Let’s solve each triangle one by one using Pythagoras’ Theorem.
Pythagoras’ Theorem says:
hypotenuse² = side₁² + side₂²
So, to find the hypotenuse, we do:
hypotenuse = √(side₁² + side₂²)
We’ll calculate each and round to 2 decimal places if needed.
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Triangle 1: sides 3cm and 4cm
→ hypotenuse = √(3² + 4²) = √(9 + 16) = √25 =
5.00 cm
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Triangle 2: sides 6mm and 5mm
→ hypotenuse = √(6² + 5²) = √(36 + 25) = √61 ≈
7.81 mm
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Triangle 3: sides 3cm and 6cm
→ hypotenuse = √(3² + 6²) = √(9 + 36) = √45 ≈
6.71 cm
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Triangle 4: sides 5cm and 5cm
→ hypotenuse = √(5² + 5²) = √(25 + 25) = √50 ≈
7.07 cm
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Triangle 5: sides 7m and 4m
→ hypotenuse = √(7² + 4²) = √(49 + 16) = √65 ≈
8.06 m
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Triangle 6: sides 9cm and 5cm
→ hypotenuse = √(9² + 5²) = √(81 + 25) = √106 ≈
10.30 cm
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Triangle 7: sides 7cm and 8cm
→ hypotenuse = √(7² + 8²) = √(49 + 64) = √113 ≈
10.63 cm
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Triangle 8: sides 11m and 8m
→ hypotenuse = √(11² + 8²) = √(121 + 64) = √185 ≈
13.60 m
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Triangle 9: sides 12in and 5in
→ hypotenuse = √(12² + 5²) = √(144 + 25) = √169 =
13.00 in
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Final Answer:
5.00 cm, 7.81 mm, 6.71 cm, 7.07 cm, 8.06 m, 10.30 cm, 10.63 cm, 13.60 m, 13.00 in
Parent Tip: Review the logic above to help your child master the concept of pythagorean theorem coloring worksheet.
