1,0): Δrow=1, Δcol=−2 → invalid).
But m(0,3) → a(0,2) → r(1,2) = “mar” — yes! m→a→r is valid: (0,3)→(0,2)→(1,2). “mar” is a word.

Also: a(0,2) → r(1,2) → y(1,3) = “ary” — valid, and “ary” is a suffix, but often accepted in Boggle as part of words; however, we want full words. Let’s aim for real standalone words.

What about “play”? p(0,0) → l(0,1) → a(0,2) → y(1,3)? Path: p→l→a is fine, a to y is (0,2)→(1,3): Δrow=1, Δcol=1 → diagonal, allowed. So p-l-a-y = “play” ✔

Yes! “play” is a 4-letter word, all letters adjacent step-by-step.

Also: “near”? n(1,0) → e(1,1) → a(0,2) → r(1,2):
n(1,0) → e(1,1) ✔
e(1,1) → a(0,2): Δrow=−1, Δcol=+1 → diagonal ✔
a(0,2) → r(1,2): down ✔
So “near” ✔

Also: “war”: w(2,2) → a(0,2)? No, too far. w(2,2) → r(1,2) → e(1,1) = “wre”? Not a word.
w(2,2) → i(2,3) → y(1,3) = “wiy” no.

How about “the”? t(2,0) → h(3,2)? Not adjacent. t(2,0) → e(3,0) = “te”, then e→g? “teg” no.
t(2,0) → v(2,1) → e(1,1) = “tve” no.
But t(2,0) → e(3,0) → g(3,1) = “teg” no.

Wait — what about “leg”? l(0,1) → e(1,1) → g(3,1)? No, e to g is (1,1)→(3,1): Δrow=2 — invalid.

Let’s try second grid:

```
h g i n
t l f s
a e n t
m u y r
```

Look for words:

- “gin”: g(0,1) → i(0,2) → n(0,3) = horizontal, “gin” ✔
- “fit”: f(1,2) → i(0,2) → t(1,0)? No. f→i→t not connected directly. But f(1,2) → l(1,1) → t(1,0) = “flt” no.
- “sin”: s(1,3) → i(0,2) → n(0,3): s→i is (1,3)→(0,2): Δrow=−1, Δcol=−1 → diagonal ✔; i→n is right → “sin” ✔
- “net”: n(0,3) → e(2,1) → t(2,2)? n to e is far. But n(2,2) → e(2,1) → t(1,0)? No.
Wait: n(2,2) → e(2,1) → t(1,0) not adjacent.
But look: a(2,0) → e(2,1) → n(2,2) = “aen” no. But “ant”: a(2,0) → n(2,2)? Not adjacent (skip col 1). a→e→n = “aen” no.
However, a(2,0) → t(1,0) → l(1,1) = “atl” no.

Better: “fun”: f(1,2) → u(3,1) → n(0,3)? No. f→u is (1,2)→(3,1): Δrow=2 — invalid.

Let’s step back. The worksheet says: “Use these grids to for student boggle.” And there are blank lines (6 total: 3 per grid) — likely expecting 3 words per grid.

Common Boggle words from these grids:

Grid 1:
1. play — p-l-a-y
2. near — n-e-a-r
3. warm? w(2,2) → a(0,2) no. What about “rate”? r(1,2) → a(0,2) → t(2,0)? No.
Try “live”: l(0,1) → i(2,3)? No.

Wait — another: “may”: m(0,3) → a(0,2) → y(1,3) = m-a-y ✔ “may” is a word! And path is valid: (0,3)→(0,2)→(1,3) — yes, a to y is diagonal down-right, allowed.

So grid 1:
- play
- near
- may

All valid.

Grid 2:
Letters:
Row0: h g i n
Row1: t l f s
Row2: a e n t
Row3: m u y r

Find 3 words:

1. gin — g-i-n (0,1)-(0,2)-(0,3) ✔
2. sin — s(1,3)-i(0,2)-n(0,3) ✔
3. run? r(3,3) → u(3,1)? No. r(3,3) → y(3,2) → n(2,2) = r-y-n = “ryn” no.
What about “ten”: t(1,0) → e(2,1) → n(2,2):
t(1,0) to e(2,1): Δrow=+1, Δcol=+1 → diagonal ✔
e(2,1) to n(2,2): right ✔
So “ten” ✔

Yes! “ten” is a word.

So grid 2: gin, sin, ten.

Alternatively, “fit”: f(1,2) → i(0,2) → t(1,0)? Not connected. But f→l→t = “flt” no.

“lit”: l(1,1) → i(0,2) → t(1,0)? l to i is diagonal, i to t is not adjacent. But l(1,1) → i(0,2) → n(0,3) = “lin” — “lin” is not standard, but “line” would need 4 letters.

Wait — what about “hay”? h(0,0) → a(2,0) → y(3,2)? h to a is (0,0)→(2,0): Δrow=2 — invalid.

Another: “rug”? r(3,3) → u(3,1) no.

Let’s verify “ten” again:
t at (1,0), e at (2,1), n at (2,2) — all consecutive and adjacent. Yes.

Also: “fan”: f(1,2) → a(2,0)? No. f→e(2,1) → a(2,0) = f-e-a = “fea” no.
But f(1,2) → e(2,1) → n(2,2) = “fen” ✔ “fen” is a real word (a type of wetland).

So grid 2: gin, sin, fen — all valid and common.

Which set is more likely expected for students? “fen”, “sin”, “gin” are all 3-letter common words.

Similarly, grid 1: “may”, “play”, “near” — all common.

The worksheet has 3 blank lines per grid, so 3 words each.

Thus, final answers (one per line, 3 per grid):

Grid 1: play, near, may
Grid 2: gin, sin, ten (or fen — but “ten” is simpler for students)

Let’s double-check “ten” path once more:
- t at row1,col0
- e at row2,col1 → from (1,0) to (2,1): down-right diagonal → allowed
- n at row2,col2 → from (2,1) to (2,2): right → allowed
✔

“gin”: (0,1)-(0,2)-(0,3) → all horizontal → ✔
“sin”: s(1,3) → i(0,2) diagonal up-left, then i→n right: ✔

So those are solid.

Final Answer:
play, near, may
gin, sin, ten