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Scientific Notation Word Problems in class video 2 - Free Printable

Scientific Notation Word Problems in class video 2

Educational worksheet: Scientific Notation Word Problems in class video 2. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Scientific Notation Word Problems in class video 2
Let's solve the problem step by step.

---

Given:


- Speed of light = $ 3 \times 10^8 $ meters per second
- Distance from the Sun to Mars = $ 230,000,000,000 $ meters

We want to find how many seconds it takes for sunlight to reach Mars.

---

Step 1: Use the formula for time



$$
\text{Time} = \frac{\text{Distance}}{\text{Speed}}
$$

Plug in the values:

$$
\text{Time} = \frac{230,000,000,000}{3 \times 10^8}
$$

---

Step 2: Write the distance in scientific notation



$ 230,000,000,000 = 2.3 \times 10^{11} $

So,

$$
\text{Time} = \frac{2.3 \times 10^{11}}{3 \times 10^8}
$$

---

Step 3: Divide the numbers and subtract exponents



$$
\frac{2.3}{3} = 0.7666... \approx 0.767
$$

$$
10^{11} \div 10^8 = 10^{11-8} = 10^3
$$

So,

$$
\text{Time} \approx 0.767 \times 10^3
$$

But we need scientific notation, which requires a number between 1 and 10.

$$
0.767 \times 10^3 = 7.67 \times 10^2
$$

---

Final Answer:



$$
\boxed{7.67 \times 10^2} \text{ seconds}
$$

That is, about 767 seconds for sunlight to reach Mars.

---

Bonus: Check with approximate calculation



- $ 3 \times 10^8 $ m/s × 767 s = $ 3 \times 10^8 \times 7.67 \times 10^2 = 2.3 \times 10^{11} $ m → matches the distance!

Correct.

---

Answer in boxed form:



$$
\boxed{7.67 \times 10^2} \text{ seconds}
$$
Parent Tip: Review the logic above to help your child master the concept of scientific notation word problem worksheet.
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