Probability worksheet for K-5 students involving a candy jar with various colored candies.

To solve the probability questions for the candy jar, we need to count the number of each type of candy and then calculate the probabilities based on those counts. Let's assume the following counts from the image (since the exact numbers aren't provided in the text):

- Orange candies: 5
- Yellow candies: 6
- Blue candies: 4
- Green candies: 3

The total number of candies is:
$$
5 + 6 + 4 + 3 = 18
$$

Now, let's solve each question step by step.

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1. What is the probability of picking an orange candy?

The probability of picking an orange candy is the number of orange candies divided by the total number of candies:
$$
P(\text{orange}) = \frac{\text{Number of orange candies}}{\text{Total number of candies}} = \frac{5}{18}
$$

Answer:
$$
\boxed{\frac{5}{18}}
$$

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2. What is the probability of picking a yellow candy?

The probability of picking a yellow candy is the number of yellow candies divided by the total number of candies:
$$
P(\text{yellow}) = \frac{\text{Number of yellow candies}}{\text{Total number of candies}} = \frac{6}{18} = \frac{1}{3}
$$

Answer:
$$
\boxed{\frac{1}{3}}
$$

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3. What is the probability of picking a blue candy?

The probability of picking a blue candy is the number of blue candies divided by the total number of candies:
$$
P(\text{blue}) = \frac{\text{Number of blue candies}}{\text{Total number of candies}} = \frac{4}{18} = \frac{2}{9}
$$

Answer:
$$
\boxed{\frac{2}{9}}
$$

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4. What is the probability of picking a green candy?

The probability of picking a green candy is the number of green candies divided by the total number of candies:
$$
P(\text{green}) = \frac{\text{Number of green candies}}{\text{Total number of candies}} = \frac{3}{18} = \frac{1}{6}
$$

Answer:
$$
\boxed{\frac{1}{6}}
$$

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5. Which candy is least likely to be picked at random?

To determine which candy is least likely to be picked, we compare the probabilities calculated above:
- Probability of orange: $\frac{5}{18}$
- Probability of yellow: $\frac{1}{3} = \frac{6}{18}$
- Probability of blue: $\frac{2}{9} = \frac{4}{18}$
- Probability of green: $\frac{1}{6} = \frac{3}{18}$

The smallest probability is for green candies ($\frac{3}{18}$).

Answer:
$$
\boxed{\text{green}}
$$

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6. What is the probability of picking either a yellow candy or a green candy?

The probability of picking either a yellow candy or a green candy is the sum of their individual probabilities:
$$
P(\text{yellow or green}) = P(\text{yellow}) + P(\text{green}) = \frac{6}{18} + \frac{3}{18} = \frac{9}{18} = \frac{1}{2}
$$

Answer:
$$
\boxed{\frac{1}{2}}
$$

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7. What is the probability of picking either an orange candy or a blue candy?

The probability of picking either an orange candy or a blue candy is the sum of their individual probabilities:
$$
P(\text{orange or blue}) = P(\text{orange}) + P(\text{blue}) = \frac{5}{18} + \frac{4}{18} = \frac{9}{18} = \frac{1}{2}
$$

Answer:
$$
\boxed{\frac{1}{2}}
$$

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8. Would it be more likely to pick an orange candy or a yellow candy?

To determine which is more likely, we compare the probabilities of picking an orange candy and a yellow candy:
- Probability of orange: $\frac{5}{18}$
- Probability of yellow: $\frac{6}{18} = \frac{1}{3}$

Since $\frac{6}{18} > \frac{5}{18}$, it is more likely to pick a yellow candy.

Answer:
$$
\boxed{\text{yellow}}
$$

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Final Answers:

1. $\boxed{\frac{5}{18}}$
2. $\boxed{\frac{1}{3}}$
3. $\boxed{\frac{2}{9}}$
4. $\boxed{\frac{1}{6}}$
5. $\boxed{\text{green}}$
6. $\boxed{\frac{1}{2}}$
7. $\boxed{\frac{1}{2}}$
8. $\boxed{\text{yellow}}$