Printable Punnett Squares worksheets for genetics practice, featuring various inheritance problems and blank Punnett square grids.
Two printable worksheets titled "Punnett Squares" with genetics problems and Punnett square grids, set against a blue background with "PRINT VERSION" text and a "LANEY LEE" logo.
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Show Answer Key & Explanations
Step-by-step solution for: Punnett Square Practice or Quiz PDF with Answer Key - Laney Lee
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Show Answer Key & Explanations
Step-by-step solution for: Punnett Square Practice or Quiz PDF with Answer Key - Laney Lee
Explanation:
Let’s go through each question step by step.
---
1. A pea plant has genotype Bb. Circle all words that describe this genotype:
- Heterozygous → ✔ Yes (two different alleles: B and b)
- Homozygous → ✘ No (that would be BB or bb)
- True breeding → ✘ No (true breeding means homozygous — always produces same offspring)
- Purebred → ✘ No (same as true breeding — only for homozygous)
- Hybrid → ✔ Yes (hybrid = heterozygous)
→ So: A. Heterozygous, E. Hybrid
---
2. A rabbit has genotype AA. Circle all words that describe this genotype:
- Heterozygous → ✘ No
- Homozygous → ✔ Yes (two same alleles: A and A)
- True breeding → ✔ Yes (homozygous dominant will always pass on A)
- Purebred → ✔ Yes (same as true breeding)
- Hybrid → ✘ No
→ So: B. Homozygous, C. True breeding, D. Purebred
---
3. In pea plants, purple flowers are dominant to white flowers. List all possible genotypes for a purple flower:
Dominant trait = purple → needs at least one dominant allele (let’s say P = purple, p = white).
So genotypes: PP or Pp
(Only pp is white.)
→ Answer: PP, Pp
---
4. In pea plants, yellow peas are dominant to green peas. List all possible genotypes for a green pea:
Green is recessive → only possible if both alleles are recessive (yy).
So: yy
→ Answer: yy
---
5. Tallness is dominant to short in pea plants. Phenotype for each genotype:
- TT → homozygous dominant → tall
- Tt → heterozygous → still has dominant allele → tall
- tt → homozygous recessive → short
→ Answers:
TT → tall
Tt → tall
tt → short
---
6. Grey fur dog (Gg) × black fur dog (gg)
We fill the Punnett Square:
Parent 1 (Gg): gametes = G or g
Parent 2 (gg): gametes = g or g
Punnett square:
```
g g
G Gg Gg
g gg gg
```
Genotypes:
- Gg → 2 out of 4 → 50%
- gg → 2 out of 4 → 50%
Phenotypes:
- Gg = grey fur
- gg = black fur
So:
- GG — not possible
- Gg — grey fur ✔
- gg — black fur ✔
In the table, they list:
- GG – ___
- Gg – grey fur
- gg – black fur
So we just confirm:
GG: (none) — leave blank or write “not possible”
Gg: grey fur
gg: black fur
But since the question says “list all possible genotypes and phenotypes”, only Gg and gg occur.
---
7. Two hybrid grey fur dogs crossed (Gg × Gg)
Gametes from each: G or g
Punnett square:
```
G g
G GG Gg
g Gg gg
```
Genotypes:
- GG → 1/4
- Gg → 2/4 = 1/2
- gg → 1/4
Phenotypes:
- GG and Gg → grey fur (dominant)
- gg → black fur
So:
- GG – grey fur
- Gg – grey fur
- gg – black fur
Fill in table accordingly.
---
8. Two heterozygous curly-haired guinea pigs crossed. Straight hair is recessive.
Let C = curly (dominant), c = straight (recessive)
Parents: Cc × Cc
Punnett square:
```
C c
C CC Cc
c Cc cc
```
Genotypes: CC, Cc, Cc, cc
→ CC, Cc, cc
Phenotypes:
- CC & Cc → curly hair
- cc → straight hair
So:
- Genotypes: CC, Cc, cc
- Phenotypes: curly, curly, straight
Or listed as:
GENOTYPES: CC, Cc, cc
PHENOTYPES: curly, curly, straight
(but usually grouped: 3 curly : 1 straight)
---
9. Purebred red flower × purebred white flower. Red is dominant.
Let R = red (dominant), r = white (recessive)
Purebred red = RR
Purebred white = rr
Cross: RR × rr
All offspring: Rr
Genotype: all Rr
Phenotype: all red (since R is dominant)
→ GENOTYPES: Rr
→ PHENOTYPES: red
---
10. Heterozygous tall pea plant (Tt) × homozygous short (tt)
Gametes:
Tt → T or t
tt → t or t
Punnett:
```
t t
T Tt Tt
t tt tt
```
Genotypes: Tt, Tt, tt, tt → Tt and tt
Phenotypes: Tt = tall, tt = short
So:
GENOTYPES: Tt, tt
PHENOTYPES: tall, short
---
11. Parents: mother = homozygous brown hair (BB), father = heterozygous brown (Bb). Baby has blonde hair. Is hospital mistake?
Blonde hair must be recessive → genotype bb.
Mother: BB → can only give B
Father: Bb → can give B or b
Possible offspring:
- B (mom) + B (dad) = BB → brown
- B (mom) + b (dad) = Bb → brown
No way to get bb (blonde), because mom has no b allele to give.
So baby with blonde hair (bb) cannot be their biological child.
→ Hospital likely made a mistake.
Final Answer:
1. A, E
2. B, C, D
3. PP, Pp
4. yy
5. TT → tall; Tt → tall; tt → short
6. Gg → grey fur; gg → black fur (GG not possible)
7. GG → grey fur; Gg → grey fur; gg → black fur
8. Genotypes: CC, Cc, cc; Phenotypes: curly, curly, straight
9. Genotypes: Rr; Phenotypes: red
10. Genotypes: Tt, tt; Phenotypes: tall, short
11. Yes, the hospital made a mistake — two brown-haired parents (BB × Bb) cannot have a blonde-haired (bb) child.
But since the instruction says:
→ *Final Answer:* [Provide only the final correct answer — this should come AFTER all explanations and reasoning.]
However, there are multiple questions. The user likely expects answers to all parts. Since the format says “only the final correct answer”, and there are many subparts, I’ll consolidate each part clearly as the final output.
But per instructions: ONLY THEN provide the final answer — and it should be just the answer, no explanation.
Given the complexity, and that the user uploaded a worksheet with many items, the expected output is the completed worksheet answers.
I will format the Final Answer as a clean list matching each question in order.
Final Answer:
1. A, E
2. B, C, D
3. PP, Pp
4. yy
5. TT → tall; Tt → tall; tt → short
6. Genotypes: Gg, gg; Phenotypes: grey fur, black fur
7. Genotypes: GG, Gg, gg; Phenotypes: grey fur, grey fur, black fur
8. Genotypes: CC, Cc, cc; Phenotypes: curly, curly, straight
9. Genotypes: Rr; Phenotypes: red
10. Genotypes: Tt, tt; Phenotypes: tall, short
11. Yes, the hospital made a mistake — the baby cannot be biologically theirs because blonde hair (recessive, bb) requires a b allele from both parents, but the mother (BB) has no b allele to contribute.
Let’s go through each question step by step.
---
1. A pea plant has genotype Bb. Circle all words that describe this genotype:
- Heterozygous → ✔ Yes (two different alleles: B and b)
- Homozygous → ✘ No (that would be BB or bb)
- True breeding → ✘ No (true breeding means homozygous — always produces same offspring)
- Purebred → ✘ No (same as true breeding — only for homozygous)
- Hybrid → ✔ Yes (hybrid = heterozygous)
→ So: A. Heterozygous, E. Hybrid
---
2. A rabbit has genotype AA. Circle all words that describe this genotype:
- Heterozygous → ✘ No
- Homozygous → ✔ Yes (two same alleles: A and A)
- True breeding → ✔ Yes (homozygous dominant will always pass on A)
- Purebred → ✔ Yes (same as true breeding)
- Hybrid → ✘ No
→ So: B. Homozygous, C. True breeding, D. Purebred
---
3. In pea plants, purple flowers are dominant to white flowers. List all possible genotypes for a purple flower:
Dominant trait = purple → needs at least one dominant allele (let’s say P = purple, p = white).
So genotypes: PP or Pp
(Only pp is white.)
→ Answer: PP, Pp
---
4. In pea plants, yellow peas are dominant to green peas. List all possible genotypes for a green pea:
Green is recessive → only possible if both alleles are recessive (yy).
So: yy
→ Answer: yy
---
5. Tallness is dominant to short in pea plants. Phenotype for each genotype:
- TT → homozygous dominant → tall
- Tt → heterozygous → still has dominant allele → tall
- tt → homozygous recessive → short
→ Answers:
TT → tall
Tt → tall
tt → short
---
6. Grey fur dog (Gg) × black fur dog (gg)
We fill the Punnett Square:
Parent 1 (Gg): gametes = G or g
Parent 2 (gg): gametes = g or g
Punnett square:
```
g g
G Gg Gg
g gg gg
```
Genotypes:
- Gg → 2 out of 4 → 50%
- gg → 2 out of 4 → 50%
Phenotypes:
- Gg = grey fur
- gg = black fur
So:
- GG — not possible
- Gg — grey fur ✔
- gg — black fur ✔
In the table, they list:
- GG – ___
- Gg – grey fur
- gg – black fur
So we just confirm:
GG: (none) — leave blank or write “not possible”
Gg: grey fur
gg: black fur
But since the question says “list all possible genotypes and phenotypes”, only Gg and gg occur.
---
7. Two hybrid grey fur dogs crossed (Gg × Gg)
Gametes from each: G or g
Punnett square:
```
G g
G GG Gg
g Gg gg
```
Genotypes:
- GG → 1/4
- Gg → 2/4 = 1/2
- gg → 1/4
Phenotypes:
- GG and Gg → grey fur (dominant)
- gg → black fur
So:
- GG – grey fur
- Gg – grey fur
- gg – black fur
Fill in table accordingly.
---
8. Two heterozygous curly-haired guinea pigs crossed. Straight hair is recessive.
Let C = curly (dominant), c = straight (recessive)
Parents: Cc × Cc
Punnett square:
```
C c
C CC Cc
c Cc cc
```
Genotypes: CC, Cc, Cc, cc
→ CC, Cc, cc
Phenotypes:
- CC & Cc → curly hair
- cc → straight hair
So:
- Genotypes: CC, Cc, cc
- Phenotypes: curly, curly, straight
Or listed as:
GENOTYPES: CC, Cc, cc
PHENOTYPES: curly, curly, straight
(but usually grouped: 3 curly : 1 straight)
---
9. Purebred red flower × purebred white flower. Red is dominant.
Let R = red (dominant), r = white (recessive)
Purebred red = RR
Purebred white = rr
Cross: RR × rr
All offspring: Rr
Genotype: all Rr
Phenotype: all red (since R is dominant)
→ GENOTYPES: Rr
→ PHENOTYPES: red
---
10. Heterozygous tall pea plant (Tt) × homozygous short (tt)
Gametes:
Tt → T or t
tt → t or t
Punnett:
```
t t
T Tt Tt
t tt tt
```
Genotypes: Tt, Tt, tt, tt → Tt and tt
Phenotypes: Tt = tall, tt = short
So:
GENOTYPES: Tt, tt
PHENOTYPES: tall, short
---
11. Parents: mother = homozygous brown hair (BB), father = heterozygous brown (Bb). Baby has blonde hair. Is hospital mistake?
Blonde hair must be recessive → genotype bb.
Mother: BB → can only give B
Father: Bb → can give B or b
Possible offspring:
- B (mom) + B (dad) = BB → brown
- B (mom) + b (dad) = Bb → brown
No way to get bb (blonde), because mom has no b allele to give.
So baby with blonde hair (bb) cannot be their biological child.
→ Hospital likely made a mistake.
Final Answer:
1. A, E
2. B, C, D
3. PP, Pp
4. yy
5. TT → tall; Tt → tall; tt → short
6. Gg → grey fur; gg → black fur (GG not possible)
7. GG → grey fur; Gg → grey fur; gg → black fur
8. Genotypes: CC, Cc, cc; Phenotypes: curly, curly, straight
9. Genotypes: Rr; Phenotypes: red
10. Genotypes: Tt, tt; Phenotypes: tall, short
11. Yes, the hospital made a mistake — two brown-haired parents (BB × Bb) cannot have a blonde-haired (bb) child.
But since the instruction says:
→ *Final Answer:* [Provide only the final correct answer — this should come AFTER all explanations and reasoning.]
However, there are multiple questions. The user likely expects answers to all parts. Since the format says “only the final correct answer”, and there are many subparts, I’ll consolidate each part clearly as the final output.
But per instructions: ONLY THEN provide the final answer — and it should be just the answer, no explanation.
Given the complexity, and that the user uploaded a worksheet with many items, the expected output is the completed worksheet answers.
I will format the Final Answer as a clean list matching each question in order.
Final Answer:
1. A, E
2. B, C, D
3. PP, Pp
4. yy
5. TT → tall; Tt → tall; tt → short
6. Genotypes: Gg, gg; Phenotypes: grey fur, black fur
7. Genotypes: GG, Gg, gg; Phenotypes: grey fur, grey fur, black fur
8. Genotypes: CC, Cc, cc; Phenotypes: curly, curly, straight
9. Genotypes: Rr; Phenotypes: red
10. Genotypes: Tt, tt; Phenotypes: tall, short
11. Yes, the hospital made a mistake — the baby cannot be biologically theirs because blonde hair (recessive, bb) requires a b allele from both parents, but the mother (BB) has no b allele to contribute.
Parent Tip: Review the logic above to help your child master the concept of punnett square worksheet 2 answer key.