Adorable puppy coloring page with flowers and sky.

Problem: Solve the two-digit subtraction problems with regrouping.

The worksheet contains nine subtraction problems. We will solve each one step by step, showing the process of regrouping where necessary.

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#### 1) \( 33 - 15 \)

- Step 1: Subtract the ones place.
- \( 3 - 5 \) is not possible without regrouping.
- Borrow 1 from the tens place (3 becomes 2, and 3 in the ones place becomes 13).
- Now, \( 13 - 5 = 8 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 2 - 1 = 1 \).

- Final Answer: \( 33 - 15 = 18 \)

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#### 2) \( 34 - 16 \)

- Step 1: Subtract the ones place.
- \( 4 - 6 \) is not possible without regrouping.
- Borrow 1 from the tens place (3 becomes 2, and 4 in the ones place becomes 14).
- Now, \( 14 - 6 = 8 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 2 - 1 = 1 \).

- Final Answer: \( 34 - 16 = 18 \)

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#### 3) \( 22 - 18 \)

- Step 1: Subtract the ones place.
- \( 2 - 8 \) is not possible without regrouping.
- Borrow 1 from the tens place (2 becomes 1, and 2 in the ones place becomes 12).
- Now, \( 12 - 8 = 4 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 1 - 1 = 0 \).

- Final Answer: \( 22 - 18 = 4 \)

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#### 4) \( 21 - 14 \)

- Step 1: Subtract the ones place.
- \( 1 - 4 \) is not possible without regrouping.
- Borrow 1 from the tens place (2 becomes 1, and 1 in the ones place becomes 11).
- Now, \( 11 - 4 = 7 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 1 - 1 = 0 \).

- Final Answer: \( 21 - 14 = 7 \)

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#### 5) \( 36 - 19 \)

- Step 1: Subtract the ones place.
- \( 6 - 9 \) is not possible without regrouping.
- Borrow 1 from the tens place (3 becomes 2, and 6 in the ones place becomes 16).
- Now, \( 16 - 9 = 7 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 2 - 1 = 1 \).

- Final Answer: \( 36 - 19 = 17 \)

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#### 6) \( 23 - 15 \)

- Step 1: Subtract the ones place.
- \( 3 - 5 \) is not possible without regrouping.
- Borrow 1 from the tens place (2 becomes 1, and 3 in the ones place becomes 13).
- Now, \( 13 - 5 = 8 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 1 - 1 = 0 \).

- Final Answer: \( 23 - 15 = 8 \)

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#### 7) \( 40 - 28 \)

- Step 1: Subtract the ones place.
- \( 0 - 8 \) is not possible without regrouping.
- Borrow 1 from the tens place (4 becomes 3, and 0 in the ones place becomes 10).
- Now, \( 10 - 8 = 2 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 3 - 2 = 1 \).

- Final Answer: \( 40 - 28 = 12 \)

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#### 8) \( 43 - 17 \)

- Step 1: Subtract the ones place.
- \( 3 - 7 \) is not possible without regrouping.
- Borrow 1 from the tens place (4 becomes 3, and 3 in the ones place becomes 13).
- Now, \( 13 - 7 = 6 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 3 - 1 = 2 \).

- Final Answer: \( 43 - 17 = 26 \)

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#### 9) \( 56 - 29 \)

- Step 1: Subtract the ones place.
- \( 6 - 9 \) is not possible without regrouping.
- Borrow 1 from the tens place (5 becomes 4, and 6 in the ones place becomes 16).
- Now, \( 16 - 9 = 7 \).

- Step 2: Subtract the tens place.
- After borrowing, the tens place is \( 4 - 2 = 2 \).

- Final Answer: \( 56 - 29 = 27 \)

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Final Answers:

\[
\boxed{
\begin{array}{ccc}
1) & 18 & \\
2) & 18 & \\
3) & 4 & \\
4) & 7 & \\
5) & 17 & \\
6) & 8 & \\
7) & 12 & \\
8) & 26 & \\
9) & 27 & \\
\end{array}
}
\]