Completed Punnett Square Practice Worksheet showing answers for genetics problems involving dominance, recessiveness, and inheritance patterns.
A completed Punnett Square Practice Worksheet with handwritten answers, covering genotype-phenotype relationships for traits like flower color, knuckle hairiness, and cat tail type, along with a Punnett square for dog fur color inheritance.
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Show Answer Key & Explanations
Step-by-step solution for: SOLUTION: SCB101 Punnett Square Practice Worksheet - Studypool
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Show Answer Key & Explanations
Step-by-step solution for: SOLUTION: SCB101 Punnett Square Practice Worksheet - Studypool
Let's go through the Punnett Square Practice Worksheet step by step and evaluate the answers, correct any mistakes, and explain the reasoning.
---
> Purple flowers are dominant to white flowers.
- PP → Purple ✔
- Pp → Purple ✔
- pp → White ✔
> Hairy knuckles are dominant to non-hairy knuckles in humans.
- HH → Hairy ✔
- Hh → Hairy ✔
- hh → Non-hairy ✔
> Bobtails in cats are recessive. Normal tails are dominant.
- TT → Normal ✔
- Tt → Normal ✔
- tt → Bobtail ✔
✔ All answers for Question 1 are correct.
---
Determine if each genotype is:
- Homozygous dominant (AA)
- Heterozygous (Aa)
- Homozygous recessive (aa)
| Genotype | Answer Given | Correct? | Explanation |
|---------|--------------|----------|------------|
| AA | Homozygous dominant | ✔ | Two identical dominant alleles |
| gg | Homozygous recessive | ✔ | Two identical recessive alleles |
| Pp | Heterozygous | ✔ | One dominant, one recessive allele |
| Ii | Heterozygous | ✔ | Same as above |
| tt | Homozygous recessive | ✔ | Two recessive alleles |
| TT | Homozygous dominant | ✔ | Two dominant alleles |
✔ All answers for Question 2 are correct.
---
> Gene for fur color in dogs:
- Dominant allele (F) = Grey fur
- Recessive allele (f) = Black fur
#### Scenario:
- Female dog is heterozygous → Ff
- Male dog is homozygous recessive → ff
We need to use a Punnett square to determine:
- Possible genotypes of puppies
- Percentages of genotypes and phenotypes
---
Place male alleles (ff) on top, female alleles (Ff) on the side:
```
f f
---------------
F | Ff | Ff
---------------
f | ff | ff
---------------
```
So the possible offspring genotypes are:
- Ff → 2 out of 4 → 50%
- ff → 2 out of 4 → 50%
There is no FF because the male contributes only 'f' alleles.
---
- FF: 0% ✔
- Ff: 50% ✔
- ff: 50% ✔
✔ These are correct.
---
- Grey fur: Requires at least one F → Ff → 50% ✔
- Black fur: Only ff → 50% ✔
✔ These are also correct.
---
The student’s diagram has a small error:
They wrote:
```
f f
------
F | Ff Ff
------
f | ff ff
```
But they labeled the squares incorrectly:
- The top row should be labeled with male gametes: f and f
- The left column with female gametes: F and f
- Then the squares should be:
- Top-left: Ff → Grey
- Top-right: Ff → Grey
- Bottom-left: ff → Black
- Bottom-right: ff → Black
However, the student labeled the bottom two boxes as "FF", which is incorrect.
✘ Mistake: They wrote FF instead of Ff and ff.
It looks like they may have mixed up the alleles.
Let’s fix it:
✔ Corrected Punnett Square:
```
f f
-----------------
F | Ff (grey) | Ff (grey)
-----------------
f | ff (black) | ff (black)
-----------------
```
So:
- Ff → grey fur
- ff → black fur
The phenotypic ratio is 50% grey, 50% black.
---
#### Question 3:
- % of possible Genotypes:
- FF: 0%
- Ff: 50%
- ff: 50%
- % of possible Phenotypes:
- Black fur: 50%
- Grey fur: 50%
✔ All percentages are correct.
✘ But the Punnett square labeling is incorrect — the student wrote FF in the boxes where it should be Ff or ff.
---
Correct Punnett Square:
| | f | f |
|-------|-------|-------|
| F | Ff → grey | Ff → grey |
| f | ff → black | ff → black |
This shows:
- 2/4 = 50% Ff → grey fur
- 2/4 = 50% ff → black fur
---
- All answers for questions 1 and 2 are correct.
- Question 3 answers (percentages) are correct.
- ✘ The Punnett square has an error in labeling — FF was written instead of Ff and ff.
- ✔ The final percentages are correct, but the diagram needs correction.
---
Replace the labels in the Punnett square:
- Top-left: Ff → grey
- Top-right: Ff → grey
- Bottom-left: ff → black
- Bottom-right: ff → black
And label the rows/columns properly:
- Rows: F and f (from female)
- Columns: f and f (from male)
---
✔ Final Answer:
- Genotypes: 0% FF, 50% Ff, 50% ff
- Phenotypes: 50% grey fur, 50% black fur
- Punnett Square corrected as above.
Let me know if you'd like a visual version!
---
Question 1: Determine Phenotypes
> Purple flowers are dominant to white flowers.
- PP → Purple ✔
- Pp → Purple ✔
- pp → White ✔
> Hairy knuckles are dominant to non-hairy knuckles in humans.
- HH → Hairy ✔
- Hh → Hairy ✔
- hh → Non-hairy ✔
> Bobtails in cats are recessive. Normal tails are dominant.
- TT → Normal ✔
- Tt → Normal ✔
- tt → Bobtail ✔
✔ All answers for Question 1 are correct.
---
Question 2: Genotype Classification
Determine if each genotype is:
- Homozygous dominant (AA)
- Heterozygous (Aa)
- Homozygous recessive (aa)
| Genotype | Answer Given | Correct? | Explanation |
|---------|--------------|----------|------------|
| AA | Homozygous dominant | ✔ | Two identical dominant alleles |
| gg | Homozygous recessive | ✔ | Two identical recessive alleles |
| Pp | Heterozygous | ✔ | One dominant, one recessive allele |
| Ii | Heterozygous | ✔ | Same as above |
| tt | Homozygous recessive | ✔ | Two recessive alleles |
| TT | Homozygous dominant | ✔ | Two dominant alleles |
✔ All answers for Question 2 are correct.
---
Questions 3–5: Dog Fur Color Genetics
> Gene for fur color in dogs:
- Dominant allele (F) = Grey fur
- Recessive allele (f) = Black fur
#### Scenario:
- Female dog is heterozygous → Ff
- Male dog is homozygous recessive → ff
We need to use a Punnett square to determine:
- Possible genotypes of puppies
- Percentages of genotypes and phenotypes
---
Step 1: Set up the Punnett Square
Place male alleles (ff) on top, female alleles (Ff) on the side:
```
f f
---------------
F | Ff | Ff
---------------
f | ff | ff
---------------
```
So the possible offspring genotypes are:
- Ff → 2 out of 4 → 50%
- ff → 2 out of 4 → 50%
There is no FF because the male contributes only 'f' alleles.
---
Genotype Percentages:
- FF: 0% ✔
- Ff: 50% ✔
- ff: 50% ✔
✔ These are correct.
---
Phenotype Percentages:
- Grey fur: Requires at least one F → Ff → 50% ✔
- Black fur: Only ff → 50% ✔
✔ These are also correct.
---
Punnett Square Diagram (Corrected)
The student’s diagram has a small error:
They wrote:
```
f f
------
F | Ff Ff
------
f | ff ff
```
But they labeled the squares incorrectly:
- The top row should be labeled with male gametes: f and f
- The left column with female gametes: F and f
- Then the squares should be:
- Top-left: Ff → Grey
- Top-right: Ff → Grey
- Bottom-left: ff → Black
- Bottom-right: ff → Black
However, the student labeled the bottom two boxes as "FF", which is incorrect.
✘ Mistake: They wrote FF instead of Ff and ff.
It looks like they may have mixed up the alleles.
Let’s fix it:
✔ Corrected Punnett Square:
```
f f
-----------------
F | Ff (grey) | Ff (grey)
-----------------
f | ff (black) | ff (black)
-----------------
```
So:
- Ff → grey fur
- ff → black fur
The phenotypic ratio is 50% grey, 50% black.
---
✔ Final Answers Summary:
#### Question 3:
- % of possible Genotypes:
- FF: 0%
- Ff: 50%
- ff: 50%
- % of possible Phenotypes:
- Black fur: 50%
- Grey fur: 50%
✔ All percentages are correct.
✘ But the Punnett square labeling is incorrect — the student wrote FF in the boxes where it should be Ff or ff.
---
✔ Final Correction:
Correct Punnett Square:
| | f | f |
|-------|-------|-------|
| F | Ff → grey | Ff → grey |
| f | ff → black | ff → black |
This shows:
- 2/4 = 50% Ff → grey fur
- 2/4 = 50% ff → black fur
---
🟩 Conclusion:
- All answers for questions 1 and 2 are correct.
- Question 3 answers (percentages) are correct.
- ✘ The Punnett square has an error in labeling — FF was written instead of Ff and ff.
- ✔ The final percentages are correct, but the diagram needs correction.
---
🔧 Recommended Fix:
Replace the labels in the Punnett square:
- Top-left: Ff → grey
- Top-right: Ff → grey
- Bottom-left: ff → black
- Bottom-right: ff → black
And label the rows/columns properly:
- Rows: F and f (from female)
- Columns: f and f (from male)
---
✔ Final Answer:
- Genotypes: 0% FF, 50% Ff, 50% ff
- Phenotypes: 50% grey fur, 50% black fur
- Punnett Square corrected as above.
Let me know if you'd like a visual version!
Parent Tip: Review the logic above to help your child master the concept of punnett square worksheet 2 answer key.